Update MYSQL database table using PHP | Edit operation | PHP tutorials -57 [HINDI]

In this tutorial, we will update data of MYSQL database table using the PHP script. The update operation is known as edit operation.
Here, we create a simple and easy web application to insert data, fetch data and update data by id.
An update operation is a form of modification data.
Part 2 is here-
• Edit database data usi...
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Reference -
1. Upata MYSQL database table using PHP.
2. Insert data into the database and edit.
3. Update operation for MYSQL database.
4. PHP tutorials for beginners.
5. Language - HINDI
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[@khanturi4987]

thnx alot Sir....

[@TechnoSmarter]

Welcome

[@sececsea8936]

Hello sir, When I try to update without image. In view page image becomes blank can you help me solve this?

[@TechnoSmarter]

You have to make two conditions when you update data with or without image .
1. If image temp is empty then update other database . Do not update image .
2. If image temp is not empty then update only image and unlink old image then move new image and update name in database .
You can create both conditions when image temp is empty or when image temp is not empty.

[@sececsea8936]

@@TechnoSmarter Thank you Sir!

[@TechnoSmarter]

Welcome

[@nakummonish3264]

Delete query kaa video upload karo sir please

[@TechnoSmarter]

Watch delete query in this video tutorial
ruclips.net/video/LL_PIaoT2Ww/видео.html

[@r.s.pagore6529]

sir can make video on notification system plz

[@TechnoSmarter]

Yes, sure

[@genalpha1100]

I try to make it. but data not showing in db.

[@TechnoSmarter]

First, you have to insert then update the data.

[@sanketpanchal1582]

Notice: Undefined index: id in C:\xampp\htdocs\tecprac\updedit.php on line 3
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, bool given in C:\xampp\htdocs\tecprac\updedit.php on line 6
solve my problem

[@TechnoSmarter]

Kindly check your id in updedit.php page
Like get id from url
updedit.php?id=1
Format
page.php?id=value_of_row_id

[@satyajit2019]

source co Please

[@TechnoSmarter]

Check reference link in Description

[@easylearningwithng741]

I am not getting the output name while running for the first time..plz help sir

[@TechnoSmarter]

Kindly share your errors or eloborate more about it.

[@easylearningwithng741]

@@TechnoSmarter sir, when I run our first form,where we have given all fields of a student ( dob, mobile,name,email, Password ) ,for once it takes values, and it gets inserted in table in db, but when I m running the other php file where you are giving table tags, on running that I don't get that name like u got Mohan displayed

[@easylearningwithng741]

@@TechnoSmarter Plz help in giving how to solve this

[@TechnoSmarter]

Ok , first off all fetch data by mysqli_fetch_array using while loop .
Create correct select query then fetch by mysqli_fetch_array() function .
Then use while and echo in the table .

[@easylearningwithng741]

@@TechnoSmarterok thanks sir, but doing the exact same coding as yours ,also like if we consider our first form with all fields , in that also it takes data only once, and when I again run it, with new data it gives msg failed( means it runs the else part )