Core loss and copper loss are two types of losses that occur in electrical systems. Core loss refers to the energy dissipated in the core material of transformers and inductors, while copper loss refers to the energy dissipated in the copper windings due to the resistance of the wire. Here's how you can calculate core loss and copper loss: Core Loss Calculation: Core loss is generally expressed as a function of the peak magnetic flux density (Bmax) and the frequency (f). The specific equation used to calculate core loss depends on the type of core material and its characteristics. Two common equations used for core loss calculation are the Steinmetz equation and the Epstein frame method. I'll demonstrate the Steinmetz equation here: Core Loss (Pc) = K * f^α * Bmax^β In this equation, K, α, and β are constants that depend on the core material. The values of these constants can be obtained from the core material datasheet or empirical measurements. Copper Loss Calculation: Copper loss is calculated based on the resistance (R) of the winding and the current (I) flowing through it. The formula for copper loss is: Copper Loss (Pcu) = I^2 * R The resistance (R) is determined by the resistivity of the copper wire, the length of the wire, and its cross-sectional area. The current (I) can be calculated from the load connected to the transformer or inductor. Let's consider an example to demonstrate the calculations: Example: Suppose we have a transformer with the following parameters: Core Loss Constants: K = 0.02, α = 1.6, β = 2.4 Core Material: Silicon Steel Magnetic Flux Density: Bmax = 1.2 Tesla Frequency: f = 50 Hz Copper Wire Resistance: R = 0.1 Ohm Current: I = 10 Ampere Core Loss Calculation: Pc = K * f^α * Bmax^β = 0.02 * (50^1.6) * (1.2^2.4) ≈ 0.02 * 564.47 * 2.297 ≈ 25.97 Watts Copper Loss Calculation: Pcu = I^2 * R = 10^2 * 0.1 = 10 Watts So, in this example, the core loss is approximately 25.97 Watts, and the copper loss is 10 Watts. Please note that these calculations are simplified examples, and in practice, additional factors such as temperature, harmonics, and efficiency should be considered for more accurate results.
Sir agli vedio is topic pe bnayega Ki hm transmission line line mai sbss phle kise off krte hai Isolator ,CB , relay , aur vise versa kiske liye ( kon si condition mai krte hain) Mai uske baare mai bhool gya hoon
Sir sb ko part 1 2 3 karke upload kare video Jaise poles lagane m pahle survey fir installation Feeder separation m bhi aise Aur sub station ka bhi Khaas kar line ka
Safety factor remove krish diye or Sir Aaj kal cover wire LG gye hai... Or sir home electric miter ko smjhne me problem hoti hi iske uper El videos bnaiye n...???
ون تھرٹی ٹو کیوی لائن کے اوزار کے بارے میں بتا دوں کہ اس میں کون کون سے لگے مثال کے طور پر سم شین ہوگی اور چائنا east ہوگیا ہوگیا ہے سٹیل روپ ہوگیا ہے جناب وغیرہ وغیرہ اس کے بارے میں آپ اگر آپ جس تفصیل سے شیئر کریں
The number of aluminum and GI (Galvanized Iron) wires required in an H.T. (High Tension) line conductor or an L.T. (Low Tension) line cable depends on several factors such as the voltage rating, current carrying capacity, and the type of conductor or cable used. To calculate the number of wires, you'll need the following information: Current carrying capacity: Determine the maximum current that the conductor or cable should carry. This value is usually specified by the system designer or can be calculated based on the load requirements. Cross-sectional area: Determine the cross-sectional area of the individual aluminum and GI wires. This information is typically available from conductor or cable manufacturer datasheets. Allowable current density: Determine the allowable current density for the conductor or cable material. This value is usually provided by industry standards or specifications. Once you have this information, you can use the following steps to calculate the number of wires: Calculate the total cross-sectional area required: Multiply the desired current carrying capacity by the reciprocal of the allowable current density. This will give you the total cross-sectional area required for the conductor or cable. Total Cross-sectional Area = (Desired Current Carrying Capacity) / (Allowable Current Density) Determine the individual cross-sectional area for each wire: Divide the total cross-sectional area by the number of wires you want to use. This will give you the cross-sectional area required for each aluminum and GI wire. Individual Wire Cross-sectional Area = Total Cross-sectional Area / (Number of Aluminum Wires + Number of GI Wires) Calculate the number of aluminum wires: Divide the total cross-sectional area by the cross-sectional area of each aluminum wire. Number of Aluminum Wires = Total Cross-sectional Area / (Individual Wire Cross-sectional Area for Aluminum Wire) Calculate the number of GI wires: Divide the total cross-sectional area by the cross-sectional area of each GI wire. Number of GI Wires = Total Cross-sectional Area / (Individual Wire Cross-sectional Area for GI Wire) Please note that the actual number of wires used may also depend on other factors such as the mechanical strength and voltage drop requirements, which may require additional considerations. It is always recommended to consult with a qualified electrical engineer or a professional who specializes in power distribution systems for an accurate and safe design.
the insulator is for electrical stresses as well as mechanical stress. If one of them is failed, then the conductor will be short with the cross arm of the tower. It means the conductor will be earthed. As a result, earth fault happens.
If an insulator has weak portion due to manufacturing defect ,it may break from that weak portion when mechanical stress is applied on it by its conductor.
The calculation of the factor of safety (FoS) for an electrical insulator involves assessing the mechanical strength and electrical withstand capabilities of the insulator. Here's a general approach to calculating the FoS for an electrical insulator: Determine the Maximum Working Load (MWL): Identify the maximum load or stress that the insulator is expected to experience during normal operation. This load can include mechanical loads, such as weight or tension, and electrical loads, such as voltage or current levels. Determine the Maximum Allowable Load (MAL): Refer to the manufacturer's specifications or applicable standards to determine the maximum load that the insulator is designed to withstand without failure. This value is typically provided by the manufacturer and represents the insulator's rated mechanical and electrical strength. Calculate the Factor of Safety (FoS): FoS = MAL / MWL The FoS is the ratio of the maximum allowable load to the maximum working load. A higher FoS indicates a larger safety margin. It's important to note that the specific calculations and factors considered may vary depending on the type of insulator, application, and relevant standards. In practice, it's recommended to consult the manufacturer's documentation, and industry standards (such as IEC or ANSI), or work with qualified engineers with expertise in insulator design and selection for accurate and reliable calculations. Additionally, the factor of safety should consider various factors, including mechanical, electrical, and environmental conditions, to ensure the insulator's reliable performance under normal and extreme operating conditions. But the actual calculation is N=LINE VOLTAGE IN KV /(1.732*11 KV). This equation is for the suspension tower. But you can take 1 or 2 extra for the tension tower
you can add . But the extra factor of safety means extra protection. It will be very healthy for a power system. But more adding of insulator means, extra cost..Now you can better understand. But for the tension tower you may add 2 more extra for safety. N=line voltage in kv /(1.732*11 kv).This is for the suspension tower (you may add one more extra). But for the tension tower, please add 2 more.
धन्यवाद
बहोत ही आसान भाषा में समजाया है।
ऐसे ही विषय मे बहोत सारे विडिओ बनवाने के लिए शुभ कामनाए।
Bade ache se mathematically samjhaaya.👌
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Thanks alot 🙏
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VERY GOOD EXPLANATION SIR....KEEP IT UP
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Thanks bhi itne ache se samjhane ke liye
Thanks
Share this video with your electrical friends for more videos
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Thanks sir transformer ke jo losses hote hai wo hme example ke through samjao aapka samjane ka way bahot badiya hai
Core loss and copper loss are two types of losses that occur in electrical systems. Core loss refers to the energy dissipated in the core material of transformers and inductors, while copper loss refers to the energy dissipated in the copper windings due to the resistance of the wire.
Here's how you can calculate core loss and copper loss:
Core Loss Calculation:
Core loss is generally expressed as a function of the peak magnetic flux density (Bmax) and the frequency (f). The specific equation used to calculate core loss depends on the type of core material and its characteristics. Two common equations used for core loss calculation are the Steinmetz equation and the Epstein frame method. I'll demonstrate the Steinmetz equation here:
Core Loss (Pc) = K * f^α * Bmax^β
In this equation, K, α, and β are constants that depend on the core material. The values of these constants can be obtained from the core material datasheet or empirical measurements.
Copper Loss Calculation:
Copper loss is calculated based on the resistance (R) of the winding and the current (I) flowing through it. The formula for copper loss is:
Copper Loss (Pcu) = I^2 * R
The resistance (R) is determined by the resistivity of the copper wire, the length of the wire, and its cross-sectional area. The current (I) can be calculated from the load connected to the transformer or inductor.
Let's consider an example to demonstrate the calculations:
Example:
Suppose we have a transformer with the following parameters:
Core Loss Constants: K = 0.02, α = 1.6, β = 2.4
Core Material: Silicon Steel
Magnetic Flux Density: Bmax = 1.2 Tesla
Frequency: f = 50 Hz
Copper Wire Resistance: R = 0.1 Ohm
Current: I = 10 Ampere
Core Loss Calculation:
Pc = K * f^α * Bmax^β
= 0.02 * (50^1.6) * (1.2^2.4)
≈ 0.02 * 564.47 * 2.297
≈ 25.97 Watts
Copper Loss Calculation:
Pcu = I^2 * R
= 10^2 * 0.1
= 10 Watts
So, in this example, the core loss is approximately 25.97 Watts, and the copper loss is 10 Watts.
Please note that these calculations are simplified examples, and in practice, additional factors such as temperature, harmonics, and efficiency should be considered for more accurate results.
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THANKS SIR, YOU ARE LIKE MORPHEUS FOR ELECTRICAL ENGINEERS FOR FIELD JOB
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Kya power house main nhi ptta lgta sir neutral leakage time ya fir alarm set hota hai
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In 11kv 1or 2 disc are use, extra one is use for mechanical support, and therefore, for 33kv 3 or 4 discs are used.
Bhuat acche sir
Share with your electrical friends
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Safety factor kaise calculate kiya yeh btaiye thoda safety factor lete hai yeh to books m bhi likha hai
actually factor of safety is ratio of puncher voltage to flashover voltage (PV/FOV)
Sir agli vedio is topic pe bnayega
Ki hm transmission line line mai sbss phle kise off krte hai
Isolator ,CB , relay , aur vise versa kiske liye ( kon si condition mai krte hain)
Mai uske baare mai bhool gya hoon
Phir se yaad kar lo
Fir se yad kar lo
@@chandancreation4656
Vo mujhe nahi milega kyunki jibone btaya tha orally btaya tha
Sir sb ko part 1 2 3 karke upload kare video
Jaise poles lagane m pahle survey fir installation
Feeder separation m bhi aise
Aur sub station ka bhi
Khaas kar line ka
sir safety factor kitna v le sakte hai ,to fir no. of disc se kaise find kar sakte
Sir, 220 kv t/x line 14+14 disc insulator ak sath parallel me kyun hoti he? 🤔
Bcz Road cross or River cross Mai disc insulator parallel Mai rahet hai
Sld pr ek vdo bhi bna dijiye sir... Smdb pr bhi
SIR -- PSC POLE, STP POLE, RAIL POLE, STEEL TOWER IN SAB KA POWER FACTOR & CALCULATION KAISE NILKALTE HAI ?? PLZZZ THODA BATA DIJIYE ??
Safety factor remove krish diye or Sir Aaj kal cover wire LG gye hai...
Or sir home electric miter ko smjhne me problem hoti hi iske uper El videos bnaiye n...???
स्पष्ट रहें। मैं आपको उत्तर दूंगा।
मुझे स्पष्ट रूप से बताओ। मैं आपको जवाब दूंगा। मैं एक सरकारी सबस्टेशन में इलेक्ट्रिकल इंजीनियर हूं। तो मैं आपको ये बहुत अच्छी तरह से बता सकता हूँ
Some corrections
This called shackles insulators
Tell me please about safety factor value calculation,
Sir agla part bhi banaiye
Besti knowledge
ون تھرٹی ٹو کیوی لائن کے اوزار کے بارے میں بتا دوں کہ اس میں کون کون سے لگے مثال کے طور پر سم شین ہوگی اور چائنا east ہوگیا ہوگیا ہے سٹیل روپ ہوگیا ہے جناب وغیرہ وغیرہ اس کے بارے میں آپ اگر آپ جس تفصیل سے شیئر کریں
Line voltage 22 KV asayala pahije sir🤔🤔33KV kase sanga please.....
Sir CT meter reading ka video bnaye
Sir 220kv me kitne lagenge???
Pin insulater ke bare main bataiya sir
ruclips.net/video/QQXivBmK5UA/видео.html
Watch pin insulator
sir phase aur neutral kase pata chalega 11kv au savime
Sir how to calculate no.of aluminium wire and no.of GI Wire in H.T line conductor And L.T line cable or wire
The number of aluminum and GI (Galvanized Iron) wires required in an H.T. (High Tension) line conductor or an L.T. (Low Tension) line cable depends on several factors such as the voltage rating, current carrying capacity, and the type of conductor or cable used.
To calculate the number of wires, you'll need the following information:
Current carrying capacity: Determine the maximum current that the conductor or cable should carry. This value is usually specified by the system designer or can be calculated based on the load requirements.
Cross-sectional area: Determine the cross-sectional area of the individual aluminum and GI wires. This information is typically available from conductor or cable manufacturer datasheets.
Allowable current density: Determine the allowable current density for the conductor or cable material. This value is usually provided by industry standards or specifications.
Once you have this information, you can use the following steps to calculate the number of wires:
Calculate the total cross-sectional area required: Multiply the desired current carrying capacity by the reciprocal of the allowable current density. This will give you the total cross-sectional area required for the conductor or cable.
Total Cross-sectional Area = (Desired Current Carrying Capacity) / (Allowable Current Density)
Determine the individual cross-sectional area for each wire: Divide the total cross-sectional area by the number of wires you want to use. This will give you the cross-sectional area required for each aluminum and GI wire.
Individual Wire Cross-sectional Area = Total Cross-sectional Area / (Number of Aluminum Wires + Number of GI Wires)
Calculate the number of aluminum wires: Divide the total cross-sectional area by the cross-sectional area of each aluminum wire.
Number of Aluminum Wires = Total Cross-sectional Area / (Individual Wire Cross-sectional Area for Aluminum Wire)
Calculate the number of GI wires: Divide the total cross-sectional area by the cross-sectional area of each GI wire.
Number of GI Wires = Total Cross-sectional Area / (Individual Wire Cross-sectional Area for GI Wire)
Please note that the actual number of wires used may also depend on other factors such as the mechanical strength and voltage drop requirements, which may require additional considerations. It is always recommended to consult with a qualified electrical engineer or a professional who specializes in power distribution systems for an accurate and safe design.
For 220 kv?
Sir
You are great like a God kindly tell me about Lt lines 3ph 5wire lines and materials namaskar
ruclips.net/video/-aeKO39GnAs/видео.html
33kv line me safety factor nahi lenge tab?
the insulator is for electrical stresses as well as mechanical stress. If one of them is failed, then the conductor will be short with the cross arm of the tower. It means the conductor will be earthed. As a result, earth fault happens.
Yahan per voltage stress hoga na ki machanical stress
If an insulator has weak portion due to manufacturing defect ,it may break from that weak portion when mechanical stress is applied on it by its conductor.
Sir safety factor kitna bhi le sakate hai kya
But 132 kv me 12 insulator hoga
The calculation of the factor of safety (FoS) for an electrical insulator involves assessing the mechanical strength and electrical withstand capabilities of the insulator. Here's a general approach to calculating the FoS for an electrical insulator:
Determine the Maximum Working Load (MWL): Identify the maximum load or stress that the insulator is expected to experience during normal operation. This load can include mechanical loads, such as weight or tension, and electrical loads, such as voltage or current levels.
Determine the Maximum Allowable Load (MAL): Refer to the manufacturer's specifications or applicable standards to determine the maximum load that the insulator is designed to withstand without failure. This value is typically provided by the manufacturer and represents the insulator's rated mechanical and electrical strength.
Calculate the Factor of Safety (FoS):
FoS = MAL / MWL
The FoS is the ratio of the maximum allowable load to the maximum working load. A higher FoS indicates a larger safety margin.
It's important to note that the specific calculations and factors considered may vary depending on the type of insulator, application, and relevant standards. In practice, it's recommended to consult the manufacturer's documentation, and industry standards (such as IEC or ANSI), or work with qualified engineers with expertise in insulator design and selection for accurate and reliable calculations.
Additionally, the factor of safety should consider various factors, including mechanical, electrical, and environmental conditions, to ensure the insulator's reliable performance under normal and extreme operating conditions.
But the actual calculation is N=LINE VOLTAGE IN KV /(1.732*11 KV). This equation is for the suspension tower. But you can take 1 or 2 extra for the tension tower
Sir har kv me safety factor lagata he kya
you can add . But the extra factor of safety means extra protection. It will be very healthy for a power system. But more adding of insulator means, extra cost..Now you can better understand. But for the tension tower you may add 2 more extra for safety. N=line voltage in kv /(1.732*11 kv).This is for the suspension tower (you may add one more extra). But for the tension tower, please add 2 more.
Sir 13 disc insulator kitni kv par lagte hai.yah mene dekha hai
220kv system. Actually, 12 is the number of discs. But (12+1)=13, 1 extra is taken for factor of safety
Mai 132 kv substation pr kaam krta hu yaha line me 12 insulator lage h kaise Please clear krein
Near substation and grid number of insulator increase because of safety factor
Disc insulator kitne Cain ka hona chahiye
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