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Update MYSQL database table using PHP | Edit operation | PHP tutorials -57 [HINDI]
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- Опубликовано: 3 июн 2019
- In this tutorial, we will update data of MYSQL database table using the PHP script. The update operation is known as edit operation.
Here, we create a simple and easy web application to insert data, fetch data and update data by id.
An update operation is a form of modification data.
Part 2 is here-
• Edit database data usi...
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Reference -
1. Upata MYSQL database table using PHP.
2. Insert data into the database and edit.
3. Update operation for MYSQL database.
4. PHP tutorials for beginners.
5. Language - HINDI
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thnx alot Sir....
Welcome
Hello sir, When I try to update without image. In view page image becomes blank can you help me solve this?
You have to make two conditions when you update data with or without image .
1. If image temp is empty then update other database . Do not update image .
2. If image temp is not empty then update only image and unlink old image then move new image and update name in database .
You can create both conditions when image temp is empty or when image temp is not empty.
@@TechnoSmarter Thank you Sir!
Welcome
Delete query kaa video upload karo sir please
Watch delete query in this video tutorial
ruclips.net/video/LL_PIaoT2Ww/видео.html
sir can make video on notification system plz
Yes, sure
I try to make it. but data not showing in db.
First, you have to insert then update the data.
Notice: Undefined index: id in C:\xampp\htdocs\tecprac\updedit.php on line 3
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, bool given in C:\xampp\htdocs\tecprac\updedit.php on line 6
solve my problem
Kindly check your id in updedit.php page
Like get id from url
updedit.php?id=1
Format
page.php?id=value_of_row_id
source co Please
Check reference link in Description
I am not getting the output name while running for the first time..plz help sir
Kindly share your errors or eloborate more about it.
@@TechnoSmarter sir, when I run our first form,where we have given all fields of a student ( dob, mobile,name,email, Password ) ,for once it takes values, and it gets inserted in table in db, but when I m running the other php file where you are giving table tags, on running that I don't get that name like u got Mohan displayed
@@TechnoSmarter Plz help in giving how to solve this
Ok , first off all fetch data by mysqli_fetch_array using while loop .
Create correct select query then fetch by mysqli_fetch_array() function .
Then use while and echo in the table .
@@TechnoSmarterok thanks sir, but doing the exact same coding as yours ,also like if we consider our first form with all fields , in that also it takes data only once, and when I again run it, with new data it gives msg failed( means it runs the else part )