Probability of making 2 shots in 6 attempts | Probability and Statistics | Khan Academy
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- Опубликовано: 16 сен 2024
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Probability and statistics on Khan Academy: We dare you to go through a day in which you never consider or use probability. Did you check the weather forecast? Busted! Did you decide to go through the drive through lane vs walk in? Busted again! We are constantly creating hypotheses, making predictions, testing, and analyzing. Our lives are full of probabilities! Statistics is related to probability because much of the data we use when determining probable outcomes comes from our understanding of statistics. In these tutorials, we will cover a range of topics, some which include: independent events, dependent probability, combinatorics, hypothesis testing, descriptive statistics, random variables, probability distributions, regression, and inferential statistics. So buckle up and hop on for a wild ride. We bet you're going to be challenged AND love it!
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Sal, I just want to say you've been there for me since high school. I'm out of College and STILL use your videos. Absolutely great information in every video and I know you loved making that graph last in the previous one. Thanks!!! 😂
I've been supporting Khan Academy on a monthly basis for years because your mission and offered service is so important but I've never used any of your work personally. Recently I had a need to dig into probability and binomial distribution and happened across this video from your website. I am blown away by the quality! I've been at my problem for about 6 hours of googling probability formulas and working on my spreadsheet and had a few unanswered questions. The way you break down the binomial distribution formula in this video is wonderfully clear. You've done nothing but reinforce my commitment to continue support of your cause. Thank you!
Thank you so much for your entire RUclips channel! It's been helpful to me and all of us for so many years!
The way you have presented is really commendable. I like your all videos. Thanks for the lecture.
This video helps me understand the logic behind the binomial probability formula. Instead of memorizing the formula, I can reason the solution. Thank you very much, Khan! Here is the formula that was in my course of statistic: P(x) = n^(C_x ) p^x q^(n−x)= n!/(n−x)!x! p^x q^(n−x)
Clear explanation. Thank you.
Very helpful. Thanks!
This is explained very well. Thank you!
soothing voice and spot-on explanation !! you rock bro!!!!
my statistics final exam is in 9 hours
That's nice, mine's in 8 hours
im currently doing mine rn
All the best from the future.
How did you do
Did you pass?
Thank you for a great explanation.
I'm doing the steps to start to be able to chat about the video's content on the institution's website, but gonna try contact on RUclips (if anyone else can help with my question too, feel free: I want to understand the subjetct). I haven't experienced the whole content (or at least, one full topic) yet but can already say that would be nice to know the author of the mathematical expression that are being explained and the name of the teacher (from the academy). That help those that have the wanting or need to go deep into the theme. About the video, follow.
If "A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order. Combinations can be confused with permutations." Knowing that (n/x) refers the number of combinations, I understand that there are cases when forming binomial expressions that can't express what the (n/x) represents: number of combinations. If the academy already know that these cases exist I would like to know what happens if these cases came into matter (that's why I understand interesting know the author of the expression so I can study his/her work once the academy only work the more considered content about a subject).
For clarification, if the number of combinations is 0, the use 0! (that will be needed folling the expression logic) is not the proper way to solve the problem. I don't want to express a realistic or analogous problem because it doesn't fit my intentions. The simple mention that the number of combinations in some cases can be 0 and 0! is not 0 resumes what I want to understand if someone explored the reality between the relationship of the expression and the problem (i.e., the expression need to fit reality).
Dispite all, once in superficial experience, mentioning that I could not find an area to give general feedback, the work avaiable in the website is very good. A lot of content and, considerably, good explained.
THANK YOU!
Thanks I love you bro you saved me !!!!!!!! Lots of love!!!!!
YOU ARE AMAZING!!!
Sal, you're the best!
what statistical formula can be applied on this?
This entire video is just part of a multiple choice in our exam which is like 3 points per number 🙂
Thanks for helping me calculate Pokémon GO Shiny Chance 😃
Sal, I think it is 0.059535 you wrote 0.05935 just checking your work. Great video
He should’ve just showed the formula and that would’ve been much easier for most people. This one is more confusing than just showing the basic formula..
HAHA! Slightly less bold color. Great explanation! thank you
The P(2) = 0.059535. Khan has copied incorrectly for those that may have been confused.
I wonder if this is a correct calculation. If we change 6 attempts into 100 attempts or into 10000 attempts means the probability of scoring 2 times will keep decreasing as the attempts increase? I don't think so! Think about those scenarios that you have not taken into account: 1 score and 5 missing or all 6 attempts missings. How are those reflected in your calculation? How about the cases when you make 4 shots in 6 attempts or 5 shots in 6 attempts? Your presentation is for 6 attempts with 2 scores AND 4 missings. That AND is very important.
I don't get why the you need to multiply (0.7)^2 x (0.3)^4 by 15. Why does the 15 need to be there?
Because there are 15 different ways/orders in which two successes can occur out of the 6 attempts.
+xkoalakingx ClusterzR is right. However, he introduces that without letting us know why. He just does it. I went to look for the formula and realized that.
That's not right is it?
Awesome comment :D
I have doubt , why we multiplying those probabilities S*S*M*M*M*M ? 🤔
I think of them as this
imagine you flip a coin two times here the probability of getting exactly two heads will be 1/ 4 now the bellow 4 you can get by multiplying 2*2 here 2 is number of possibilities for one flip and think of the nominater as deriving from 1*1 here 1 is the outcome you are interested in, in one flip now to scale this scenario to Manny flips you can just multiply . Note that 1/2 is probability heads in one flip. For un even scenario like if coin is unfair you can think of the denominator as if it can have more outcomes then just two and the nominater as how Manny of those outcomes can lead to the outcome you are interested in for example if a coin has 2/3 probability of getting heads then the probability of getting two heads in two flips is 2*2/3*3 and as probability is just saying how Manny outcomes in total number outcomes satisfy the outcome you are interested in so I think this is why we multiply probability.I hope you can understand what I mean English is not my native language and if you think I am wrong somewhere feel free to correct me.