Thank you very much for this video. I'm really frustrated to sort out a problem related with B.M.D & S. F. D for MMUP exam in Qatar. Now I'm relaxed. It's really useful. 👍
Sir,Plz solve and tell me the answer 🙏 A simply supported beam of length 8m carries point loads of 4,10 & 7 KN at 1.5m,2.5m,2m respectively from left end,Find max bending moment over the beam. Here I'm getting 30.9375 max bending moment but in book the answer is 90KNm ....HOW plzz tell me ?????🙏
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Really Very helpful vedios for self studying students...
Thank you so much for your determination to help other people that may not have time for these tutors 🙏
Thank you very much for this video. I'm really frustrated to sort out a problem related with B.M.D & S. F. D for MMUP exam in Qatar. Now I'm relaxed. It's really useful. 👍
Very impressive, learnt a lot from your simple method.
Great content sir
Very claer about the explaination... thank you so much
Very nice sir
Mst h sir👌👌
amazing😍😍😍😍😍 ❤❤❤💕❤❤💕💕❤❤❤❤❤❤💕💕💕💕💕💕💕💕💕💕
Thanks for the lesson
Sir, kindly see to the sign convention for moment calculation, for first part it should be -108(not 108), for second 48 (not 132). Please reply.
Nice video Sir
Sir,Plz solve and tell me the answer 🙏
A simply supported beam of length 8m carries point loads of 4,10 & 7 KN at 1.5m,2.5m,2m respectively from left end,Find max bending moment over the beam.
Here I'm getting 30.9375 max bending moment but in book the answer is 90KNm ....HOW plzz tell me ?????🙏
calculate clearly by using pen on the board for calculation part
WHAT IF DRAW THE SFD FROM RIGHT TO LEFT......IAM NOT GETING A CLOSED DIAGRAM
where TF did he get 90 from in the BMD
show some decency to someone teaching you..
Thank you sir
Mb= 36*3 kaisae huaa. Samajh nahee aayaa 🤔🤔🤔🤔🤔🤔🤔🤔🤔
Actually moment (torque )
= r ×f.
Not clear. Unable to understand. Could not get in BM calc. Not suited for beginners
Not clear some basic point ...shortcut calculation.
👍👍
sirji expain to kre kro...apne aap hi pd ke chle jate ho
Hii
😠😠😠
👎👎👎👎👎