Sir, In 17:33 why we have to take as q tends to zero for electric field? Electric field is force experienced per unit positive charge, so q should tend to 1 to get E=F, If q tends to 0 and if we apply the limit, then electric field becomes infinite know sir. Can u please explain it
Bro lim tends to zero means the value is not equal to zero but very nearer to zero , so if we divide F by very very small number we get approximately F itself so we have taken lim tends to zero
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sir in the def of one coulomb of charge time: 11:20 the charges should be kept in vaccum is a point to be added i guess sir tell me if i am right by liking the comment sir really appreciate ur sincere efforts thank u so much sir ❤
@@adilan8064 my question is : despite being unlike charges, how are the 2 charges stable at 1 position? they must attract and move toward each other right
@@AbhiramGSrivathsa When there are two equal and opposite charges it should attract. But when it comes to Dipole, charges are kept at "Minimum distance'. Due to which nuclear force and bonding force start to exert a repulsive force between them. By which [ Force of attraction = Foce of repulsion ]. And another thing is, a dipole kept in Uniform Electric field, The line of action of force is opposite for + & - charge. In case of chemical molecules like H2O, CO2.. there is ionic and covalent repulsion.( bond foces ). and that depends on electronegativity of the molecules. I hope you got it..❤
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Doubt sir: the test charge used to measure electric field at a point should be vanishingly small why ? An electrostatic field line is continuous curve i.e.. a field line cannot have sudden breaks why not ?
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Sir, In 17:33 why we have to take as q tends to zero for electric field? Electric field is force experienced per unit positive charge, so q should tend to 1 to get E=F, If q tends to 0 and if we apply the limit, then electric field becomes infinite know sir. Can u please explain it
Bro lim tends to zero means the value is not equal to zero but very nearer to zero , so if we divide F by very very small number we get approximately F itself so we have taken lim tends to zero
So if we divide by very small number that is approximately equal to zero we get F itself
1:17 yes sir understanding
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sir in the def of one coulomb of charge time: 11:20
the charges should be kept in vaccum is a point to be added i guess sir
tell me if i am right by liking the comment sir
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Sir ಸ್ವಲ್ಪ basics ಕೂಡ ಹೇಳಿ sir 4:42
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DOUBT : how can a dipole exist? because the 2 opposite charges attract and will come together and fuse
please reply sir
🙏
No bro ,, charges are fundamental so they can't get fused or combine like wise of matters .. chargers can pnly get added and multipled
@@adilan8064 my question is : despite being unlike charges, how are the 2 charges stable at 1 position? they must attract and move toward each other right
H2O molecule is an example of electric dipole ( H+ and OH- )
There is just a bonding
I hope you got that
@@AbhiramGSrivathsa they are held together with an electromagnetic forces ,,
@@AbhiramGSrivathsa When there are two equal and opposite charges it should attract.
But when it comes to Dipole, charges are kept at "Minimum distance'. Due to which nuclear force and bonding force start to exert a repulsive force between them.
By which [ Force of attraction = Foce of repulsion ].
And another thing is, a dipole kept in Uniform Electric field, The line of action of force is opposite for + & - charge.
In case of chemical molecules like H2O, CO2.. there is ionic and covalent repulsion.( bond foces ). and that depends on electronegativity of the molecules.
I hope you got it..❤
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Sir while teaching u use some real life example to make us understand the concept....it helps us lot to understand and remember the concept clearly...❤
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Doubt sir: the test charge used to measure electric field at a point should be vanishingly small why ?
An electrostatic field line is continuous curve i.e.. a field line cannot have sudden breaks why not ?
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