I wold like to have one PDF material about It. It is Very good, but i am Brazilian and dont know english linguage Very well. Do you have the PDF material ? I Will translate tô portuguesh , thank you Very much.
Hello sir, can you please explain why when the capacitor discharges through the load, the current drops linearly and not exponentially? Isn`t it a resistor there?
Yes, the inductor during off-state will change the polarity. This is why vin-vo is negative in the graph of vL=f(t). When representing the voltage across a component, you choose a direction of the drop voltage arrow as a positive reference (when s1 is closed = ON-state, vL=vin; because vin>0 you will represent it above the ox-axis. In off-state vL=vin-vo is negative and it will be under ox.)
There is no limit until you start practically designing a system. You will find limitations in switching frequency, inductor sizing, core size, ESR, response time, etc. For example the FET will have to be rated to withstand the maximum output voltage. Boost topology won't do very high power without having to use impractical components.
Well done UBC. Greetings from Brazil...
Very good explanation of how boost converters work. The state-space model can be a real beast.
Excellent video. Straight to the point.
This is my first video of this channel. Great explanation. I hope see more videos with this quality in the channel. Good job!!.
¡Eres grande! Martin Ordonez! Greatings!
best explanation for boost converters , thanks
Please make more video ......your teaching mathad is really great....thanks
Excellent explanation
nice presentation
Excellent video.
Woow thank you!!!!! Good for my examen!
great video. Thank you Martin
Thanks. Very good video
Please add more videos of power electronics converters
Amazing video thank you
Nice video...Thank you
I wold like to have one PDF material about It. It is Very good, but i am Brazilian and dont know english linguage Very well. Do you have the PDF material ? I Will translate tô portuguesh , thank you Very much.
Hello sir, can you please explain why when the capacitor discharges through the load, the current drops linearly and not exponentially? Isn`t it a resistor there?
Should D (Ton) be less than T (=1/f) OR max at 50% of duty cycle?
thanks
Hi but what happens at minute 4 why it goes -ve is it bcs back emf plse explain or email thank you
Is this the only way to step up a given voltage..
Let us say 40 to 80V with a sufficient output current??
Doesn't the inductor in Off-State change the polarity? If so, then wouldn't the Voltage across the inductor be Vo - Vin ??
I agree with you on that. I think they made a mistake
Yes, the inductor during off-state will change the polarity. This is why vin-vo is negative in the graph of vL=f(t). When representing the voltage across a component, you choose a direction of the drop voltage arrow as a positive reference (when s1 is closed = ON-state, vL=vin; because vin>0 you will represent it above the ox-axis. In off-state vL=vin-vo is negative and it will be under ox.)
How do you decide the maximum output voltage. What is the limit? o
There is no limit until you start practically designing a system. You will find limitations in switching frequency, inductor sizing, core size, ESR, response time, etc. For example the FET will have to be rated to withstand the maximum output voltage. Boost topology won't do very high power without having to use impractical components.
How did you get 9A from IL=Iin? in your case square root of 36 is 6
6/12Rx12v=6A I get 6A instead of 9
never mind is squared not square root
All is good
But the explication of tig Ac wilding
The form of signal is like that explication
Really You had put more efforts 😅.
Thanks