for 23mins with finding the volume of the cuboid. why did u only do one leanath instead of like 4. so shouldn't it be like 4L + 4h or 8h cause theres also like the left side.
i got stuck on the same part. X is the width of the crate, which was solved as L/18. Since the length is twice the width, the length is 2 times L/18 = 2(L/18) = 2L/18 = L/9 (simplifying)
for 23mins with finding the volume of the cuboid. why did u only do one leanath instead of like 4. so shouldn't it be like 4L + 4h or 8h cause theres also like the left side.
-27:00 how did you do step 18??? 2(L/18) = L/9???
i got stuck on the same part. X is the width of the crate, which was solved as L/18. Since the length is twice the width, the length is 2 times L/18
= 2(L/18)
= 2L/18
= L/9 (simplifying)
he explains it at 45:07
i think its the wrong timestamp
is there any other way of proving the maximum or minimum than double differentiation?
Yep compare y values after the value and before. Say if tp is at x=1 then try x at 0.9 and 1.1 and compare the yvalues
@@infinityplusone h = 0 and h = 16.66 so should I choose a middle value e.g 8?
No use 0.1 and -0.1
For the 16.66 use 16.76 and 16.56
@@infinityplusone ok thank you
It doesn’t let me tag you, it’s alright I’ll figure it out 🫶