With the binomial probability questions, in an independent scenario are we just ignoring the given 'the first card is blue' as it doesn't effect the next 3 outcomes and therefore just calculating for the next 3 trials.
Damn watching this the night before the exam. What mistakes have i made that led me here lol Hope i do good thanks for the video last minute explanations of some kf these questions which really werent explained well to me were explained perfectly in this video and i had a lot of aha moments even 10 hours bedore the exam so Thank you
No. The question asks for "an" antiderivative. By omitting the "+c", you are giving the antiderivative where c=0. If you really wanted to, you could add "+73" or "-164" or any constant value onto the end, and you would have given "an" antiderivative. I talk explicitly about this in the video when I answer this question.
You just need to think about the geometry of this. What needs to happen for two straight lines to cross at one point? This would only happen if they have different gradients, so this would be when k is equal to anything other than -5 or -3. If you want the equations to have no solutions, then the lines need to be parallel, so same gradient but different y-ints, so k=-5.
With the binomial probability questions, in an independent scenario are we just ignoring the given 'the first card is blue' as it doesn't effect the next 3 outcomes and therefore just calculating for the next 3 trials.
Damn watching this the night before the exam.
What mistakes have i made that led me here lol
Hope i do good thanks for the video last minute explanations of some kf these questions which really werent explained well to me were explained perfectly in this video and i had a lot of aha moments even 10 hours bedore the exam so
Thank you
same
Thanks for the kind feedback, and I'm glad you found it useful. I hope Exam 1 went well for you today and best wishes for Exam 2 tomorrow.
For q2a do I need to add a plus c
No. The question asks for "an" antiderivative. By omitting the "+c", you are giving the antiderivative where c=0. If you really wanted to, you could add "+73" or "-164" or any constant value onto the end, and you would have given "an" antiderivative. I talk explicitly about this in the video when I answer this question.
how would you do Q3 if it was find K where there is one solution?
You just need to think about the geometry of this. What needs to happen for two straight lines to cross at one point? This would only happen if they have different gradients, so this would be when k is equal to anything other than -5 or -3.
If you want the equations to have no solutions, then the lines need to be parallel, so same gradient but different y-ints, so k=-5.
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