IIR FILTER DESIGN BY APPROXIMATION OF DERIVATIVES |Problems And Derivation Explained

[@shubhammaurya3671]

There is small error at 8:25, it should be (1-sigma×T ), however final result is correct somehow😁

[@dailydose3051]

mam thanks so much God bless u
there is a mistake at the end while taking LCM 4*4=16 I think there should be 16 in the denominator instead of 4 and then it will become 17 in the denominator.
correct answer is:
0.23529/1-0.117z'+0.058z"

[@tarunshastri7953]

ya. i got confused for a while. then looked at ur comment and confirmed my doubt.

[@krishnarajputmotivational9034]

good explanation maa'm....thank you very much

[@anusha1056]

Good explanation ❤️

[@shivam4306]

Thank you ma'am. I understood it well!!!

[@AkshaySharma-cv2rp]

Ma'am when lcm 4 is multiplied with 4 it will be 16.

[@vasustar1948]

Good explanation madam

[@deepanshshrivastava7655]

4z^2/17z^2-2z+1 is the correct answer

[@rashwin4306]

Maam the last step is wrong maam!!. when u take lcm 4 becomes 16.

[@VivTronics]

We are taking LCM for 4 and 1 .Kindly check once again.😊.Its 4 only .

[@RamKumar-pn3od]

At 9.28 we not multiple sigma into T
But at the next page taken sigam into T taken directly

[@Codewithmahibtechvalla123]

I think soo

[@Codewithmahibtechvalla123]

@@VivTronics you chech madam there LCM is 16

[@amarnathjagatap2339]

@@Codewithmahibtechvalla123 Check

[@arpanojha6440]

at last it will be +17 mam

[@Navyasreepenukonda]

Mam formula is completely different that u wrote

[@Navyasreepenukonda]

A square -B square=(A+b)(A-b)

[@rajchinagundi7498]

ok so 1- (sigma-jomega)T==(1- sigma)-(jomegaT) huh?

[@adityapai5413]

good explanation but many mistakes