The documentation from my courses was really confusing, and even with your explanation I still think it's complicated to grasp, but after watching this video I get it now, thank you!
What I can understand from your video is that at the receiver end I require the same set of code to decode senders message. How do then the cdma mobile phone works, do caller mobile send their code to receiver mobile prior connecting the call so that sender voice can be decoded at receiver mobile?
sir you calculate only receiver 1 ....3.43 if we calculate reciver 2 means d1sq=1 in sender side . but we are gatting 1 in receiver side . but we are gatting -8/8=-1 . here I am confusing in receiver 2 portion... plase explane receiver 2 portion .. if possible please make a short video.. other wise i enjoy the whole video thank you very much sir🥰
![Code Division Multiple Access (CDMA) | Wireless Communication [English]](http://i.ytimg.com/vi/NjzbVxQOhvI/mqdefault.jpg)
Some people are born to be great teachers. your are one of them. thanks
The documentation from my courses was really confusing, and even with your explanation I still think it's complicated to grasp, but after watching this video I get it now, thank you!
Best & simplest lecture on CDMA...👍🏻
Explained in a simple way. Very easy to grasp the concept
Awesome. I actually understood what was going on. Thanks!
Some people are born to be great teachers. your are one of them. thanks (2)
no words....excellent explanation. hope, more topics in this area by the professor. thq sir
up to the point, clear, precise and simple
Thank you sir i really thankful to your team
Some people are born to be great teachers. your are one of them. thanks (3)
What I can understand from your video is that at the receiver end I require the same set of code to decode senders message. How do then the cdma mobile phone works, do caller mobile send their code to receiver mobile prior connecting the call so that sender voice can be decoded at receiver mobile?
Excellent sir😊😊😊
thankyou so much sir , your way of teaching is great sir. i understand each and every thing you said
Very useful.. Thank you so much
Thank you sir
sir you calculate only receiver 1 ....3.43 if we calculate reciver 2 means d1sq=1 in sender side . but we are gatting 1 in receiver side . but we are gatting -8/8=-1 . here I am confusing in receiver 2 portion... plase explane receiver 2 portion .. if possible please make a short video.. other wise i enjoy the whole video
thank you very much sir🥰
Won't be possible to do, CDMA Requires a minimum SNR which will not be reached
very cool
i traied understand it but i couldn't until i see this video
Excellent sir
Excellent explanation 👍
I have a question..If we use six station how we will multiplexing and demultiplexing??
Genius👍
It was a really fu.. good explain! Thanks man.
THANK YOU MY MAN
thank you
thanks alot
Well explained
thank you!
Why annotations does not appear ?
Codes should be orthogonal to each other.
Can i get this slide please @Tutorials Point (India)Ltd.
I want to start a CDMA NETWORK in company in Kenya. I have 100,000$. where do I get CDMA Equipments
Tq sir..
thanx sir////clr explntion...//
Great
Tnks lot
Gerald Forest
SERIOUSLY, I LOST WHAT I HAVE...
even JET is slower than your teaching speed
Violet Fork
thx a lot!
Lowe Junction
Feeney Plaza
Jacobs Plaza
Craig Pine
Balistreri Parkways
Berge Mountains
Queenie Causeway
😘😘
Short mehe smja karo cdm, fdm,tdm pls hota kya hai bas itna
I am sorry for the wrong comment,
😂😂😂😂
Murray Islands
Buford Port
Elda Key
c3p0
Sir aap chummi le lo 😘
Waste of data and time
Can u pls explain it hindi
Some people are born to be great teachers. your are one of them. thanks
Dusro ke comment chappega>?
Thank you sir