Python | Set .discard(), .remove() & .pop() | Hackerrank Solution

#python
#hackerrank
#hackerranksolution
#set.discard()
#set.remove()
#set.pop()
#set.discard()hackerrank
#set.remove()hackerrank
#set.pop()hackerrank
Python Hackerrank Challenge Tutorial
Sets - Set .discard(), .remove() & .pop()

[@rahulagre9750]

you don't need the second for loop in new version of python.
you simply can use sum(set()) to get the total

[@krutarthpatel2823]

Code ain't working

[@preetamsingh722]

n = int(input())
s = set(map(int,input().split()))
no_of_commands = int(input())
for item in range(no_of_commands):
cmd = input().split()
if cmd[0] == "pop":
s.pop()
if cmd[0] == "remove":
s.remove(int(cmd[1]))
if cmd[0] == "discard":
s.discard(int(cmd[1]))

total = 0
for item in s:
total = total + item
print(total)
program is not working, check once

[@riteshwankhede2185]

change language from "Pypy3" to "Python3"