Sampling distribution of sample proportion part 1 | AP Statistics | Khan Academy

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Formulas for the mean and standard deviation of a sampling distribution of sample proportions.
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[@laptv2144]

Why is no one capable of explaining this topic in a simpler way and then adding all this complex bull shit’s meaning at the end. Just the concept, seriously??

[@k1ara981]

Have u found someone that explains this in a normal way bc. I’m struggling sm with stats

[@noethy]

shouldn't the last calculation of sigma-phat being sigmaX divided by the sqrt of n?

[@eveunveils2422]

you're supposed to divide it by n

[@stephenong137]

very hard to follow... continuous pattern

[@abhishekchatterjee749]

Mu (x) = n1*p - where n1 is the number of objects in the trial (10 in this case)
if no. of trials in X = n2
Mu(p^) should be = n2* (n1 * p) / n2

[@aam7486]

Thank you so much!

[@kejianshi9196]

Only me feelling the explanation is confusing? I prefer the way Patrick teaches.

[@theadel8591]

The whole subject is a bit confusing and explaining it might be tricky.

[@AJ-et3vf]

awesome video! thank you!

[@brandiiiiine]

I'm concerned how I'm seeing orange gumballs.

[@user-fx4fs7ob3o]

Can I ask?
Does the sampling distribution of proportions normally distributed?

[@nafeulferdousshopnil]

If np(1-p) greater than or equal 10 than sample distribution of propotion normally distributed

[@docemeveritatum8550]

Thank you.

[@waddragon]

the last part of finding the mean and standard deviation for the sampling distribution of sampling proportion isn't explained well. That's why it is a dislike from me

[@j.o.s.h.o]

This video is an L for Khan academy

[@ozymandias4136]

fr

[@diceman7155]

Sorry what about this ( a random sample of 10,000 is taken from a population that is known to be 10% defective. Find the probability that less than 1,000 are found defective.

[@saijecoronel9924]

THIS TOLD ME NOTHING

[@aimtin1292]

Thanks

[@abdullahanwar1636]

.

[@markdanish7714]

hi

[@travisadam8251]

Khan maths is too hard shoot a video to make it easier XD

[@mehmetakifkoz]

i didn't like it

[@k1ng_chamberlain]

why can't you just solve the problem without explaining it and then doing an explanation