Remove Redundant Pairs - SQL Interview Query 1 | SQL Problem Level "HARD"

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  • Опубликовано: 27 дек 2024

Комментарии • 203

  • @mindlessscroll
    @mindlessscroll 8 месяцев назад +3

    With rm as (select *,
    IF(STRCMP(brand1,brand2) > 0, concat(brand1,brand2,year), concat (brand2,brand1,year)) as con
    from brands ),
    rm1 as(
    select *,
    row_number() OVER(PARTITION BY con order by con ) as id
    from rm)
    select brand1, brand2, year from rm1 where id=1 or (custom1 custom3 and custom2 custom4)

    • @gauravtanwar8886
      @gauravtanwar8886 7 месяцев назад

      as per the 3rd condition you need a little adjustment in your code (custom1 custom3 OR custom2 custom4)*

    • @gauravtanwar8886
      @gauravtanwar8886 7 месяцев назад +2

      but thanks to your answer i got to know about STRCMP

  • @onkarbarhate7799
    @onkarbarhate7799 14 дней назад +1

    Thank you for your SQL learning videos! Watching them has significantly boosted my confidence, and I also subscribed to your SQL session on your techtfq website.
    While going through one of your videos, I noticed a minor error: in the WHERE clause, the second condition should use 'OR' instead of 'AND'.
    Just thought to share this feedback. Keep up the great work!
    with cte as
    (select *,
    case when brand1 < brand2 then concat(brand1, brand2, year)
    else concat(brand2,brand1,year)
    end as new_grp_2
    from brands),
    cte_2 as
    (select *, dense_rank() over(partition by new_grp_2 order by brand1) as rnk
    from cte)
    select cte_2.brand1, cte_2.brand2,cte_2.year, cte_2.custom1,cte_2.custom2,cte_2.custom3,cte_2.custom4
    from cte_2
    where rnk 2 or
    (custom1 custom3 or custom2 custom4)

  • @malcorub
    @malcorub 10 месяцев назад +50

    I love the idea! I will be tuning in every day this month.... even on weekends with hangover. LOL

    • @techTFQ
      @techTFQ  10 месяцев назад +7

      Thats the spirit 😃

    • @somnathdutta6311
      @somnathdutta6311 10 месяцев назад +2

      @@techTFQ Don't give the ans in same video. give ans in next video. It will be more helpful. It will also create a hook for your next video and a short of competition as well.

    • @umangbhatnagar1415
      @umangbhatnagar1415 9 месяцев назад +1

      @@somnathdutta6311 Why making things tough. Let it be easy. We are not as good as you. The video's purpose is to help community who is still in its very crude form.

    • @Useruse867
      @Useruse867 6 месяцев назад

      @@somnathdutta6311 no one will ever watch as there are many channels who solve and give answer there.

  • @ganeshsundarachary3239
    @ganeshsundarachary3239 9 месяцев назад +5

    Awesome , Great learning Experience. Pls make more such challenges.

  • @ContentRoomB
    @ContentRoomB 5 месяцев назад

    I'm finally done with query 1 with your solution help. looking forward to cracking future questions on my own

  • @VijayKumar-ec3dz
    @VijayKumar-ec3dz 8 месяцев назад +2

    Hi sir, My solution is kind of similar as below
    with cte as (select *,case when custom1=custom3 and custom2=custom4 then 1 when custom1custom3 or custom2custom4 then 2 else 3 end as r from t1)
    select * except(r,rn) from (select *,row_number() over(partition by r,year order by year) as rn from cte) a where coalesce(case when r=1 then rn=1 else null end,1=1)

  • @junaidmahmud2894
    @junaidmahmud2894 9 месяцев назад +1

    Great solution. I'm afraid I am a bit late to start but I will definitely continue this!

  • @rahuldey4730
    @rahuldey4730 10 месяцев назад +1

    Loved the question Sir. Even if I was not able to solve this at my own but after I saw the solution and the logic behind this I am speechless and amazed. This is the type of content we need.

  • @beautifulworld3976
    @beautifulworld3976 9 месяцев назад

    It is informative from the problem statement we get idea how to solve thank you so much it is helpful for me this 30 days i will become still more strong in SQL database

  • @splendidabhi
    @splendidabhi 10 месяцев назад +2

    Excited to kick off the #30DaySQLQueryChallenge with Query #1! Let's sharpen those SQL skills together and ace those interview queries. Can't wait to see what we'll learn throughout this challenge! 💻💡

    • @techTFQ
      @techTFQ  10 месяцев назад

      Amazing 😍

  • @dataengineeringsimplified1049
    @dataengineeringsimplified1049 7 месяцев назад +2

    with tbl as
    (
    SELECT *,case when brand1

    • @37_om
      @37_om 4 месяца назад

      This is somewhat more clear
      i think

  • @VivekKBangaru
    @VivekKBangaru 8 месяцев назад

    Awesome TFQ

  • @inderpanda1
    @inderpanda1 10 месяцев назад +4

    In my opinion at least out of 30 question first 5 should have been Easy to Medium Level.
    It seems to be hard and complex for me.
    The questions should have been from only 1 function among these CTE, Case, Subquery, etc

  • @AbhishekPandey-c8o
    @AbhishekPandey-c8o 10 месяцев назад

    i was waiting for this

  • @MwAVlogs
    @MwAVlogs 9 месяцев назад

    I am new in this field, but like the way you explain. It is a complex one I know but still after practicing I’ll get it.

  • @aarizaziz4380
    @aarizaziz4380 9 месяцев назад

    Thank you very very very much for this initiative. Looking forward to a multi decade event by you just like this! You are one of the best instructors I have come across internet for SQL. hats off to you for taking time to educate us and building the community.

  • @ramakrishnatirumala428
    @ramakrishnatirumala428 8 месяцев назад

    super videos bro...keep posting

  • @andreanlobo7373
    @andreanlobo7373 9 месяцев назад +1

    extremely insightful.. thanks

  • @kalpeshispatil
    @kalpeshispatil 9 месяцев назад

    You are simply amazing buddy... I am user CTE many times, but not as you shown.. Fan of yours... ❤❤ Will be tuning daily.. Your first example has cracked and shown us where we land in DB queries... Thank You For Us Efforts

  • @prithvirajpatil7388
    @prithvirajpatil7388 9 месяцев назад

    Good question❤ starting it from today.

  • @khushboobaghel6594
    @khushboobaghel6594 10 месяцев назад +1

    Thankyou for guiding for 30 days it will help us to improove Sql.

  • @ShubhamGautam-k1k
    @ShubhamGautam-k1k 9 месяцев назад

    we can put union as well in place of or, and case statements for the conditions in place of Row_num window function, rest is same.

  • @koushikdey100
    @koushikdey100 9 месяцев назад

    Great !!, Thank you

  • @Hsalz
    @Hsalz 9 месяцев назад

    Simply amazing. Thanks, Thoufiq!

  • @shwetamishra1497
    @shwetamishra1497 10 месяцев назад +2

    Very helpful . Thank you so much big bro for this series, just keep continue.🙏

  • @fathimafarahna2633
    @fathimafarahna2633 10 месяцев назад +2

    Amazing 🔥🎉

    • @techTFQ
      @techTFQ  10 месяцев назад

      Glad you like it!

  • @pavanigoud98
    @pavanigoud98 10 месяцев назад +1

    Please also doo the sql interview questions for data analyst. Lots of love ❤

  • @NEHAKHANZODE-p8p
    @NEHAKHANZODE-p8p 5 месяцев назад

    Thank you for explaining thoroughly :-)

  • @pinkfloyd2642
    @pinkfloyd2642 9 месяцев назад

    Subscribed right away. Great content. Can't wait to watch more of your videos this weekend itself.

  • @yi-lehung6311
    @yi-lehung6311 10 месяцев назад

    still the best SQL video!!!! I love this idea, please continue!

  • @piyushnautiyal6271
    @piyushnautiyal6271 10 месяцев назад +1

    amazing que and the way of solving is awesome.. thank u so much techTFQ!!

  • @khushbu3025
    @khushbu3025 10 месяцев назад

    Really, It's very nice 🙂 Thank you for this series.

  • @padhenamit
    @padhenamit 10 месяцев назад

    Thank you for your amazing lectures and feedbacks and thank you for being so supportive!

  • @chahatjain3745
    @chahatjain3745 9 месяцев назад +5

    with cte as (Select *, row_number() over(partition by Case
    when brand1>brand2 then CONCAT(brand1,brand2,year)
    else CONCAT(brand2,brand1,year) end order by year) as rn
    from brands)
    Select * from cte rn where rn=1 or (custom1 custom3 and custom2 custom4)

  • @mkgeidam
    @mkgeidam 10 месяцев назад +1

    Thanks you Sir, it really helpful

  • @vishalmaurya3008
    @vishalmaurya3008 10 месяцев назад +1

    ❤ 30days of sql >>>>75 days of 😊 hard चैलेंज 😅
    Thank you sir that is extremely amazing❤❤❤❤❤❤❤

  • @johnsonrajendran6194
    @johnsonrajendran6194 9 месяцев назад

    Love the way you teach ❤

  • @sriharidhanakshirur9245
    @sriharidhanakshirur9245 9 месяцев назад

    Intresting Question!
    Im sure if anyone deligently follow this #30DaysSQLChallenge
    his/her SQL skills drastically improves

  • @sandydsa
    @sandydsa 9 месяцев назад

    Fantastic 🌻🌻🌻

  • @livelovelaugh4050
    @livelovelaugh4050 10 месяцев назад

    Thank you so much for starting this series. 🙏

  • @CricketLivejavwad
    @CricketLivejavwad 10 месяцев назад +5

    Techtfq is back💯😎
    We all are excited.

  • @12Patni
    @12Patni 8 месяцев назад

    Thoufiq Mohammed
    Thank you for the thorough explanation. The problem's difficulty level is high.
    Below is my solution: I utilized others columns in the Partition By clause, ensuring accurate row numbering without the need for an additional where clause condition.
    ;with CTE AS (
    Select * ,
    case when brand1 < brand2 then CONCAT(brand1,brand2,year) else CONCAT(brand2,brand1,year) end as Brand
    from [Asif_SQL].[dbo].[brands]
    ),
    CTE_RN AS (
    SELECT *
    , ROW_NUMBER () OVER (PARTITION BY BRAND,CUSTOM1,CUSTOM2,CUSTOM3,CUSTOM4 ORDER BY BRAND ASC ) AS RN
    FROM CTE
    )
    SELECT brand1,brand2,year,custom1,custom2,custom3,custom4
    FROM CTE_RN
    WHERE RN = 1

    • @shabbiransari9731
      @shabbiransari9731 6 месяцев назад

      What will you do if the brand is of equal length?

  • @sourabroy7787
    @sourabroy7787 10 месяцев назад

    great initiative and quality content 👍

  • @ritika29
    @ritika29 9 месяцев назад

    Thanks, it was Helpful 👍
    Quick question, what if there was a row with NULL in brand1 column
    Example: INSERT INTO brands VALUES ( NULL,'lava', 2020, 5, 9, NULL, NULL);

  • @navaneeth6414
    @navaneeth6414 10 месяцев назад

    Great! video Thanks

    • @techTFQ
      @techTFQ  10 месяцев назад

      Glad you liked it!

  • @vishisbest
    @vishisbest 9 месяцев назад

    This was pretty interesting

  • @nointernet...1800
    @nointernet...1800 10 месяцев назад

    Nice video

  • @pathanfirozkhan5503
    @pathanfirozkhan5503 10 месяцев назад +1

    Amazing video sir, Thanks for your time

  • @ananth.r5317
    @ananth.r5317 9 месяцев назад

    Thanks lots..❤❤❤❤

  • @abhishekkukreja6735
    @abhishekkukreja6735 8 месяцев назад

    Awesome, Can you share excel page : it's good to store the results and everthing in excel

  • @MuhammedSavadkv
    @MuhammedSavadkv 8 месяцев назад

    Great. Thank you

  • @jollymeelubari9045
    @jollymeelubari9045 9 месяцев назад

    Thanks for this

  • @Itsourfamilys
    @Itsourfamilys 8 месяцев назад

    Thank you so much for SQL videos

  • @haleylearn
    @haleylearn 7 месяцев назад +1

    For condition: For pairs of brands in the same year ---> if custom1 != custom3 OR custom2 != custom4 : then keep both pairs
    Why is it (custom1 custom3 AND custom2 custom4) NOT is (custom1 custom3 OR custom2 custom4) ?

    • @AJBeiza
      @AJBeiza 3 месяца назад

      I had same question, I think just an error. Output is the same in this case but given other entries the output would be different

  • @PraveenSinghRathore-df3td
    @PraveenSinghRathore-df3td 2 месяца назад

    MYSQL solution:
    with cte as (select *, case when brand1 < brand2 then concat(brand1,'-',brand2)
    else concat(brand2,'-',brand1) end as pair from brands)
    , cte2 as (select *, row_number() over(partition by pair,year order by (select null)) as rn from cte)
    select brand1, brand2, year, custom1, custom2, custom3, custom4 from cte2
    where case when (custom1 = custom3) or (custom2 = custom4) then rn = 1
    else rn >= 1 end;

  • @manirahofred801
    @manirahofred801 8 месяцев назад

    This was really helpful. However, if the dataset was too big and brand records were many & different, I don't think "case when" functionality would be helpful. At the moment because of the dataset we have, that would be the easiest way!

  • @sweetysweetyvghb
    @sweetysweetyvghb 6 месяцев назад

    I couldn't solve myself, but I find it easy after seeing the solution..not sure y.

  • @aswinc4829
    @aswinc4829 10 месяцев назад

    Thank you,it really helps

  • @priyankapatil6835
    @priyankapatil6835 9 месяцев назад

    big thanks techTFQ

  • @khushboobaghel6594
    @khushboobaghel6594 10 месяцев назад

    Thankyou Sir

  • @sivakrishnasriram4782
    @sivakrishnasriram4782 10 месяцев назад

    Thank You😊.

  • @srinubathina7191
    @srinubathina7191 10 месяцев назад

    Thank You sir

  • @waynegreen7970
    @waynegreen7970 10 месяцев назад

    Good content!

    • @techTFQ
      @techTFQ  10 месяцев назад

      Glad you think so!

  • @riyatiwari4767
    @riyatiwari4767 10 месяцев назад

    Can you please make video on how to write dynamic query in pyspark.
    That would be a lot of help.
    Thank u❤

  • @Venkatesh-bs7kb
    @Venkatesh-bs7kb 9 месяцев назад

    Thanks a lot for the video. the way you explain CTE's are awesome!!
    in your solution line number 20, as per problem statement, it should be an OR condition ryt ?
    ('or (custom1 custom3 OR custom2 custom4)')

  • @krishkhemani96
    @krishkhemani96 9 месяцев назад

    I am sure you love cases😂.Make a video on them please 😅

  • @jayavinayak2593
    @jayavinayak2593 10 месяцев назад +1

    Thank You

    • @techTFQ
      @techTFQ  10 месяцев назад

      You're welcome

  • @ManiKandan-kg5ky
    @ManiKandan-kg5ky 10 месяцев назад

    Waiting bro

  • @ahmedjassimameenco
    @ahmedjassimameenco 10 месяцев назад

    thanks

  • @sandeepkumarsingh7981
    @sandeepkumarsingh7981 10 месяцев назад

    Hi Tafiq, I'm also your huge friend, and your technic is always help to improve my skill. I saw the solution and the logic behind this I am speechless and amazed. This is the type of content we need.
    thanks you so much.
    Hey Tofiq, I have downloaded you content but that file is blank. please help me on that.....

  • @Dopamine.Moments
    @Dopamine.Moments 10 месяцев назад

    You are helping me a lot to build my understanding about SQL, Thanks to you I have cleared most of the interviews by watching and following you. I will be turning in for this series. 😊

  • @SamiUllah-ie7pn
    @SamiUllah-ie7pn 10 месяцев назад

    Thanks you😊

    • @techTFQ
      @techTFQ  10 месяцев назад

      Welcome 😊

  • @HarshaV44
    @HarshaV44 10 месяцев назад

    Thank you so much.
    little modified :
    WITH CTE AS (
    SELECT * ,
    ROW_NUMBER() OVER (PARTITION BY CASE WHEN brand1 < brand2
    THEN CONCAT (brand1,brand2,year)
    ELSE CONCAT (brand2,brand1,year)
    END ORDER BY (SELECT NULL)) as RKNO FROM brands )
    SELECT * FROM CTE WHERE RKNO = 1
    or (custom1 custom3 and custom2 custom4)

    • @zeeshanahmed2594
      @zeeshanahmed2594 9 месяцев назад

      Great modification!
      I think in where clause it should be OR in place of AND.

  • @nehalmaheshwari1999
    @nehalmaheshwari1999 4 месяца назад

    @techTFQ Shouldn't the custom1 of one of the row be compared with the custom3 of the other row having same airID instead of the same row?

  • @tornado9689
    @tornado9689 10 месяцев назад

    My question is you can also select query with column name what you have done in last to fetch the data . What is the need of using cte then

    • @codeduel
      @codeduel 9 месяцев назад

      For Optimization sake

  • @HERO3530
    @HERO3530 2 месяца назад

    This solution only works when first pair is "custom1 = custom3 OR custom2 = custom4 ". If the first pair were "custom1 != custom3 OR custom2 != custom4 " and the second pair were "custom1 = custom3 OR custom2 = custom4 ". then it would return only one pair despite one of the pair is "custom1 != custom3 OR custom2 != custom4 ".

  • @hrishiAOL
    @hrishiAOL 5 месяцев назад

    Can you suggest online SQL editor for practice?

  • @thirupathinaidusomineni
    @thirupathinaidusomineni 9 месяцев назад

    with cte_check
    as
    (
    select *,
    case when (custom1custom3 and custom2custom4) or custom1 is null or custom2 is null or custom3 is null or custom4 is null then 1
    when brand1 = LEAD(brand2) over(order by year)
    and LEAD(brand1) over(order by year)=brand2
    and year = LEAD(year) over(order by year)
    and (custom1=custom3 and custom2=custom4) then 2 end as dd from brands
    )
    select brand1,brand2,year,custom1,custom2,custom3,custom4
    from cte_check
    where dd in (1,2)

  • @Shruti_Gore
    @Shruti_Gore 7 месяцев назад

    Can you make 30 days sql easy to hard playlist

  • @m.kirubakaran6564
    @m.kirubakaran6564 10 месяцев назад

    🤞🙏🏻

  • @phamnguyentrucgiang569
    @phamnguyentrucgiang569 9 месяцев назад

    ​ @techTFQ Hi, thanks for uploading useful videos. I want to ask: this is easy, medium or hard question?

  • @amanchourasia8280
    @amanchourasia8280 9 месяцев назад +1

    what if the brand names start with the same letter?

  • @prithvipampana1492
    @prithvipampana1492 9 месяцев назад

    Bro @malcorub what if brand1 and brand2 length is same

  • @teawithbaety
    @teawithbaety 4 месяца назад +1

    While using concat () in MySql why am I getting NULL for pair_id?

    • @SwarajLandge-c7f
      @SwarajLandge-c7f 4 месяца назад

      use this code ---just change case condition
      with cte1 as( select *,
      case
      when brand1

    • @teawithbaety
      @teawithbaety 4 месяца назад +1

      @@SwarajLandge-c7f okay. Thanks for your help!

  • @madhurimadas6260
    @madhurimadas6260 10 месяцев назад

    amazing!! can you tell me what to do in case of equal length of brand1 and brand2?
    thanks in advance :)

    • @bhanugoyal428
      @bhanugoyal428 9 месяцев назад

      you can put that condition in the same case along with < condition. Ultimately we are concatenating all the records in that cte.

  • @shristisrivastava1324
    @shristisrivastava1324 9 месяцев назад

    How will you know when to use CTE by looking at the question, sir?

  • @manvendramingwal8696
    @manvendramingwal8696 7 месяцев назад

    how about 100 days of database series,from 0 to 100 making people perfect in DB, i would like to join.

  • @venkateshmallisetty4196
    @venkateshmallisetty4196 10 месяцев назад +1

    it is very tipical to download the data set could you please help me with that

  • @MrYeduguri
    @MrYeduguri 10 месяцев назад

    Hello Thoufiq.. Thank you so much for sharing great content. Are you offering online training for sql & plsql?

  • @mohdtoufique3786
    @mohdtoufique3786 10 месяцев назад

    Thanks a lot for the content..
    WITH PAIRS AS(
    SELECT *,CASE WHEN brand1

  • @pavankumar-cw2sx
    @pavankumar-cw2sx 9 месяцев назад

    @techTFQ
    Can we give OR condition instead of AND in WHERE condition at final query
    like as: where rn = 1
    or (custom1 custom3 OR custom2 custom4);
    ????????????????

  • @NikhilRaj-sd4xm
    @NikhilRaj-sd4xm 3 месяца назад

    Here is my Solution:
    -- Define the first CTE to calculate the next brand values
    WITH cte AS (
    SELECT *,
    LEAD(brand2, 1, NULL) OVER (PARTITION BY year ORDER BY year) AS next_brand,
    LEAD(brand1, 1, NULL) OVER (PARTITION BY year ORDER BY year) AS next_brand1
    FROM brands
    ),
    -- Define the second CTE to categorize each row
    cte2 AS (
    SELECT *,
    CASE
    WHEN brand1 = next_brand
    AND brand2 = next_brand1
    AND custom1 = custom3
    AND custom2 = custom4 THEN 'group'
    ELSE 'not a group'
    END AS GroupType
    FROM cte
    )
    -- Select rows where GroupType is 'not a group'
    SELECT brand1,
    brand2,
    year,
    custom1,
    custom2,
    custom3,
    custom4
    FROM cte2
    WHERE GroupType = 'not a group';
    Please suggest if it is a good solution or not?

  • @sabmelegarebaba1233
    @sabmelegarebaba1233 9 месяцев назад

    Bro pz upload 2 video per day😊

  • @HimanshuSingh-cf7wr
    @HimanshuSingh-cf7wr 10 месяцев назад

    My Approach:-
    select BRAND1,BRAND2,year,Custom1,Custom2,Custom3,Custom4
    from
    (select case when rk=2 and Custom1==custom3 and custom2==custom4 then 1 else 0
    end as duplicate_entry,p.*
    from
    (select row_number() over (partition by common_name,year order by Brand1) as rk,k.*
    from
    (select *,concat(greatest(BRAND1,BRAND2),least(BRAND1,BRAND2)) as common_name from input_table)k)p)o where duplicate_entry1 order by BRAND1

  • @smrutiranjansenapati1695
    @smrutiranjansenapati1695 9 месяцев назад

    Hi, Since it has example of 5-6 records, when we have large amount of records, how we can mak sure that the 1st condition if custom1 = custom3 & custom2 = custom4 will not be satisfied to eliminate the duplicate?
    Please reply. Thank you

  • @yashmistry1424
    @yashmistry1424 9 месяцев назад

    Can we use self join instead here!

  • @ManishChauhan-fb7uz
    @ManishChauhan-fb7uz 10 месяцев назад +3

    with cte as
    (
    select
    *
    , row_number() over(partition by id order by id) as rn
    from
    (
    SELECT
    *
    , case
    when brand1 > brand2 then concat(brand1, brand2, year)
    else concat(brand2, brand1, year)
    end as id
    , case
    when custom1 = custom3 or custom2 = custom4 then 1
    else 0 end as flag
    FROM brands
    ) as t
    )
    select
    *
    from cte
    where rn = 1 or (rn > 1 and flag = 0)

  • @surabhijagadish5210
    @surabhijagadish5210 8 месяцев назад

    Made complex query too easy.

  • @ashabhumza3394
    @ashabhumza3394 9 месяцев назад

    I think there should have been 'or' condition in the bracket instead of 'and'

  • @lakshitgupta5064
    @lakshitgupta5064 10 месяцев назад

    What if after creating the pairid, we just perform groupby operation based on pairid, custom1, custom2, custom3 and custom4 and then filter it by using having count = 1? Will this approach work?