Finite Fields & Return of The Parker Square - Numberphile

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  • Опубликовано: 17 июл 2024
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Комментарии • 1,2 тыс.

  • @numberphile
    @numberphile  2 года назад +218

    Extra footage & become a millionaire by winning The Parker Prize: ruclips.net/video/hn8SwBhhDvU/видео.html
    The Original Parker Square video: ruclips.net/video/aOT_bG-vWyg/видео.html
    Stand-Ups Maths on RUclips: ruclips.net/user/standupmaths
    Matt's Books (Amazon): amzn.to/3absFfV
    Matt's playlist on Numberphile: bit.ly/Matt_Videos
    Parker Square Merch: numberphile.creator-spring.com/listing/the-parker-square

    • @nowionlywantatriumph
      @nowionlywantatriumph 2 года назад +8

      A millionaire, or a Parker Millionaire?

    • @felixlaroche8039
      @felixlaroche8039 2 года назад +11

      Btw, Matt Parker got something wrong! Z mod powers of primes are *not* fields! For instance, in Z_4, 2x2 = 4 = 0, so that Z_4 has zero-divisors. Hence, since it has zero-divisors, it cannot be a field

    • @ZainAK283
      @ZainAK283 2 года назад +4

      @@felixlaroche8039 Exactly - given a power of a prime, there is a finite field of that size, but it's NOT just modular arithmetic (it's a bit more complicated than that)

    • @zunaidparker
      @zunaidparker 2 года назад +2

      Man I feel attacked...

    • @baronhannsz8900
      @baronhannsz8900 2 года назад

      How do we get the article you referenced?

  • @wilkmarton
    @wilkmarton 2 года назад +3530

    I don't mind Numberphile's filler episodes, but I love it when they seriously advance the main plot like this.

  • @JulietKneeled
    @JulietKneeled 2 года назад +3322

    When I saw that "Parker" was a property of something in an actual, published research paper I legitimately doubled over laughing. The parker square is officially a real mathematical term!! I never thought I'd see the day.

    • @tsawy6
      @tsawy6 2 года назад +243

      See, at first I was surprised, but after a certain point it's like... Damn Matt and Numberphile's fans have gotta include a significant fractions of budding mathematicians

    • @jamesonhardy2126
      @jamesonhardy2126 2 года назад +6

      Same

    • @DomenBremecXCVI
      @DomenBremecXCVI 2 года назад +189

      @@tsawy6 I feel like there are 10 types of mathematicians watching Numberphile; those that came here because they know maths, those that were brought into maths by Numberphile and those who forgot this comment isn't supposed to be a spin on the classic binary joke.

    • @AaronRotenberg
      @AaronRotenberg 2 года назад +53

      @@DomenBremecXCVI That's a real Parker list, if I do say so myself.

    • @Deus_Almighty
      @Deus_Almighty 2 года назад +4

      It's not published though

  • @dig_dus
    @dig_dus 2 года назад +2486

    That P vs NP killed me

    • @RanEncounter
      @RanEncounter 2 года назад +62

      That was golden :D

    • @Saka_Mulia
      @Saka_Mulia 2 года назад +43

      Had to pause for my lols to come to a side-stiched stop

    • @sgttomas
      @sgttomas 2 года назад +9

      Best part 😁

    • @beev
      @beev 2 года назад +14

      surely, NP should be rebranded IP - Inverse Parker.... ;-)

    • @GreRe9
      @GreRe9 2 года назад +1

      +

  • @SkywalterDBZ
    @SkywalterDBZ 2 года назад +772

    In the Parker Square video, Matt said something like "In mathematics, fame is different. It's when someone looks you up once a century.". This must mean Matt is REALLY famous now.

    • @custodeon
      @custodeon 2 года назад +69

      he is some hybrid of maths-famous and regular famous which is both more famous than maths-famous and less famous than celebrity-status

    • @thealkymyst
      @thealkymyst 2 года назад +67

      Parker Famous.

    • @SG2048-meta
      @SG2048-meta Год назад +10

      @@custodeon TL;DR a superposition of different famousnesses

    • @tinkut8960
      @tinkut8960 Год назад +10

      @@custodeon he’s a Parker square of a celebrity

    • @crisdunbar4753
      @crisdunbar4753 Год назад +3

      He's on a coffee mug fer gosh sake. Millennia from now, archaeologists (probably alien) will dig them up and he'll still be famous.

  • @QuantumHistorian
    @QuantumHistorian 2 года назад +1178

    It's so rare, and incredibly delightful, to see a grown man beaming with joy at what is literally a consequence of being mocked in front of an audience of millions.

    • @landsgevaer
      @landsgevaer 2 года назад +29

      He is a meme.
      I would be happy too...

    • @warasilawombat
      @warasilawombat 2 года назад +78

      Honestly I think it’s quite sweet that they named it after him.

    • @almoglevin
      @almoglevin 2 года назад +46

      But affectionally mocked.

    • @broadleyn
      @broadleyn 2 года назад +5

      Well, self-mocked, but yep. Matt is awesome.

    • @josephjennings7932
      @josephjennings7932 2 года назад +6

      All this mockery just earned him a place in mathematics for posterity.

  • @saraqael.
    @saraqael. 2 года назад +1259

    8:33
    Kid: “Mom can I have P vs NP“
    Mom: “No, we have P vs NP at home“
    P vs NP at home: Parker vs Non-Parker

  • @sakkikoyumikishi
    @sakkikoyumikishi 2 года назад +786

    Also:
    "They're all non-Parker - because they work." *dies inside*

  • @wecantry4393
    @wecantry4393 2 года назад +713

    Parker square video was one of the most fun video I've ever watched. I never thought how a simple mathematical puzzle can be so enchanting.

    • @goldnutter412
      @goldnutter412 2 года назад +2

      1/7 is a cool number with 6 recurring digits and the 0 is the FP function
      How many are there for 1/49 ? 😎

    • @veggiet2009
      @veggiet2009 2 года назад +2

      @@goldnutter412 but not in integer fields

    • @goldnutter412
      @goldnutter412 2 года назад +1

      14:48 there's 13 ? really ? 🤣
      This seems right to me for personal reasons hahaha also distribution wise you wouldn't expect, but possibly suddenly another group appears wayyyy up there in the giant numbers.. hm

  • @TECHN01200
    @TECHN01200 2 года назад +778

    I love how mathematicians use Parker as an adjective meaning "almost works"...

    • @dexter2392
      @dexter2392 2 года назад +68

      If the large mathematical community finally caught it... Parker will be a legend.

    • @pvic6959
      @pvic6959 2 года назад +39

      idk if I would be happy or sad if my name was given that definition. On one hand, my name has become an ACTUAL property in math. Like in a published paper - it will live on forever. but on the other hand, the property my name describes is "doesnt work" LOLOL

    • @Relkond
      @Relkond 2 года назад +38

      Matt Parker is a comedian. Some of the best jokes in life are where things almost work.
      I’m sure he’s elated.

    • @TECHN01200
      @TECHN01200 2 года назад +3

      @@pvic6959 At the very least, they have a sense of humor...

    • @brandonthesteele
      @brandonthesteele 2 года назад +8

      I would be tremendously honored to have my name used in math in any capacity. Matt seems pretty jazzed about it.

  • @WMTeWu
    @WMTeWu 2 года назад +765

    Everybody seem excited that "parker" has been mentioned in real, published research paper - but I think most of you underestimate how exited the authors of the paper are, that their paper has been featured in real, published Numberphile video.

    • @nomekop777
      @nomekop777 2 года назад +64

      It's basically numberphile bait

    • @mati.benapezo
      @mati.benapezo Год назад +12

      And we got tricked.

  • @olifantoliver
    @olifantoliver 2 года назад +420

    Everytime he said "Non-Parker.. because.. it's working" you can see in his eyes, a part of him dies. :D

    • @simonmultiverse6349
      @simonmultiverse6349 2 года назад +5

      It's fame... don't knock it!

    • @loturzelrestaurant
      @loturzelrestaurant 2 года назад

      @@simonmultiverse6349 Anti-Science is on the Rise. Uneducation causes Muffled Logic to be be more and more accepted, so casual B.S. is getting more and more popular.
      People embarass themselves all the time now by claming NASA is faking the Sun,
      the moon is a hologram,
      the Earth is flat,
      Aura and Chakra are kinda Science, so trust me bro, i know we are all immortal - oh, and one last thing: Koalas are Fake; they are ALL CGI. All.

    • @SillyMakesVids
      @SillyMakesVids 2 года назад +6

      A part of him becomes Parker.

    • @loturzelrestaurant
      @loturzelrestaurant 2 года назад

      @Irony What a silly comment, Irony.

    • @Triantalex
      @Triantalex 6 месяцев назад

      false :D.

  • @alancash6420
    @alancash6420 2 года назад +448

    I look forward to seeing Matt being awarded the Inverse Fields Medal

    • @LeonardChurch33
      @LeonardChurch33 2 года назад +105

      Would that involve paying $15,000 for damages done to the field of mathematics?

    • @tobiaswilhelmi4819
      @tobiaswilhelmi4819 2 года назад +69

      I would much more like to see a Parker Medal for mathematical innovations that almost work.

    • @MattMcIrvin
      @MattMcIrvin 2 года назад +27

      The Parker Finite Fields Medal

    • @cookieninja2154
      @cookieninja2154 2 года назад +19

      The medal for math that doesn't work but you gave it a go.

    • @simonmultiverse6349
      @simonmultiverse6349 2 года назад +4

      @@MattMcIrvin Damn! You got there before me!

  • @HopUpOutDaBed
    @HopUpOutDaBed 2 года назад +167

    Finally someone explaining P vs. NP in a way everyone can easily understand.

  • @helpme6599
    @helpme6599 2 года назад +411

    It's been 5 years, but Matt Parker is still Matt Parker.

    • @yourguard4
      @yourguard4 2 года назад +22

      Matt Parker + 5 years = Matt Parker ? :D

    • @2D_SVD
      @2D_SVD 2 года назад +2

      And that's great!

    • @Ravendragon52
      @Ravendragon52 2 года назад +29

      Matt Parker is officially invariant wrt time

    • @proloycodes
      @proloycodes 2 года назад

      88th like!

    • @idahogie
      @idahogie 2 года назад +5

      And I'm still non-Parker.

  • @feudiable
    @feudiable 2 года назад +559

    The 6x6 table says 3*2 = 1 mod 6, but I guess that is a parker-one.

    • @Minihood31770
      @Minihood31770 2 года назад +125

      The Parker Times Table

    • @cybisz2883
      @cybisz2883 2 года назад +66

      Lol, I caught that too. Seems closeups of that table were edited out due to the mistakes in it.

    • @laurihei
      @laurihei 2 года назад +31

      Plus he also circled that one when circling all the ones in the table ':D

    • @simonmultiverse6349
      @simonmultiverse6349 2 года назад +13

      Can we have a Parker Timetable, (not "Times Table") where the trains almost but not quite arrive at the times they're supposed to?

    • @laurihei
      @laurihei 2 года назад +11

      @@simonmultiverse6349 I think we already have that :D

  • @agar0285
    @agar0285 2 года назад +367

    I love the fact that "Parker" defined as "not working" is an actual term in a math research. I just started laughing so much, this was awesome.

    • @user-zn4pw5nk2v
      @user-zn4pw5nk2v 2 года назад +3

      6:50 ( left square 3;2 )(seen the meme, just was about to comment on the Parker square, and was informed that it's actually a Parker Parker square. The circle later really helped )

    • @RaiinWing
      @RaiinWing 2 года назад +2

      lets gooo you watch numberphile too

    • @agar0285
      @agar0285 2 года назад +1

      @@RaiinWing Hi rainwing 😀

    • @Triantalex
      @Triantalex 6 месяцев назад

      ??

  • @YosmHere
    @YosmHere Год назад +17

    For those who might've missed a pun at 8:38:
    P v/s NP (Which in video is used as a short form for Parker v/s Non-Parker) is actually one of the seven millenium problems by the Clay University. Each problem worth a million dollars. That means if you solve it you'll get a million dollars.

  • @karlwaugh30
    @karlwaugh30 2 года назад +243

    For finite fields of prime power orders there was some confusion in this video. The integers mod 49 or 4 or 8 etc don't produce finite fields of those orders. It's just that there do exist other finite fields of those orders with different structure to them.
    Eg. In Z mod 4 the multiples of 2 are 2x1 = 2, 2x2=0, 2x3=2 and 2x0=0 and so there is no inverse for 2.

    • @samuelthecamel
      @samuelthecamel 2 года назад +31

      The true Parker Finite Fields

    • @MrSamwise25
      @MrSamwise25 2 года назад +1

      Thanks for pointing this out! :)

    • @probablyapproximatelyok8146
      @probablyapproximatelyok8146 2 года назад +20

      And I think the way you can get finite fields of prime power order p^k is by adding zeros of particular polynomials to the finite field Z/pZ, much like you can add i (one of the zeros of x^2 + 1) to the real numbers to get a new, bigger field: The complex numbers

    • @djyotta
      @djyotta 2 года назад +1

      I was thinking that finite fields of order of "powers of primes" could be things other than Z mod (p^r), but note that the paper says: Finite Fields and Rings - which implies to me that they're claiming that magic squares of squares don't just work in (most) finite fields of the form Z mod (p), but also some rings of the form Z mod (p^r) where p is prime...

    • @johanrichter2695
      @johanrichter2695 2 года назад +8

      Yes, that is a very important point, hope they correct that.

  • @P3dotme
    @P3dotme 2 года назад +412

    I think I'm going to start saying "don't go trivial" randomly to people.

    • @goldnutter412
      @goldnutter412 2 года назад +5

      Just answer any complex question with relativity
      Meaning of life ? relativity (or 369)

    • @MrAlRats
      @MrAlRats 2 года назад +1

      For String Theorists, every sequence of "Why" questions leads ultimately to the answer "String theory".

    • @goldnutter412
      @goldnutter412 2 года назад

      @@MrAlRats but they have to be "strings" of physical matter, with 2 dimensions 😅

  • @ugu8963
    @ugu8963 2 года назад +211

    I'm feeling the need to hear the word "Parkericity"
    "Hey how about the Parkericity of that field ?"

    • @prashantadhimal
      @prashantadhimal 2 года назад +10

      Parkerness?

    • @annie4424
      @annie4424 2 года назад +2

      This. This needs to become a thing.

    • @mond256
      @mond256 2 года назад +9

      Why not have degrees of Parker for how far off from working it is

    • @Games_and_Music
      @Games_and_Music 2 года назад +9

      Margin of error is now called "Parker approximation".

    • @NoNameAtAll2
      @NoNameAtAll2 2 года назад +1

      @@Games_and_Music approximation is already Parker property (Parker action?)
      Parkerximation?

  • @namduong8437
    @namduong8437 2 года назад +5

    The fact that you still have the mug at 7:52 makes me super happy to follow math community

  • @shawon265
    @shawon265 2 года назад +22

    Matt Parker: You cannot find a whole number inverse of an integer.
    1: I will pretend I didn't see that.

    • @purrplaysLE
      @purrplaysLE 2 года назад

      1*1=1

    • @ragnkja
      @ragnkja 2 года назад

      Unless it’s the identity. Just like the only non-negative number with a non-negative additive inverse is 0.

  • @illesizs
    @illesizs 2 года назад +292

    "Every real number has a buddy real number, where if they multiply together, you get 1."
    1: "Am I a joke to you?"
    0: "Yes."

    • @pulsefel9210
      @pulsefel9210 2 года назад +27

      1 is such a lonely number. so powerful they wont even let it have its proper title of prime of primes.

    • @Sibula
      @Sibula 2 года назад +29

      @@pulsefel9210 You could even say that one is the loneliest number

    • @neopalm2050
      @neopalm2050 2 года назад +17

      -1:

    • @BizVlogs
      @BizVlogs 2 года назад +5

      1? One’s buddy number is 1.
      0? Zero is the same as n (limit as n goes to zero). So its buddy number in that case is 1/n (limit as n goes to 0).

    • @allanolley4874
      @allanolley4874 2 года назад +3

      It is after all an ancient mathematical proposition that one is not a number but the unit first enunciated by Aristotle. If 1 is not a number then 0 is right out.

  • @MrQwefty
    @MrQwefty 2 года назад +66

    He gave it a go, he tried, and finally he's achieved infamy in actual mathematical research! Kudos to you Matt

  • @shaftahoy
    @shaftahoy 2 года назад +6

    14:46 'Parker' being in Comic Sans is the cherry on the top of this video.

  • @Sam_on_YouTube
    @Sam_on_YouTube 2 года назад +31

    I tip my hat to the author of this paper. Well done.

  • @KSJR1000
    @KSJR1000 2 года назад +9

    This is the most clear explanation of N vs NP I've ever seen.

  • @JanxakaJX
    @JanxakaJX 2 года назад +38

    Matt Parker is a great teacher and quite funny too. I love seeing him here.

  • @cereal_chick2515
    @cereal_chick2515 Год назад +3

    This is one of the greatest character arcs I've ever seen!

  • @floyo
    @floyo 2 года назад +53

    5:13 The finite field with 49 elements is not actually the integers mod 49 (Z/49Z), because 7 has no inverse. The construction of this field is more complicated.

    • @jaredbitz
      @jaredbitz 2 года назад +7

      For the curious - to actually construct that finite field, consider the set of polynomials with coefficients modulo 7. You can get a field with 49 elements by taking all polynomials of the form ax + b, and then doing arithmetic on them modulo x^2 - 3 (again all the coefficients are modulo 7). 7 choices for a and 7 choices for b make 49 elements, and you can never multiply two polynomials to get zero because x^2 - 3 doesn't factor modulo 7.
      You can get finite fields whose sizes are higher prime powers (i.e. 7^n) by doing arithmetic modulo some irreducible polynomial of degree n.

    • @FireSwordOfMagic
      @FireSwordOfMagic 2 года назад +1

      Same with any number that isn't a prime.

    • @danielyuan9862
      @danielyuan9862 2 года назад +2

      @@jaredbitz why modulo x^2-3 and not x^2?

    • @danielyuan9862
      @danielyuan9862 2 года назад +2

      @@jaredbitz no wait, it's because you can imagine x=sqrt(3)

    • @user-fd1ux4ly1e
      @user-fd1ux4ly1e 11 месяцев назад

      @@jaredbitz , or for people who don't know how to do that with finite fields, but do know how complex numbers work, imagine that i is the square root of 3 mod 7, and consider things of the form a + bi where a and b are in Z7.

  • @chimiseanga9054
    @chimiseanga9054 2 года назад +25

    Correction: only "integers mod a prime" is a field, not "integers mod a power of a prime". There are finite fields of size "power of a prime" but they are not a quotient of the integers.

    • @keineangabe8993
      @keineangabe8993 2 года назад +1

      Thank you! I didn't think they would miss such an obvious mistake..

    • @mbartelsm
      @mbartelsm 2 года назад +6

      It was a Parker-explanation

    • @kijkbuis8575
      @kijkbuis8575 2 года назад +1

      These are the Parker finite "fields"

  • @stardustpan
    @stardustpan 2 года назад +18

    PARKER SQUARE LES GOOOO

  • @davidwilsch4668
    @davidwilsch4668 2 года назад +27

    Z mod 49 and Z mod 25 are NOT fields. There exist fields with 49 or 25 elements but they aren't simply integers modulo some number.

    • @davidkalichman
      @davidkalichman 2 года назад

      THANK YOU for pointing this out. An uncharacteristic error from Matt :(

  • @terraqueo89
    @terraqueo89 2 года назад +8

    This is one of the best gags of this channel lol

  • @EdwardCree
    @EdwardCree 2 года назад +14

    "What about _infinite_ rings?" Well, if a magic square of squares "works" in ℤ, then it must also work modulo n ∀ n∈ℕ. However, in some of those ℤₙ, the square may have repeated entries that weren't there in ℤ; in particular we know that this must be the case for all n for which ℤₙ is Parker. (As the paper points out, and as you mention in the extra footage, a solution in ℤ would imply there are only finitely many Parker rings.) Thus those rings give us constraints on any possible solution in ℤ; for instance, ℤ₆₇ being Parker implies that a magic square of squares in ℤ cannot have all nine numbers distinct modulo 67, because otherwise it would imply a solution in ℤ₆₇. It's the Parker rings, and _only_ those rings, which help us by cutting down the search space for ℤ; Parker rings are _useful_ because they help us identify what _won't_ work, and that can be valuable in itself :)
    Hope that helps Matt feel a little better about his eponymy.

  • @iah7264
    @iah7264 2 года назад +306

    "Return of the Parker square"
    This is probably the most clickbaity title possible, for numberfile fans ;)

    • @Neefew
      @Neefew 2 года назад +26

      Is it clickbait if it's true?

    • @SheldonBird
      @SheldonBird 2 года назад +2

      It's the only reason I clicked instantly

    • @simonmultiverse6349
      @simonmultiverse6349 2 года назад

      Return of The Pink Parker?

    • @simonmultiverse6349
      @simonmultiverse6349 2 года назад +1

      ...featuring Peter Parker? (different superhero, I know)

    • @alfieomega
      @alfieomega 2 года назад

      it did reappear, not as main focus though
      more like a cameo old character in the new series

  • @ImaginaryMdA
    @ImaginaryMdA 2 года назад +44

    The Parker prize needs to become a reality, surely!

    • @nielskorpel8860
      @nielskorpel8860 2 года назад +13

      For all maths research whose results do not accomplish what they aimed for,...
      ...but which do make some headway towards it, which gives an insight into the subject, which explores useful perspective on the subject, or which studies the hardship of proving what you are trying to prove,...
      ... so that maybe one day we can make more informed maths research that DOES achieve what it was trying to do.
      In other words, for all the disappointing, unglamorous near-misses which might eventually lead to actual results.
      Not a bad thing to have a prize for, actually.
      If this approach of near misses does at some point answer the question whether the integers are parker or not, then it actually becomes a serious proposal: the approach worked.

    • @camicus-3249
      @camicus-3249 2 года назад +7

      @@nielskorpel8860 Basically, "Give it a go"

  • @rubenlarochelle1881
    @rubenlarochelle1881 2 года назад +36

    "Technology has moved on since", showing a 3D-printed version of what he once wrote on brown paper.

  • @bootesvoidband
    @bootesvoidband 2 года назад +20

    I’m waiting for the OEIS entry for Parker Numbers

    • @babel_
      @babel_ 2 года назад +6

      A308838, the Orders of Parker finite fields of odd characteristic, aka the list shown ignoring 2. The "state of the art" has improved and it was shown 243 is a Parker finite field.

  • @PopeLando
    @PopeLando 2 года назад +25

    8:09 I am made up, and enormously proud of you, Matt! Edited: doubly proud of your joke at 8:33 🤣🤣

  • @IamBATMAN13
    @IamBATMAN13 2 года назад +13

    The P vs NP reference killed me

  • @ModeDecay
    @ModeDecay 2 года назад +50

    I wish there was a compilation of every time Matt says "big fan..."

  • @TheSummoner
    @TheSummoner 2 года назад +102

    5:09 - Is he implying that the integers mod 49 are equivalent to the finite field of order 49? Because as far as I know this only work for primes, for prime *powers* the multiplicative structure is actually different.

    • @Vodboi
      @Vodboi 2 года назад +21

      Yea, just noticed that, in Z_49 you have 7*7=0, and a field doesn't have zero divisors, so its not a field. I guess he kinda confused it with the fields of order equal to that prime power.

    • @pianissimo7121
      @pianissimo7121 2 года назад +2

      I am a bit confused, does a Z7 field for example, have 0 in it? Cause 0 doesn't have a multiplicative inverse does it?

    • @AGLubang
      @AGLubang 2 года назад +12

      @@pianissimo7121 Yes. All fields must have a 0. The rule for multiplicative inverse doesn't include 0, as with usual real numbers, rationals, etc.

    • @dabluse3497
      @dabluse3497 2 года назад +7

      @@pianissimo7121 In fields, zero is a special number that follows different rules. In every field, 0*a=0, for any a in the field, and 0 is the only number that doesn't have a multiplicative inverse, because a field needs 0 to work. That's true in the real numbers, complex numbers, and any other field. Hope that clears it all up.

    • @Vodboi
      @Vodboi 2 года назад +5

      @@pianissimo7121 The statement of being a field is that: "Every nonzero element has a multiplicative inverse", where zero is defined as the element satisfying 0+x=x+0=x for all x in the field (in other words, 0 is the additive identity). So yes Z_7 has the elements {0,1,2,3,4,5,6}, where all but 0 have multiplicative inverses

  • @EmC_98
    @EmC_98 2 года назад +3

    10:58 nice surprise seeing myself in a Numberphile video!!

  • @smallishkae
    @smallishkae 2 года назад +59

    “If you’ve got a number, I dunno… a.”
    Can’t wait to see that one out of context

  • @argentvixen
    @argentvixen 2 года назад +15

    This is about right. We had the "Mould effect" so now Matt is just catching up to Steve with the "Parker property". I assume this is the omen that Matt will catch up with a million subs soon. 😘

  • @davidharmeyer3093
    @davidharmeyer3093 2 года назад +2

    I burst out laughing when you put "P vs. NP" as an overlay on the screen for Parker vs. Non Parker fields

  • @user-vn8kw9sm3k
    @user-vn8kw9sm3k 2 года назад +7

    It's not true that integers mod 49 (or any non-trivial prime power) form a field. For example, 7 doesn't have an inverse mod 49.
    I think Matt got confused by the notation F_{49} for a finite field with 49 elements.

  • @vindj2391
    @vindj2391 2 года назад +4

    14:10 i don't know why but seeing those parkers pop up on the screen cracks me up

  • @antezante
    @antezante 2 года назад +7

    This was great, having in-depth math on a higher level than usual! Please do more of this!

  • @yoyoyogames9527
    @yoyoyogames9527 2 года назад +1

    awesome stuff as usual, thanks so much for making these sorta vids i love them

  • @ferraneb
    @ferraneb Год назад +2

    5:04 Just to clarify the the integers mod a power of a prime do NOT form a field in general (for example, 7 does not have an inverse mod 49). It is only the case when the power is 1 (that is, the integers mod a prime). There exist finite fields of size p^k for p prime and k > 1, but they are constructed differently.

  • @gordonwiley2006
    @gordonwiley2006 2 года назад +6

    We tease because we love you, Matt. Your enthusiasm is infectious. I consider myself, to be a Parker Person.

  • @DemoniteBL
    @DemoniteBL 2 года назад +2

    I just love the fact that "Parker" is a term accepted by most if not all mathematicians.

  • @danielbergman1984
    @danielbergman1984 2 года назад +2

    This video made me happy! Not that any other Numberphile video makes me otherwise, but this one's special. Congratulations Matt!

  • @rubenlarochelle1881
    @rubenlarochelle1881 2 года назад +4

    Parker and non-Parker being used in an actual paper was an hilarious twist ahahahah

  • @codelerias
    @codelerias 2 года назад +9

    I love it when they bring back season 1 characters!

  • @nopetuber
    @nopetuber 2 года назад +4

    I've been following these channels forever and I'm like, look at you Matt! Congrats!

  • @matheusspable
    @matheusspable 2 года назад +4

    Ok. When you get named in a paper that actually delivers, and sets a new standard for maths... This is amazing.

  • @WGSen
    @WGSen 2 года назад +4

    I am in love with this whole saga

  • @MeTalkPrettyOneDay
    @MeTalkPrettyOneDay 2 года назад +3

    Truly the most troll-y way to get something professionally named after you. I love it.

  • @mathieudehouck9657
    @mathieudehouck9657 2 года назад +2

    This amazing 1 in the column of 2.
    Made my day Mr Parker.
    Thank you.

  • @cyaneya
    @cyaneya 2 года назад +6

    This was soooo interesting, thank you Parker for being very knowledgeble and funny. I wish i was able to sit with you with a glass of beer and just ask basic questions about math, which i'm terrible at, and the answers would be probably unexpected. Yeah, thanks again!

  • @certainlynotthebestpianist5638
    @certainlynotthebestpianist5638 2 года назад +3

    That's absolutely insane! Parker is not only a scientist, but also a living meme - we know that for quite some time. But the fact, that he's not just an ordinary walking meme (albeit this in itself is something to be proud of), but a meme which is included in scientific papers. Incredibly amazing!

    • @jd9119
      @jd9119 8 месяцев назад

      Are mathematicians scientists? And if so (or not so), what exactly are the criteria we're using to define what a scientist is?

    • @fregattenkapitan
      @fregattenkapitan 8 месяцев назад

      ​@@jd9119they do research in universities in a scientific field. Difficult to be more of a scientist....

    • @jd9119
      @jd9119 8 месяцев назад

      @@fregattenkapitan Except scientists usualy apply the mathematics to another discipline.

  • @johnchessant3012
    @johnchessant3012 2 года назад +16

    Important note (for anyone who, like me, is going to spend a few hours looking into this): The finite field F_(p^k) is NOT the integers mod p^k. For example, F_9 = {0, 1, 2, i, 1+i, 2+i, 2i, 1+2i, 2+2i} where i = sqrt(-1).

    • @redapplefour6223
      @redapplefour6223 2 года назад +3

      well you know for pedantry that it's actually that i^2 = -1, thats the technical definition

    • @StoicTheGeek
      @StoicTheGeek 2 года назад +1

      Darn I just went and typed all that out less clearly and then I saw your comment!

    • @StoicTheGeek
      @StoicTheGeek 2 года назад +3

      Please also not that the field F_(p^k) has character p ie. np = 0 for all n in the field

    • @leftaroundabout
      @leftaroundabout 2 года назад +1

      @@redapplefour6223 that's not the technical definition either. Or, well, it is part of the definition, but of the technical definition of the _multiplication operation_ in ℂ, not of i. The imaginary unit can't be defined like this. (Note that e.g. in the quaternions there are three distinct values that all fulfill this equation!) To make it a technical definition, you need to first define ℂ as a 2-dimensional vector space with unit vectors 1 and i, and only then equip it with the multiplication that has this property, in order to form a field.

    • @redapplefour6223
      @redapplefour6223 2 года назад

      @@leftaroundabout right, thanks! makes sense that that's how that works. so are field extensions are just unit vectors in disguise?

  • @baguettegott3409
    @baguettegott3409 2 года назад +2

    This made me so happy. I can't believe this is actually in the paper - what a wonderful thing the community has created here.

  • @kwanarchive
    @kwanarchive 2 года назад +2

    It would be hilarious if Parker vs Non-Parker becomes an elemental part in solving the P vs NP issue.

  • @henrygreen2096
    @henrygreen2096 2 года назад +8

    I actually find the the fact that Parker is rare a really cool thing. Sure they “don’t work” but they got people talking first, and there aren’t that many

  • @Astromath
    @Astromath 2 года назад +3

    A Numberphile video with Matt Parker AND a Stand-Up Maths video on the same day? Nice!

  • @meeDamian
    @meeDamian 2 года назад +1

    This is the greatest video I've watched this year by far 👏🏻👏🏻👏🏻.

  • @video99couk
    @video99couk 2 года назад +2

    Many years from now when you're pushing up the daisies, at least you will be forever remembered having had a mathematical property (even a duff one) named after you. Quite an honour.

  • @user-gh2fd8kg6v
    @user-gh2fd8kg6v 2 года назад +153

    This guy has such comical facial expressions, he would probably do well in comedy movies if he did acting.

    • @EM-pb7lk
      @EM-pb7lk 2 года назад +74

      He does math related stand-up

    • @elevown
      @elevown 2 года назад +21

      Well he does do stand up about math lol

    • @danielleanderson6371
      @danielleanderson6371 2 года назад +20

      He's really the Jim Carrey of math(s) educators.

    • @yousorooo
      @yousorooo 2 года назад +12

      Matt Parker is a comedian after all

    • @abhijiths5237
      @abhijiths5237 2 года назад

      Mallu spotted 😂

  • @DiracComb.7585
    @DiracComb.7585 2 года назад +4

    Being diagnosed with Parker finite-fieldness is a truly heartbreaking event, my condolences.

  • @arnauarnauarnau
    @arnauarnauarnau 2 года назад +1

    Wow this is so cool! Awesome sequel to parker square. Can’t wait for part 3 in a few years

  • @Frownlandia
    @Frownlandia 2 года назад +13

    Maybe a Mathematician gets to be upset when their name is associated with a kind of failure, but a Standup Mathematician is just happy to setup a punchline.

  • @julesbrunton1728
    @julesbrunton1728 2 года назад +2

    I've always enjoyed how the multiplication symbol is the addition symbol nudged over 45° and the division symbol is the minus symbol with some dots or recently also just pushed over at an angle /

  • @cgibbard
    @cgibbard 2 года назад +18

    Polynomial rings typically aren't fields, but you can make fractions of them (rational functions) and those will be a field.

    • @JM-us3fr
      @JM-us3fr Год назад +2

      True, but those aren’t _finite_ fields. You have to mod an irreducible polynomial to get a field.

  • @ancbi
    @ancbi 2 года назад

    Love seeing the RUclips url put in as a reference in the paper.

  • @expomath9348
    @expomath9348 2 года назад +2

    Excellent comme d'habitude ! Un plaisir de regarder cette chaine.
    Translation for non french people : " Hi, it's sunny today but it depends where you live actually"

  • @rickdoesmath3945
    @rickdoesmath3945 2 года назад +5

    I think convergence almost everywhere should be called parker convergence.

  • @eatingsfun
    @eatingsfun 2 года назад +3

    I can't wait to watch this video

  • @SigmaSixSoftware
    @SigmaSixSoftware 2 года назад +1

    I haven’t started the video yet and this is the best explication of fields I’ve heard

  • @asdfghyter
    @asdfghyter 2 года назад

    15:26 I love that the previous video is in the citations for this paper!

  • @falquicao8331
    @falquicao8331 2 года назад +6

    The sequel we always knew we needed

  • @mohamedaminekoubaa5231
    @mohamedaminekoubaa5231 2 года назад +3

    a small mistake at 5:04. It only works for prime numbers. If you take a power of prime numbers, it is not modular arithmetic anymore. So basically if you are working in the finite field with four elements, 1+1 is still 0 just like the field with two elements, but you have an extra element x which satisfies x^3=1.

  • @louiswhaley258
    @louiswhaley258 2 года назад

    Your Parker video reveals a surprising side of Parker! I watched with rapt attention because you cleared up so many questions about finite fields I one video. Now I have a proposition for you (not the spicy kind); what would you say if I said that I applied aspects of quantum mechanics to something that you just talked about, but that wasn't sure was a finite field (integers mod a prime). I did some research (I'm not a slouch) but I came away confused by reading the wiki pages and online textbooks. In your honor I would like to call the application of QM to finite fields 'Parker Mechanics.' Has a nice ring to it, no? Just my way of saying thanks for a fine (-ite) video!

  • @calebcopeland6425
    @calebcopeland6425 2 года назад +1

    It brings me joy that the Parker Square has left the numberphile bubble and ventured into general mathematics and is being used in published research papers

  • @shanathered5910
    @shanathered5910 2 года назад +6

    Finite field F₄ isn’t technically integers mod 4, it’s a bit more complicated than that. Example: 2² = 3, it’s not mod 4 because 2² = 0 mod 4. This is true for all non-prime order fields.

    • @shanathered5910
      @shanathered5910 Год назад

      I also showed that integers mod 4 has zero divisors and therefore NOT a field

  • @RuyLopezTheSicilian
    @RuyLopezTheSicilian 2 года назад +10

    P vs NP has just been solved 😂😂

  • @jannis7139
    @jannis7139 2 года назад +2

    Actually, finite fields with order p^n are not Z mod p^n (check for yourself 2^2). They are instead constructed using polynomials, as outlined on wikipedia

  • @alienworm1999
    @alienworm1999 2 года назад +1

    8:00 I read the title of the video and knew what I was getting into, but I didn't realize they did poor Matt THAT dirty with the section title

  • @XtReMz98
    @XtReMz98 2 года назад +3

    Well. I can only guess that Matt Parker’s ego went from finite to non-finite after being established as an (in)famous legend of mathematics! I love this guy!

  • @eathonhowell7414
    @eathonhowell7414 Год назад +2

    This is the equivalent of how Gary Larson is now credited as naming "the spiny bits on the end of a Stegosaurus" the Thagomizer because before him nobody had a name for it. It was done as a joke and then someone saw value outside of it being funny.

  • @RedStinger_0
    @RedStinger_0 2 года назад +1

    Thank you Parker for taking one for the team.

  • @jolle938
    @jolle938 2 года назад +2

    What a coincidence I was wearing my Parker Square shirt today!

  • @Megalopros
    @Megalopros 2 года назад +3

    15:25 hey...brady's name is on a paper now (if this has already happened before i didn't notice)
    (also...it would technically be better if the link was archived since stuff on youtube can disappear)

  • @alastairdouglas1737
    @alastairdouglas1737 2 года назад +11

    Imagine in 100 years and students are asking why Parker means “something that almost works but isn’t quite there”

    • @koenth2359
      @koenth2359 2 года назад +1

      They probably ask:
      Grandad, what does shoddy mean?
      - That's an ancient word for Parker.

  • @jjknave
    @jjknave 2 года назад +1

    Nice Escher print! Also informative and entertaining video as usual.

  • @jan-pi-ala-suli
    @jan-pi-ala-suli 2 месяца назад +2

    parker is finally a true mathematician, he has a thing named after himself