This video was BY FAR the best I have seen for titrations. Thank you so much! You covered every aspect of the topic in such detail. Really appreciate the effort you put into making such a simple yet comprehensive explanation!!
AAHH finally!! I watched so many videos and still didn't get it, but you addressed every concern and confusion I had and now it makes sense!! THANK YOU. I thought I was officially stupid.
Good question! This is because we can use the amount of acid or base added to reach equivalence to determine the amount of base or acid that must have been in the starting solution. By having the end point (point at which colour of indicator changes) and equivalence points (point at which all starting acid or base has been perfectly reacted) occur at the same time in the titration, we can use the end point as a visual indication that the equivalence point has been reached and then use this to determine amount of acid or base present at the start :) You may find the video on acid-base titrations useful as a general overview - ruclips.net/video/RiyD6syn-4s/видео.html
Great question! A weak acid against a strong base would normally give an equivalence point above pH7. For example, ethanoic acid, CH3COOH (a weak acid) and sodium hydroxide, NaOH (a strong base). At the equivalence point, all the original ethanoic acid molecules will have reacted and formed ethanoate ions, CH3COO-. However, these CH3COO- ions can form their own equilibrium with water molecules, reforming CH3COOH and releasing OH- ions. CH3COO- + H2O = CH3COOH + OH- The position of this equilibrium will be very far to the left however some OH- ions will still be present, meaning the solution will be slightly alkaline and have a pH above 7. Hope that helps :)
This video was BY FAR the best I have seen for titrations. Thank you so much! You covered every aspect of the topic in such detail. Really appreciate the effort you put into making such a simple yet comprehensive explanation!!
Thank you! Hope it helped :)
AAHH finally!! I watched so many videos and still didn't get it, but you addressed every concern and confusion I had and now it makes sense!! THANK YOU. I thought I was officially stupid.
this is the best video ive watched regarding the concept of pH and titration, thanks a lot man this really helped
Thank you!
ridiculously helpful..thanks all the way from India!:)
The best video in this topic so far. 😊
Thank you!
Love from India ♥️ best video I have ever seen on titration...
Thank you! Hope it helped :)
Very good, clarity of concepts are guaranteed.
Thank you! Glad you found it helpful :)
thank you. clutched up for my test tomorrow
Hope it went really well :)
You are really underrated...best explanation...👏
Thank you! Glad it helped :)
A very very very awesome explanation 💯
Thank you! Hope it helped :)
Thank you so much! Very clear!
Thank you! Glad it helped :)
This is beyond helpful. Thank you so much for the video!
Thank you! Glad it helped :)
Very very clear!
Thank you!
Thanks a lot for the video.
Thank you for watching - glad it helped!
Hello, thanks for this. I am wondering why do we want the end point and equivalence point to be the same.
Good question! This is because we can use the amount of acid or base added to reach equivalence to determine the amount of base or acid that must have been in the starting solution.
By having the end point (point at which colour of indicator changes) and equivalence points (point at which all starting acid or base has been perfectly reacted) occur at the same time in the titration, we can use the end point as a visual indication that the equivalence point has been reached and then use this to determine amount of acid or base present at the start :) You may find the video on acid-base titrations useful as a general overview - ruclips.net/video/RiyD6syn-4s/видео.html
Idk what to say!! Just thank u really❤❤❤
Thank you! Glad it helped :)
Good video 😊
Thank you! Hope it helped :)
Fab video! What would cause the equivalence point to be at a pH greater than 7?
Great question!
A weak acid against a strong base would normally give an equivalence point above pH7.
For example, ethanoic acid, CH3COOH (a weak acid) and sodium hydroxide, NaOH (a strong base).
At the equivalence point, all the original ethanoic acid molecules will have reacted and formed ethanoate ions, CH3COO-. However, these CH3COO- ions can form their own equilibrium with water molecules, reforming CH3COOH and releasing OH- ions.
CH3COO- + H2O = CH3COOH + OH-
The position of this equilibrium will be very far to the left however some OH- ions will still be present, meaning the solution will be slightly alkaline and have a pH above 7.
Hope that helps :)
all doubts cleared
Thx a million 🫶🏻
Glad it helped :)