Untold concept of Influence Line Diagram - Structural Analysis
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- Опубликовано: 30 сен 2024
- In today's lesson, I will tell you how you can draw an influence line diagram (ILD) easily. We will clear all the confusion and commonly asked doubts in influence line diagram. Plus get short notes, and a challenge question on ILD here: www.apsed.in/p...
Imagine a moving vehicle on a bridge. For each location, we will get different Shear Force and Bending Moment. To overcome this difficultly, we go for Influence Line Diagram.
Müller-Breslau's principle makes it simpler to draw these influence line diagrams. We can say it in simple terms: ILD is a tool to see the effect of moving loads on a structure.
How to draw these influence line diagrams easily is what is covered in the video.
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Short Notes and Challenge Q on ILD here: bit.ly/ild_sa
well......no one told me to choose computer science instead of civil in counselling process........zindagi k lodey lag gaye
Koi na,Ek din har kisi ko marna hai chahiye cs wala ho ya civil wala🙂
I have a doubt. How can we say that ild for portion BC will be non linear when we apply a unit roller at B. Why cannot it be a similar triangle like how it looks like for portion AB, with 0.5 ordinate on AB and 0.5 ordinate for BC. Can you say when will ILD become non linear. The given sturcture is a determinate one but still why in portion BC we expect the ild for shear to be non linear and why we neglect it?
ILD is non linear for indeterminate structures. We are not neglecting it. The ILD on BC part is zero because when the load is on the span BC there will be no shear force at B. You can confirm the same by applying a unit load anywhere between B and D and finding the value of shear at B. ILD just shows the actual behaviour of reactions, SF etc. Not having any value between B and D just shows that there will be no shear at B when the load is between BD. Saying the part cannot be nonlinear is just a way to quickly solve it and avoid the confusion.
And it cannot be a triangle like AB part because C is an internal support. There is a single member between B and D, and it cannot simply lift like part AB. That only happens for an end support and cannot happen for an internal support.
@@APSEDUVERSE clearly understood sir thank you
@@APSEDUVERSE but sir y don't u hv done same for shear force given for eg gvn in description،،in this case ans would hv been half then
ILD always was confusing for me, got clarity now. Thank you so much for this
You are so welcome!
I solved this question within 30 sec using muller breslaw method
Sir, i am big fan of urs..!
U helped me a lot !
Sir, u r truly a Magnamopus, a Paragon and a Raconteur...!
You are welcome, these words mean a lot to our team ✌️ And we learnt a new word from you - raconteur 🙂
Keep watching
@@APSEDUVERSE ❤
Good
Could you please make a video on Matrix Method of structure Analysis.
Thanks
😂😂
Badhiya