Damn, This 1hour was the best spent watching you vids. Sadly it seems you have moved on to better things... I just hope wherever you are, whatever you may be doing feel happy that you had helped hundreds of thousands of students worlwide survive math class:))
I like the AC method better where you multiply the leading coefficient of A with constant term of c, and find the factors of that number like 2x^2+7x+3 2*3=6 2 numbers that add up to 7 and multiply to 6 are 6 and 1 it becomes 2x^2+6x+1x+3 factor out 2x and 1 and you get 2x(x+3)+1(x+3) and your 2 solutions are (2x+1)(x+3) that also adds up to the middle number, and then replace the middle term with those 2 x terms, and then factor by grouping. That's another way to do it that's less "luck" based.
![Hunxho - Ball Forever [Official Video]](http://i.ytimg.com/vi/nki9ZTF9Uls/mqdefault.jpg)
Part 5 never happened 😔
Sad
Where is he now bro ??
Maybe there wasn't part 5. :(
@@thomashvnmusic Theres got to be
😔
I'M OBSSESED WITH YOUR VIDEOS MAN u literally made me excited about something I never thought I'd fully understand
im sad he didnt make a part 5
Damn, This 1hour was the best spent watching you vids. Sadly it seems you have moved on to better things... I just hope wherever you are, whatever you may be doing feel happy that you had helped hundreds of thousands of students worlwide survive math class:))
Bro I was becoming a fan of this channel and realized this is the last video 😭
I wonder why he stopped 😭
@@abm5195 😫i also loved his video
U are the best
I pass my test because of u
I need this for my final exam this really helps me a lot
Thank uuuu!!!!
your videos are amazing and has helped me and my friend out when we were stuck. great job and keep going with the videos!
Please tell me you're alive :((
Still waiting on that part 5 😔
Thanks you helped students make the best choice for factoring terrible situation in exams- 🙏🙏🙏🙏👍👍👍✊✊✊✊😄😄😄😍😍😍
It helped me alot in my exam
me2
Bro I'm fallin'in Love...
Thank you very much for bringing this video to help those who are poor at maths
Excellent video
Keep posting on more !!! 👏👏
I like the AC method better where you multiply the leading coefficient of A with constant term of c, and find the factors of that number like 2x^2+7x+3 2*3=6 2 numbers that add up to 7 and multiply to 6 are 6 and 1 it becomes 2x^2+6x+1x+3 factor out 2x and 1 and you get 2x(x+3)+1(x+3) and your 2 solutions are (2x+1)(x+3) that also adds up to the middle number, and then replace the middle term with those 2 x terms, and then factor by grouping. That's another way to do it that's less "luck" based.
Thanks ! 👍
Looking for Factoring Quadratic Expressions Pt. 5
same
Good work keep training the generation
This was the only helpful video i could find, thanks man!
You're a great saver
May God bless you 💕, you saved me
Thank you for sharing this video, I now learned something important ❤
uh...i dont see the pt.5 (crying) :(
Maybe it’s in the works, dw too much
@@nyanimation07 it's in works since 6 yearssss???!
@@ashnayawrr it must be super long and epic that's why it took super long
@@nyanimation07 What grade are you : me 8
@@Yuichiro_X_7 grade 8, why?
Unfortunately, there was *never* a Part 5.
Thank you for your videos! They have helped me tutor my son in math. Please turn on your Super Thanks so that I can give you a thank you tip.
After Factoring =(3X+2) (x+2)=0 (3X+2)=0 3X=-2 x=-2/3 (x+2)=0 x=-2 so x=-2/3 or -2 Ans
there is no value of x
Looking forward for the 5th part
Thank you for the easy way you teach me
Where is part five (5)
This helped a lot. thank you
u help me soooooo muchhhh
Fully understand ❤️❤️
thank you so much sir ♥
but where is part 5 ???? ☹️
sometime must've happened
Thank you
u are smarter than my teacher
nvm i searched u up and ur a Phd
Thank you so much!!
Now this kind of expression is difficult how can you know that they want to find the number in between as the answer after solving?
You can always check your answer by multiplying the two () to see if you get what you started with.
Where is pt 5!!!???
Similar triangles please sir
Why does my teacher doesn't teach us like this, it's my exam later! thanks to your videos I know how to answer now!
Maybe he will see the these
the what will he see?!
wow u are the best
hey wheres part 5 😨😰 its been 8 years man
where is pt 5😥
I think something happened to him
EASIEST METHOD ON EARTH
Thank you so so much
That is how to solve it.. mathematics should be make it easier to solve..
last, i appreciate your
thank.
i have a test tommorow.. Ill update you if i passed!
Factoring Quadratic Expression: 3x² + 8x + 4
3x² + 8x + 4 = (y² + 8y + 12)/3 where y = 3x
Facroring using THE Po-Shen Loh-Method: y² + 8y + 12:
SUM: (p + q) + (p - q) = 8 ⇔ p = 4
PORDUCT: (4 + q) × (4 - q) = 12 ⇒ q = 2
(p - q) = 2
(p + q) = 6
y² + 8y + 12 = (y + 2)(y + 6)
3x² + 8x + 4 = (3x + 2)(3x + 6)/3
3x² + 8x + 4 = (3x + 2)(x + 2)
■
Examples: A Different Way to Solve Quadratic Equations
Daily Challenge with Po-Shen Loh 53,8K abonnees ruclips.net/video/XKBX0r3J-9Y/видео.html
What if your coefficient term is 2a²
Where’s part five 😢
Yeah indeed t z
Can anyone help with 6X(square 2) - 7X + 12. thanks in advance.
3x^2+6x+2x+4=(3x+2)(x+2)ans
dont worry fam, He's fine, I found he's LinkedIn
This is the last vid from monkimath. Sucks, great teacher fr.
where is part 5
3x^2+6x+2x+4=(3x+2)(x+2)ans