Coefficients of the stiffness matrix - Derivation - Beam element

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  • Опубликовано: 12 сен 2024

Комментарии • 43

  • @dkscidmore
    @dkscidmore 3 года назад +3

    It took forever to find this video, but this was the concept I was stuck on. Thank you so much for making this video.

  • @tariq-salzengineering9650
    @tariq-salzengineering9650 2 года назад +4

    Hi, @TM'sChannel: I found a confirm mistake for the value of a2 which should be: a2=-3/L3(v1-v2) - 1/L(2 Θ1+Θ2) [Not "...-1/L( 1/L(Θ1+Θ2)" as per your slides]. I checked the after derivation part with matrix and also the algebra so I have confirmed this by all means. You also check and confirm.
    [P.S: Just checked you already mentioned that in description and also uploaded corrected video. Thanks for that. ] updated.

    • @evazhang3232
      @evazhang3232 2 года назад +1

      a2=-3/L2(v1-v2) - 1/L(2 Θ1+Θ2)

    • @nicologrilli9931
      @nicologrilli9931 11 месяцев назад

      I agree, a factor 2 is missing
      Thank you for pointing this out

  • @TMsChannels
    @TMsChannels  9 лет назад +1

    @Yong-Min Jeong I have noticed this and posted the corrected video at ruclips.net/video/RNIZ8Ju3_CI/видео.html
    Thank you for noticing... :)

  • @Amhara3K
    @Amhara3K 4 года назад +1

    Thanks. FYI, I think thet the General displacement equation(4:42) needs some revision on the fourth term.

  • @pratikdutta5136
    @pratikdutta5136 6 лет назад +5

    a2 = -3/L^2(v1-v2) - 1/L(2phi1+ phi2)

    • @MaltaLumpie
      @MaltaLumpie 5 лет назад

      Haha I can relate

    • @igorbarcelos9531
      @igorbarcelos9531 4 года назад +1

      @@MaltaLumpie Yes, there is this mistake in your calculation.

    • @ashrafultamjeed8746
      @ashrafultamjeed8746 4 года назад +1

      @@igorbarcelos9531 this mistake destroyed my day

  • @koushikr7039
    @koushikr7039 3 года назад +1

    TM's channel, can you show the derivation of stiffness matrix of 2 noded beam element

  • @joelstains4366
    @joelstains4366 6 лет назад +2

    Thank you so very much. That was very helpful.

  • @gowthamthotapalli8867
    @gowthamthotapalli8867 5 лет назад +1

    can you tell me how to find out the missing element in the matrix using shape function

  • @rajithodlme
    @rajithodlme 9 лет назад +1

    hi, one doubt, at 6:47, i am not getting the expansion of m1 as mentioned in the video, i get it as EI/l3 * (6LV1+fi1L^2-6LV2+fi2L^2) instead of EI/l3 * (6LV1+4fi1L^2-6LV2+2fi2L^2)...could you please upload a screenshot of the derivation .. thanks

    • @TMsChannels
      @TMsChannels  9 лет назад

      Hi, thanks for pointing it out :). I went back to my derivation and I discovered a typing error on the slide when calculating the displacement function v(x) at 4:44. The expression for the second term i.e. a2 should be: a2 = -3 (v1-v2) /L^2-( 2fi1 + fi2 )/L . Using this adjustment you can obtain the correct expression for v(x) and from there calculate the correct coefficients as in the video. Sorry for the inconvenience, I will upload a revision of this video with the typing error corrected. Please let me know if you encounter any more errors/doubts.

  • @DANNY40379
    @DANNY40379 7 лет назад

    Can you elaborate more on how the geometric stiffness matrix for a beam element is derived? thx

    • @TMsChannels
      @TMsChannels  7 лет назад

      Hi, I came across this document: people.duke.edu/~hpgavin/cee421/frame-finite-def.pdf Which has a version of the derivation. I will add it to my list for future videos. :)

  • @enginkeskin4829
    @enginkeskin4829 10 лет назад

    How v(x) changes when beam is parabolic haunch beam ? Or what changes?

    • @TMsChannels
      @TMsChannels  10 лет назад

      Hi, thanks for the comment. Honestly I don't really know. But the theory used to derive the matrix models the center line displacement of the (straight) beam. If that line is curved, I presume the theory also changes. Unfortunately I cannot say how. Another thing that also changes is the inertia (I), this becomes a function of position due to the change in height (h). Sorry if this is not very helpful, I have not yet dealt with the analysis of haunch beams.

    • @enginkeskin4829
      @enginkeskin4829 10 лет назад

      Hi, thanks for reply. Video is a very helpful. Haunch beam is not a easy topic. Thanks again.

  • @madalitsonjobvucristoclear
    @madalitsonjobvucristoclear 7 лет назад

    hi,how can i derive the stiffness matrix for authotropic beam?

    • @TMsChannels
      @TMsChannels  7 лет назад

      Hi, I actually have no idea. I haven't worked with such beams yet. Maybe you can find a paper or a book which deals with this topic and post it here? I would love to read it.

  • @mrajsma01
    @mrajsma01 9 лет назад +1

    a beam element has 3 dofs at each node

    • @TMsChannels
      @TMsChannels  9 лет назад

      +Chris10B Thanks for your comment. Are you referring to the degree of freedom associated with axial force and displacement as the one I left out?

    • @mrajsma01
      @mrajsma01 9 лет назад

      +TM'sChannel I realise you left it out since there is no load in the axial direction :) I am trying to solve a problem with three degrees of freedom at each node and looking for a way to deal with the stifness matrices.

    • @TMsChannels
      @TMsChannels  9 лет назад

      +Chris10B I see :). It sounds like you are describing a frame element. It is the combination of a beam and a bar element and thus have three degrees of freedom at each note. You can have a look at my derivation video of this element at ruclips.net/video/wq7Os0hdYtk/видео.html . The stiffness matrix is shown there. I also have a video showing an example on how to approach a problem with frame elements. I hope this comment was helpful :)

  • @zackbristol1
    @zackbristol1 7 лет назад

    If you have a cantilever does the stiffness matrix change ?

    • @TMsChannels
      @TMsChannels  7 лет назад +1

      Hi, no it does not. Only the boundary conditions are different i.e. the end degrees of freedom are not prescribed.

    • @zackbristol1
      @zackbristol1 7 лет назад

      TM'sChannel can you add a video of 6 degree of freedom derivation ?

    • @TMsChannels
      @TMsChannels  7 лет назад

      Hi, I have a video on the derivation of a frame element (which has 6 degrees of freedom, 3 at each node). You are welcome to view it here: ruclips.net/video/wq7Os0hdYtk/видео.html

    • @zackbristol1
      @zackbristol1 7 лет назад

      TM'sChannel sorry I meant 12, 6 at each node. I am interested in twist

    • @TMsChannels
      @TMsChannels  7 лет назад +1

      I see, I shall try to make a video for such an element, although it may take me a while. For torsion the basis is similar to that of the truss element, only with AE/L replaced by GJ/L. For the time being you may look at the book "a first course in the finite element method" by D.L. Logan which does provide a derivation of a 3D frame element. Hope this helps

  • @thomasdakin9108
    @thomasdakin9108 7 лет назад +18

    You teach me how to obtain stiffness coefficients, I teach you how to record on something other than a potato

    • @TMsChannels
      @TMsChannels  7 лет назад +4

      Hahaha, As long as you supply the computer :)

    • @dexbuild1206
      @dexbuild1206 6 лет назад +1

      😂

    • @abdofaisel4968
      @abdofaisel4968 5 лет назад

      Can you prove it with cojugate method or virutual work

  • @salmankhi
    @salmankhi 8 лет назад

    I can't find a1 and a2 at 04:15. Has anyone done this?

    • @TMsChannels
      @TMsChannels  8 лет назад

      +Salman Khan Hi, I have made a mistake in the video. Please see ruclips.net/video/RNIZ8Ju3_CI/видео.html for the corrected version.

    • @salmankhi
      @salmankhi 8 лет назад

      +TM'sChannel thanks for the fast response.

  • @azadyadav5080
    @azadyadav5080 2 года назад

    thanks