Power Electronics - Boost Converter

Join Dr. Martin Ordonez and graduate student Matt Amyotte in a lesson on the design and analysis of the boost converter. This video introduces the topology, details the fundamental relationships between its components, and provides a design example.
Script/Visuals: Ettore Scabeni Glitz
Narration: Matt Amyotte
Production: Martin Ordonez
Audio/Video Editing: Gregor Morrison
Music: Back to the Ocean - Jesiah
Photo Credits: UBC Hover Collective, Drew Hays

[@oliverwijesooriya2067]

Excellent explanation

[@mohmedahmed-vw2us]

All is good
But the explication of tig Ac wilding
The form of signal is like that explication

[@unsearchablethings8167]

Very good explanation of how boost converters work. The state-space model can be a real beast.

[@22697166]

I wold like to have one PDF material about It. It is Very good, but i am Brazilian and dont know english linguage Very well. Do you have the PDF material ? I Will translate tô portuguesh , thank you Very much.

[@accazita]

Well done UBC. Greetings from Brazil...

[@TheDradge]

Excellent video. Straight to the point.

[@devdev8194]

Please make more video ......your teaching mathad is really great....thanks

[@kittyissu]

Hello sir, can you please explain why when the capacitor discharges through the load, the current drops linearly and not exponentially? Isn`t it a resistor there?

[@blenderNOOb69]

Should D (Ton) be less than T (=1/f) OR max at 50% of duty cycle?

[@daenenjurgen]

Woow thank you!!!!! Good for my examen!

[@reingblak]

¡Eres grande! Martin Ordonez! Greatings!

[@addisumengesha4816]

nice presentation

[@kilany10]

best explanation for boost converters , thanks

[@jimmycollege3851]

Hi but what happens at minute 4 why it goes -ve is it bcs back emf plse explain or email thank you

[@AL-kn4yx]

Doesn't the inductor in Off-State change the polarity? If so, then wouldn't the Voltage across the inductor be Vo - Vin ??

[@milosjoksimovicjogz5657]

I agree with you on that. I think they made a mistake

[@alexpascu6074]

Yes, the inductor during off-state will change the polarity. This is why vin-vo is negative in the graph of vL=f(t). When representing the voltage across a component, you choose a direction of the drop voltage arrow as a positive reference (when s1 is closed = ON-state, vL=vin; because vin>0 you will represent it above the ox-axis. In off-state vL=vin-vo is negative and it will be under ox.)

[@ershekharsolanki]

Nice video...Thank you

[@abdelhakimbahloul8188]

Is this the only way to step up a given voltage..
Let us say 40 to 80V with a sufficient output current??

[@gradientattack]

This is my first video of this channel. Great explanation. I hope see more videos with this quality in the channel. Good job!!.

[@sofianemendaci4049]

Thanks

[@harshavardhankanoj6021]

Really You had put more efforts 😅.

[@joshledford8921]

How did you get 9A from IL=Iin? in your case square root of 36 is 6
6/12Rx12v=6A I get 6A instead of 9

[@joshledford8921]

never mind is squared not square root

[@diyaazaghloul756]

Amazing video thank you

[@AmatorElektronik]

Excellent video.

[@nic_kafutafuta]

great video. Thank you Martin

[@juanarysantana]

How do you decide the maximum output voltage. What is the limit? o

[@MCSGproject]

There is no limit until you start practically designing a system. You will find limitations in switching frequency, inductor sizing, core size, ESR, response time, etc. For example the FET will have to be rated to withstand the maximum output voltage. Boost topology won't do very high power without having to use impractical components.

[@montectronyxz]

Thanks. Very good video

[@montectronyxz]

Please add more videos of power electronics converters

[@fifijojo5757]

thanks