[@vovanmilos3233]

Thanks to your previous lessons I already had solved this one by myself, just checked the answer in the end.

[@lalitverma5818]

Wow nice question thnx to give solution sir ..Iam prepareing for gate cse

[@venkateshmk8824]

i am also bro But i am preparing for GATE 2022
please help me something you say bro

[@kunalsingh4584]

@@venkateshmk8824 me to for 23

[@lovishgupta1001]

@@detroit0p i m preparing for MCA 1sem at NIT-ALLAHABAD

[@khushalkumawat2254]

@@lovishgupta1001 i m preparing for MCA 1sem at NIT-TRICHY

[@ashutoshpatidar3288]

so beautifully explained

[@amitpal9479]

if we try to solve it using T and F method, then the answer will be (D)All of these
lets assume p and Q both T
1. P or ~Q = T or F = T
2.~(~P^Q) = ~(F^T) = ~F = T
3. (P and Q) or (P and Negation of Q) or (negation of P and negation of Q) = (T and T) or (T and F) or (F and F) = T or F or F= T or F = T
4. (P and Q) or (P and Negation of Q) or (negation of P and Q) = (T and T) or (T and F) or (F and T) = T or F or F= T or F = T

[@fighting_125]

I love this channel

[@OriginalElements5]

Thank God for subtitles yo

[@priyanshumangal4996]

By all options 1 and 2 are equal

[@advaithkumar5966]

actually we didn't need to even check 4th since its obvious it cant be equivalent to 1,2,3

[@odgarig8601]

Why? Can you elaborate?

[@odgarig8601]

NVM, I took another look at it, and yeah, it was obvious hehe.

[@kirekav1199]

where u have ' in the propositio ?? you make a big trouble you dont need to do that
if you know you know, but here is the people who wanna learn. why use simplicity or some s*** in the exam?

[@hashebulhasan3624]

🇧🇩❤️

[@kirekav1199]

if you write this on exam like here you never pass the exam because its not alowed to make your private math in discrete math .

[@KeshariPiyush24]

You made a mistake while copying 4th proposition. Answer should be all of them are equivalent.

[@chakradharthota1100]

No mistake bro.. sir is correct..
That is 1,2,3 are correct