Demorgan's Law Proof

Поделиться
HTML-код
  • Опубликовано: 7 ноя 2024
  • If you take courses involving set theory you will see this - you will need this - all hail Demorgan and the Laws. Kidding, but this is a nice theorem and a good intro set theory proof. Enjoy!
    #demorgans
    ►BECOME A CHANNEL MEMBER
    / @brithemathguy

Комментарии • 29

  • @BriTheMathGuy
    @BriTheMathGuy  4 года назад +4

    🎓Become a Math Master With My Intro To Proofs Course! (FREE ON RUclips)
    ruclips.net/video/3czgfHULZCs/видео.html

  • @DB-nl9xw
    @DB-nl9xw 4 года назад +11

    This is amazing. Simple English for math graduate courses. Please do topology explaining.

  • @kkqum17
    @kkqum17 Год назад +4

    But doesnt the union sign mean OR operation? Why did you write AND operation over there?

    • @Hassanbinaisha
      @Hassanbinaisha 5 месяцев назад +1

      Because x is neither in A nor B or x is not in A and also not in B

  • @Cat_Sterling
    @Cat_Sterling 2 года назад +4

    But how did you go from "x € A' and x € B' " to " x € A' /\ B' "? Shouldn't we use "or" in order to get an intersection?

    • @ryanjackson0x
      @ryanjackson0x 2 года назад +1

      Intersection is AND, so these statements are equivalent.

  • @shiblyhossain6020
    @shiblyhossain6020 Год назад +1

    Fantastic,!!!!!!! Couldn't thank you enough, sir....

  • @mikelanichivende9548
    @mikelanichivende9548 Год назад

    ❤❤ you're the best teacher on earth

  • @Shivangvinci
    @Shivangvinci 4 года назад +2

    keep it up you will definitely grow because something is better than nothing

  • @roberttoltowicz9452
    @roberttoltowicz9452 4 года назад +3

    Thanks. Can you provide a brief explanation of subset vs proper subset and the notation used for each?

  • @shadykhatri5668
    @shadykhatri5668 3 года назад +1

    Briefly explained
    Thanks

  • @AsandaDube-fe8xq
    @AsandaDube-fe8xq 9 месяцев назад

    Very informative

  • @i.arcturus
    @i.arcturus 3 года назад +2

    thanks for this it's super helpful!

  • @pranayblue
    @pranayblue 3 года назад

    I came across this, and had to watch a video

  • @sreejaGhosh-b6x
    @sreejaGhosh-b6x 3 месяца назад

    There is and and there is also intersection, how this can be correct?

  • @abbasfadhil1715
    @abbasfadhil1715 4 месяца назад

    Great vid man😊😊

  • @Небовглазах-н5ы
    @Небовглазах-н5ы 3 года назад

    OMG Bri you are Brilliant...!

    • @BriTheMathGuy
      @BriTheMathGuy  3 года назад

      I appreciate it! Thanks for watching!

  • @buck7352
    @buck7352 2 года назад

    This is good

  • @mohammadamanalimyzada8332
    @mohammadamanalimyzada8332 3 года назад

    thank you
    well explained

  • @gowtime
    @gowtime 3 года назад

    Great video, I wish you could prove the other law (A intersection B)' = A' union B'
    This one is trickier for me and is hard to grasp...

    • @ryanjackson0x
      @ryanjackson0x 2 года назад

      Taking the second part first, since union is OR, it means that x lives somewhere outside A OR somewhere outside B -- this leaves out the middle. A AND B complement describes this scenario, because x could exist in A or B, but not both.

  • @Shivangvinci
    @Shivangvinci 4 года назад

    good video with great explanation insane !!!

  • @maiwandomed2579
    @maiwandomed2579 Год назад

    🎉

  • @szshyng5599
    @szshyng5599 Год назад

    This guy sounds so familiar... Khan Academy?

  • @dibyajyoti_pradhan_12
    @dibyajyoti_pradhan_12 3 года назад

    Jee main & advance IIT