Trying before watching solution: okay so Set S has every number from 0 to 4 excluding the integers and (2,3) and vo integers T mein hai (a) first thing im noticing is that set S mein infinite numbers hai and since infinite elements hai set S mein, there should be infinite functions kyunki those infinite elements ki value rearrange kar sakte ho infinitely Hence A is correct (b) yes again there could be infinite functions, [edit: did not differ between increasing and strictly increasing so galat hogaya] for better understanding assume T mein 2 numbers hai {0,1}, ab set S mein se we can select n numbers jinki value 0 hogi and baaki numbers ki value 1 hogi numbers of ways of selecting n numbers from infinite numbers = infinity Hence B is correct (c) tricky option confuse kardiya 120 dekhkar im thinking ki set S ko (0,1) (1,2) (3,4) mein divide kardenge and then inki alag values daal denge toh function should still be continuous since by definition left hand limit should be equal to right hand limit but integers toh domain mein hi nahi hai toh even if 1+ is not equal to 1-, it wouldnt matter because 1 hi domain mein nahi hai so set (0,1) ki same value hogi which could be any of {0,1,2,3} so there are 4 ways same for (1,2) and (3,4) so there should be 4*4*4 = 64 ways I think C is incorrect (d) I think this option is pretty easy after solving option c we saw ki continuous function means example: (0,1) = 0 , (1,2) = 3 and (3,4) = 1 so ismein we have to see lhd and rhd har jagah here function is constant in these intervals so I think lhd=rhd=0 Hence D is correct so id select A,B,D Edit: -2 ho gaya mera.
Option 1: obviously correct Option 2: continuous isn't possible when co domain only has discrete values Option 3: 4³(WTF is the official solution???) Option 4: any continuous function without any sharp points is differentiable especially constant functions (piecewise)
I am dropper ma ishe sahi karke aaya tha option a and d But mana socha ans 64 hona chahiye isliye c nahi maara Exam pressure ma kuch suzh nahi padhti hain
Mehne bhaiya meh functions just recently revise kiya tha so meh options a and d kardiya tha meh c mark nahi kiya tha same aap bhola haina english wahi karen se mark nhi kiya aap try karke iss type sawal aur lekar ao request hai bhai
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Trying before watching solution:
okay so Set S has every number from 0 to 4 excluding the integers and (2,3) and vo integers T mein hai
(a) first thing im noticing is that set S mein infinite numbers hai
and since infinite elements hai set S mein, there should be infinite functions kyunki those infinite elements ki value rearrange kar sakte ho infinitely
Hence A is correct
(b) yes again there could be infinite functions, [edit: did not differ between increasing and strictly increasing so galat hogaya]
for better understanding assume T mein 2 numbers hai {0,1}, ab set S mein se we can select n numbers jinki value 0 hogi and baaki numbers ki value 1 hogi
numbers of ways of selecting n numbers from infinite numbers = infinity
Hence B is correct
(c) tricky option confuse kardiya
120 dekhkar im thinking ki set S ko (0,1) (1,2) (3,4) mein divide kardenge and then inki alag values daal denge toh function should still be continuous
since by definition left hand limit should be equal to right hand limit but integers toh domain mein hi nahi hai toh even if 1+ is not equal to 1-, it wouldnt matter because 1 hi domain mein nahi hai
so set (0,1) ki same value hogi which could be any of {0,1,2,3} so there are 4 ways
same for (1,2) and (3,4) so there should be 4*4*4 = 64 ways
I think C is incorrect
(d) I think this option is pretty easy after solving option c
we saw ki continuous function means example: (0,1) = 0 , (1,2) = 3 and (3,4) = 1
so ismein we have to see lhd and rhd har jagah
here function is constant in these intervals so I think lhd=rhd=0
Hence D is correct
so id select A,B,D
Edit: -2 ho gaya mera.
nice shot bro
I solved it quickly, and especially for the second part, as i took example of G.I.F which is clearly not strictly increasing
Option 1: obviously correct
Option 2: continuous isn't possible when co domain only has discrete values
Option 3: 4³(WTF is the official solution???)
Option 4: any continuous function without any sharp points is differentiable especially constant functions (piecewise)
yeh bro was i damn confused
Bro in 4th option not only sharp point but also any vertical line also considered as discontinuous bz here dy/dx = 0 so not 🚫 diff...
@@Ashlu_JA-2024 I said continuous points, points with slope approaching infinity or negative infinity are discontinuous
@@lakshay-musicalscientist2144 no you said only abt sharp points na
@@Ashlu_JA-2024 Read closely I am talking about sharp point and continuous functions both
damn option 3 is just to check if the student is properly reading the option or not bruh
it should be written "continuous in its domain" in option c and d . due to this confusion i only marked a
Continuous always domain me hi dekha jata hai
A and D
Edit : Language khel gyi 😕
Sir a and d correct, at most le gaya 1 number aur maine us option pe 16 functions nikaal liye the 1 ke about limits check kar li thi galti se
I remembered I've marked 1 and 4 in advance 23 paper
I've got 64 for 3 one
😯In class 11th but still understand it😯
Mughe lga mera function weak h
But language aur thoery se lgbhag ho gya tha❤
I am dropper ma ishe sahi karke aaya tha option a and d
But mana socha ans 64 hona chahiye isliye c nahi maara
Exam pressure ma kuch suzh nahi padhti hain
Same thing did at home
Fcuked up in opt 3 (at most)
Solved by myself in about 5 to 10 mins... Probably the easiest question (if aspirant, loves maths, and that too when favourite section is calculus)
3 option me mistake hua mera ni to ye question hm kafi fundamental h
@@marinette-w3z Haa language par khela hai inhone
I contributed to rhe one who left this question
Tried to do got 2 option correct
Aaj hi diya ye paper
A, and d toh ho gya, c kaise kare click hi nahi hua
Opt 3 got me got a and d correct
Arey bhai. 3rd option tick nahi kiya bss. English weak hai thodi😢. Baaki correct aa gaya tha.
I always put more emphasis on theory but yeh 3rd option mera kaat ke chale gaya
Aaj tak kabhi zindagi m advance ka sawal solve karne m itna maza nhi aaya bhagwan kasam
Day 12 completed ❤❤
Got 1 option wrong selected that is option B however i got the intuition
Function abhi tak paraya hi nahi hai hame... 😅
Basic theory and definition implement hai
bhaiya aapki function ki playlist youtube pe kaafi sahi h.. please advance ke lie baki chapters bhi padha do pls pls pls pls pls
Sirf at most vale part pe atka bake 64 ans agya tha
Subject chnnel ki bio mai ' like ' ki spelling sahi kro bhiya
Thanks Bhaiya 🙏
I got to learn thing .
My reason for not able to solve is i got confuse with the correct way of thinking !!
mera last year dimag fuck up ho gaya tha ki partial marks kyu mile mujhe iske....abb samaj aaya meri english kharab xD
Bhaiya mujhe A and D aayi thi, C waala part samajh nhi aaya ki 64 tha ki usse zyada, isliye didn't check that
bhaiya C option ne C bana diiya baaki question badhiya tha..thankyouu🫡
6 mins lag gye but solve ho gya :)
#DAY 12.
Mehne bhaiya meh functions just recently revise kiya tha so meh options a and d kardiya tha meh c mark nahi kiya tha same aap bhola haina english wahi karen se mark nhi kiya aap try karke iss type sawal aur lekar ao request hai bhai
bhai continuous function padha hi nahi tha isliye nahi bana aur abhi theory hi padh raha hu problem solving nahi ki isliye
2026 jee advanced roadmap please
less than 1 min
Bhaiya pnc padha do
c and d option ko skip kar deta mai
couldnt solve
Sir maine toh tukka marke sahi Kiya tha😅
Set of 60 ke bare mai koi confusion hai to ask in comments
and that's the link for all the details www.jeesimplified.com/set-of-60