An Amazing Exponential Equation | Give It A Try!

[@vuyyurisatyasrinivasarao9246]

Good writing sir good solution

[@Quest3669]

X= 3

[@RealQinnMalloryu4]

111+2^3 2^3^2^3 1^1^1 1^1^1 1^1^2 1^2 (x ➖ 2x+1).

[@Fjfurufjdfjd]

Η σχεση γραφεται....[2^(7χ+3)]^(1/8)+[2^(7χ+3)]^(3/8)=520.
Αν 2^(7χ+3)=α^8 εχω α ^3+α-520=0
(α-8)(α^2+8α+65)=0 , α>0.
α=8. Δ

[@潘博宇-k4l]

X=3.

[@gregevgeni1864]

x = 3

[@RajeshKumar-wu7ox]

X=3 and other is imaginary