another short method we can break the polynomial into multiplication of 2 quadratic and find the coefecients of these 2 quadratic then check D by range of A
Sir please differentiation ka vedio bhi upload kar do. 😅class 12 with a lot of questions practicing so that we can build up approach for solving 99% questions 😅
a^2+3ax+2x^2=x^4+x^3 Now make LHS perfect square by adding 9x^2/4 on both side (a+3x/2)^2+2x^2 =x^4+x^3+9x^2/4 (a+3x/2)^2 =(x^2+x/2)^2 a+3x/2=+-(x^2+x/2) Solve it by taking + and -
x^4+x^3=2x^2+3ax+a^2 Now make LHS perfect square by adding x^/4 on both side x^4+x^3+(x^2/4)=(x^2/4)+2x^2+3ax+a^2 (X^2+x/2)^2=(3x/2+a)^2 x^2+x/2=+-(3x/2+a) Now solve it by taking+ and - sign
😂 here it will not work cause the values of a are fixed and which is why we can't tell on which a max roots will occur it was pure coincidence that it worked here but conceptually it is wrong
@@Anzaan-s5m In general, many mathematicians considered to not have an eqn with power 3 and 1 as bi quadratic. But in class 9 ncert it has been clearly mentioned that a polynomial with highest degree 4 is bi quadratic..
@@MathematicalGalaxy 12th me hoon, Allen SRG batch mein, 6months me JEE hain, AIR1 toh nahi but Under 10k mains me aa jayegi, Tumse senior hoon, tumse zyada experienced hoon aur tumne zyada jaanta hoon
Sir please start any series for Olympiads...
another short method
we can break the polynomial into multiplication of 2 quadratic and find the coefecients of these 2 quadratic then check D by range of A
Sir please differentiation ka vedio bhi upload kar do. 😅class 12 with a lot of questions practicing so that we can build up approach for solving 99% questions 😅
Already uploaded
@@mkhanra8038 bro not that one which were earlier recorded I want one shot latest video. Like now sir is uploading
my guess is 2. I tried drawing graph of both functions and see where it cuts
Sir please take question on trigonometry
Graph banake jyada easily aur jaldi analyse aur question easily hoo jata
Mera bhi 4 hii aaya
Kaise , graph kese bnaya? , btana plsssssssssss
@@opguy_219 Nahi hoga graph se Desmos par banake dekh x⁴ + x³ - 2x² and 3ax + a² a(0.75,1)
Khud dikh jaaega graph se possible nai hai
sir please make a video on honourable ramanujan ji
a^2+3ax+2x^2=x^4+x^3
Now make LHS perfect square by adding 9x^2/4 on both side
(a+3x/2)^2+2x^2
=x^4+x^3+9x^2/4
(a+3x/2)^2 =(x^2+x/2)^2
a+3x/2=+-(x^2+x/2)
Solve it by taking + and -
Name of the book
x^4+x^3=2x^2+3ax+a^2
Now make LHS perfect square by adding x^/4 on both side
x^4+x^3+(x^2/4)=(x^2/4)+2x^2+3ax+a^2
(X^2+x/2)^2=(3x/2+a)^2
x^2+x/2=+-(3x/2+a)
Now solve it by taking+ and - sign
Good demonstration..
There is an error at 8:59
Bhannat🎉
Sir which book?...
Good Question
Sar is question ko Ham Aaj hi solve kiye aur aaj hi aap Dal Diya amazing 😮😮😮
Kaha kiya
Kon sa book sa name plz..
@@SRIRAM-je8hr
Nice solution
Nice sir
Sir it is easy usuing Descartes rule of sign and we also slove it usuing Ferrari rule
Bhai kya tum mujhe aise hi kuchh aur theorems bata sakte ho jis se questions short me hojaye
@@JamesBond-db5zx you can find Ferrari method and Descartes rule in RUclips
@@hritamkashyap yes bro can you tell me the chhanel name and some other useful topics for jee like you have told now
@@JamesBond-db5zx ruclips.net/video/crw4AzKqG60/видео.htmlsi=6Zk4wWBSfDg7Qkos
@@JamesBond-db5zx ruclips.net/video/crw4AzKqG60/видео.htmlsi=mU2Ilop6vcil_CaR
Solved using descartes rule of sign
elaborate 🤔
the heck is that
😂 here it will not work cause the values of a are fixed and which is why we can't tell on which a max roots will occur it was pure coincidence that it worked here but conceptually it is wrong
❤
Sir this is not bi quadratic equation..it is quartic eqn
@@Anzaan-s5m biquadratic aur quartic same things hai
@@uditraj5427 no quartic is a general 4 degree eqn while biquadratic has no terms of x3 and x
Firstly biquadratic and quadratic are not same, and further the given eqn is bi quadratic in x and quadratic in a.
@@priyankachhajer1702 your knowledge is insufficient...
@@Anzaan-s5m In general, many mathematicians considered to not have an eqn with power 3 and 1 as bi quadratic. But in class 9 ncert it has been clearly mentioned that a polynomial with highest degree 4 is bi quadratic..
Sir I had solved it using graph
Calculation based question hain
Jai hind ❤
cool
Divided by 2 ❎
Divide by 2 ✅
sir why don't you teach maths aptitude
Des Carte rule lagado
Bohat easy question tha sirf patience chahiye thi...👍
I will go for A
Sir ise to x4 ki graph bana ke kar sakte he
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Sabas beta 🐸🐸🤡
Chal re cringe
Wah
Bahut achha
Woh
Who is the class 12th student here
Any one from class 9 😅
Baccha hain tu bete abhi
@@SeriousAspirantJEE O! Toh tum kya AIR 1 ho jo mujhe salah dene a gaye?
@@MathematicalGalaxy 12th me hoon, Allen SRG batch mein, 6months me JEE hain, AIR1 toh nahi but Under 10k mains me aa jayegi, Tumse senior hoon, tumse zyada experienced hoon aur tumne zyada jaanta hoon
@@SeriousAspirantJEE 🤔 I do respect senior for sure
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