Jensen, I think the answer in HW2, number 1 part C should either be 160 due East or (-160) m . number 5 part b) DB number 7 part e ) CB Also thank you so very much for designing such effective and efficient lesson plans and HW assignments, so that if the students do the work, their success in university is assured! Thank you for saving us time. You work hard so that we don't have to...Cheers!
I AM ONLY grade 9 student and I am learning this all . Ethiopian education is the hardest one in the world. and now I am trying hard to understand it😮💨🤔😌🤤😃. thank you for make it easy this lesson💯🙏
Having apparently forgotten how to do simple math, I got twisted around the axle with example 5, airplane flying south 300km/h wind from the west at 100km/h: ruclips.net/video/CpuYFUXe-gg/видео.html Because.... it's calculating drift angle and resultant ground speed whereas I have been working on calculating wind correction angle, used for setting true heading, and calculating resultant ground speed from that. Drift and Ground Speed w/Drift != WCA and Ground Speed w/WCA. Drift and Ground Speed w/Drift work out exactly as the video explains. However, no need to cheat knowing the 90-degree angle because using that does not lead to a generalized solution. Rather than r = sqrt (ws**2 + ts**2), go ahead and use r= sqrt (ws**2 + ts**2 - 2*ws*ts*cos (tc-wa)). Wind Correction Angle and Ground Speed w / WCA The spreadsheets I've found use the law of sines to calc WCA and cosines to get GS: WCA = sin-1 ( (WS / TS) sin (WA - TC) ) = 19.4 degrees for a true heading of 199.4 degrees (using N as 0 degrees, E as 90 degrees etc.). GS = sqrt (WS**2 + TS**2 - 2*WS*TS*cos (TC-WA+WCA)) = 282.8 km/h.
The point of tail to tail is to work without changing the direction of the vectors. Vector b is turned the other direction to make the question like an addition problem, while the tail to tail does subtraction and addition.
Jensen, I think the answer in HW2, number 1 part C should either be 160 due East or (-160) m . number 5 part b) DB number 7 part e ) CB
Also thank you so very much for designing such effective and efficient lesson plans and HW assignments, so that if the students do the work, their success in university is assured! Thank you for saving us time. You work hard so that we don't have to...Cheers!
Reviewing this for AP Physics C Mechanics because this was one of my worst topics in regular Physics. Thanks a lot, this really helped.
I AM ONLY grade 9 student and I am learning this all . Ethiopian education is the hardest one in the world. and now I am trying hard to understand it😮💨🤔😌🤤😃. thank you for make it easy this lesson💯🙏
Also from Ethiopia 9th grader🙏🙏🙏
no one cares
Congrats, hope you make it out. Its cool to hear that Ethiopia is one of the hardest educations.
@@mubassirzaman7202 i guarantee japan or china is tougher lol
A lovely lesson! Thanks.
Nicely explained, thanks
Helpful !
Thank you so much.
why is this video have 19 k when its the best ?
Having apparently forgotten how to do simple math, I got twisted around the axle with example 5, airplane flying south 300km/h wind from the west at 100km/h: ruclips.net/video/CpuYFUXe-gg/видео.html
Because.... it's calculating drift angle and resultant ground speed whereas I have been working on calculating wind correction angle, used for setting true heading, and calculating resultant ground speed from that. Drift and Ground Speed w/Drift != WCA and Ground Speed w/WCA.
Drift and Ground Speed w/Drift work out exactly as the video explains. However, no need to cheat knowing the 90-degree angle because using that does not lead to a generalized solution. Rather than r = sqrt (ws**2 + ts**2), go ahead and use r= sqrt (ws**2 + ts**2 - 2*ws*ts*cos (tc-wa)).
Wind Correction Angle and Ground Speed w / WCA
The spreadsheets I've found use the law of sines to calc WCA and cosines to get GS:
WCA = sin-1 ( (WS / TS) sin (WA - TC) ) = 19.4 degrees for a true heading of 199.4 degrees (using N as 0 degrees, E as 90 degrees etc.).
GS = sqrt (WS**2 + TS**2 - 2*WS*TS*cos (TC-WA+WCA)) = 282.8 km/h.
YASSS LOVE IT
Wait this is grade 12? In my country this is grade 9 and I am 15 and I am struggling
Congrats 🥳
what country r u ffrom?
Yep in my country this topic is grade 9 th
am like u
yep same as m3 2@@esmaelhayru4688
8:04
Wait in13:25 Tail to Tail method, why is vector b not the other way around? The way he drew it would make it a positive vector of b.
The point of tail to tail is to work without changing the direction of the vectors. Vector b is turned the other direction to make the question like an addition problem, while the tail to tail does subtraction and addition.
This is grade 12 ?! in my international school in Saudi Arabia This is grade 10 😢
Haha this is just base they dont ask these in exams
depends what level of math youre in. some students are in Calc 2 in grade 12. some are barely in alg 2