Discrete Time Convolution (Tabular Method)

Signal & System: Tabular Method of Discrete-Time Convolution
Topics discussed:
1. Tabulation method of discrete-time convolution.
2. Example of the tabular method of discrete-time convolution.
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#SignalAndSystemByNeso #Signal&System #DiscreteTimeSignal #DiscreteTimeConvolution #Convolution

[@conceptstudy5946]

y(n) = (2,-3,4,-2,1)= 4 is the value where the 0 is place

[@acn535]

What? Where's this y(n)?

[@Deepak-ip1se]

homework problem@@acn535

[@eswarabhi999]

I really thanks to neso ,because such a good staff is teaching us❤️

[@viveksingh7388]

y[n]={2,-3,4,-2,1], 4 is at n=0.

[@evan3678]

No, -3 is you just mixed up -3 and 4.

[@neeltej4123]

@@evan3678 wtf r u saying

[@maryammoghtaderi3456]

Never heard of such a straightforward method before, and WOOOW! 😍

[@vemulamanojkumar3588]

I never forgot your help my dear brother god always bless you 🤗🤗🤗🤗

[@ScientistRenzo]

Thank you so much for this video and the other video about discrete time convolution. They were great!!

[@philipthangngat2758]

Thank you so much sir, Im taking signals and systems 1 atm, wouldnt be able without ur videos, thank u again and love ur channel

[@kaviprashanna]

what do u do when the number of values for X1 and X2 are different, u can just put 0 for the the less numbered signal but how do we know if it should be on the left or right?

[@s199h]

Thank you Dr. so much 💕
Your explanation was great👌🏻

[@harishgajjar9559]

A lot simpler method than Graphical Represent method.
Thanks sir.

[@RobertoRufinojr]

Excelente aula!!!!!

[@prajapatiakshay861]

Thank you brother my doubts is clear how to find origin for different situation .❤️❤️

[@swatantrakumargupta2283]

really they done a very hard work......... thank u..

[@ey_imran]

this help me a lot. thanks

[@hazratali8563]

great work broo. i love u

[@Muhammadsleptwithayesha]

Thank you sir that was very helpful ❤

[@ersmilata6014]

thank you so much. my professor makes this as convoluted as possible in class

[@got624]

Very good content really so helpfull

[@mariammostafa7261]

thank youu !

[@user-vx3jm1vi6p]

Thank you so much 💕

[@shilpagopakumar4984]

Thanks a lot

[@leolo3540]

that's very helpful

[@loveof30]

Thanks so much

[@mixzonelive1516]

thank you sir

[@MegaBlabla45]

This method is a lifesaver. Why don't they teach this in my uni

[@inquisitiverakib5844]

great video indeed !! but a little doubt that is as convolution is performed here, don't we need to flip one sequence ???? then do the rest of the thing

[@weneedabeats9750]

This video Save my life

[@Many-ge7gv]

You have motivated me to practice and learn Digital Signal Processing, your job is very great and excellent thank you so much. Appreciate it from you. Keep up and please keep up the good work. 🙏🙏🙏😃😃😃 You really motivate me to always learn my lessons with you.

[@maheshraina3606]

Thanks

[@bltnbros122]

Thank you, and what is the procedure if one signal has 5 values and the other 4 values And dont have the information of n=0 (no arrow pointing)

[@shubhamballal2662]

If n=0 is not given or represented in given problem then how to find it

[@parthmodi5734]

Please complete analog electronics also

[@ehsanulkarimtalha9821]

should I do padding if the size is unequal?

[@alihassnain2513]

is this method only applicable only when we are given values of discrete system or we can also use this method for given equations of x[n] and h[n] ?

[@ersmilata6014]

think you have to do ztransform is you dont have discrete sequence?

[@fayaqkirmani]

Is it necessary that no of rows should be equal to no of columns

[@noonnoon6071]

Good

[@abhimannu6077]

Y[n]=(1,2,4,6,8,8) then intersection of x1[n],x2[n] is 8 then which one is X(0) is please give me reply

[@riseabovehate9476]

Then what is Matrix method ?

[@vinayakkarandikar8493]

Hello Neso academy. Is there a reference (a book/article/paper etc) which i can cite in my report (i need citation) for the above tabular method. Thank you.

[@rutweakchacha1558]

Signals and systems by A Nagoor Kani.
You can take this book as a refrence

[@s199h]

y[n]= {2,-3,4,-2,1}
↑
Is it correct, Doctor?

[@aashman_40k]

yessirrr!!!

[@nitigyajoshi4658]

yes, i got same answer

[@abhimannu6077]

Yes answer is absolutely correct

[@samuelkorvie4737]

I got the same answer

[@reetomranadutta7902]

Center will be at 4.

[@AzagloDillys-uo9sp]

Thank you very much sir.....
Please I want to ask if y(n)={-2,-1,0,3,2,1,8} and x(n)={4,-1,1,2} find the system response h(n)
How would I go about it...... thank you

[@aidanzsebenyi5286]

did you ever find out?

[@ashenafizenebe6135]

y(n) = { 2, -3, 4*, -2, 1} ,,,,,,tnx sir

This was on the FE exam for electrical engineers...

[@letsthink7664]

y[n]={2,-3,4,-2,1} n=0 at 4

[@jarnar5]

How to do when there ain't mentioned no origin for impulse inputs

[@Ssh-ml4yt]

is it tabular or matrix

[@allanraju1570]

y【n】 = { 2,-3,4,-2,1}

[@NazmulIslam-oz4re]

y(n)= (2,-3,4,-2,1). 4 is the valu of zero.

[@PrathamGupta-hl6yw]

Y[n]={2, -3, 4, -2, 1} where 4 is element when n=0;

[@swatisahu936]

Y[n]={2,-3,4,-2,1} (2

[@priyanshuranjan1986]

yes same but many of them are posting at 4 the arrow

[@shanks-tx8xu]

I thought this was matrix method

[@vivianrickyjohnson7121]

N value is taken as per our wish

[@parthaguha4705]

Its a matrix method not tabular..

[@jheelgala6353]

this isnt te tabular method. this is the matrix method

[@shaikvasim6122]

😍😍😍😍😍♥️♥️♥️♥️

[@rationalthinker9612]

Sorry but this doesn't seem to work in all case. Try the following example, it fails: x[n] = d[n] + 2d[n-1] - d[n-3] , h[n] = 2d[n+1] + 2d[n-1]. If you do the tabular method you end up with y[n] = -d[n+4] - 2d[n+3] + 2d[n+1] + 3d[n+1] - d[n-1]. That answer is incorrect, the true answer would be y[n] = 2d[n+1] + 4d[n] + 2d[n-2] + 2d[n-1] - 2d[n-4]. If I found one example of where it doesn't work, there's bound to be infinitely more.

[@alex1357in]

i got y[n] = {2, 4, 2, 2, 0, -2} with this method

[@alex1357in]

How did you get y[n] = -d[n+4] - 2d[n+3] + 2d[n+1] + 3d[n+1] - d[n-1]?

[@abhisheksinghkushwahaiiitd4215]

LoL

[@deeprelaxing7071]

y[n] = { 2, -3, 4, -2, 1 }
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