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This is an interesting derivation of Cauchy`s Schwarz inequality. However, an alternative derivation is to use vector identities such as A*B=|A|*|B|*cos(θ). What is cos(θ) in higher dimensions?!
Very cool proof, thanks!
u assumed m is greater than 0, however Cauchy's inequality is stronger than this
That's because
Right. And the inequality has many different forms in different fields.
This is an interesting derivation of Cauchy`s Schwarz inequality. However, an alternative derivation is to use vector identities such as A*B=|A|*|B|*cos(θ). What is cos(θ) in higher dimensions?!
Very cool proof, thanks!
u assumed m is greater than 0, however Cauchy's inequality is stronger than this
That's because
Right. And the inequality has many different forms in different fields.