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  • Опубликовано: 25 окт 2024

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  • @oahuhawaii2141
    @oahuhawaii2141 Месяц назад

    x⁴ = (x - 2)⁴
    Full binomial expansion and factoring:
    On both sides, drop x⁴ for cubic; 3 solutions.
    x⁴ = x⁴ - 4*x³*2 + 6*x²*4 - 4*x*8 + 16
    0 = -8*(x³ - 3*x² + 4*x - 2)
    x³ - 3*x² + 4*x - 2 = 0
    (x - 1)*(x² -2*x + 2) = 0
    x = 1, 1 ± i
    Factoring difference of squares:
    x⁴ - (x - 2)⁴ = 0
    [x² - (x - 2)²]*[x² + (x - 2)²] = 0
    [x - (x - 2)]*[x + (x - 2)]*[2*x² - 4*x + 4] = 0
    [2]*[2*x - 2]*[2]*[x² - 2*x + 2] = 0
    8*[x - 1]*[(x - 1)² + 1] = 0
    x = 1, 1 ± i
    Roots of 1:
    ((x - 2)/x)⁴ = 1 = r⁴ , where r = ±1, ±i
    1 - 2/x = r
    x = 2/(1 - r)
    = 2/0, 2/2, 2/(1 - i), 2/(1 + i)
    = ∅, 1, 1 + i, 1 - i
    x = 1, 1 ± i