Three Measures of Consumer Welfare: Compensating Variation, Equivalent Variation, Consumer Surplus
HTML-код
- Опубликовано: 21 авг 2024
- How to calculate CV, EV and change in consumer surplus from a price change.
Any channel donations are greatly appreciated: www.paypal.com...
This video explained to me what 132 slides couldn't. Thanks!
Great to hear!
Can't agree more
One of the best videos on this lesson. Super duper helpful
Thank you for the nice comment.
Noooooo! I was just examined on this 3 days ago!
Anyway great stuff, most useful uni econ tutor on the internet :)
Donated cuz u saved me for midterm. Pls keep saving me tysm!
Couldn't be any more simpler...thanks a lot.
very helpful, thank you so much
Thanks
doing gods work
well explained!!Thank you
Thank you very much!
very helpful video thank you so much
Hi sir. I used this same method for quasi-linear utility function but EV is different from CV. However, understand that EV=CV in case of quasi-linear. Please advise. Thanks.
Sir
How to find ev if u(x,y)=x+y
Income=8
Orignal price of x=4 & y=2
Then price of x falls to 1.
Hey, kindly help me with this question.
When is the equivalent variation equal to compensatory variation which is equal to
consumer surPlus?
A. When income effect is equal to zero
B. When income effect is less than one
C. When income effect is equal to substitution
D. When income effect is greater than one
I would give you the answer but you seem to be indian
Option A
A
bro, answer is literally on the video
I love uuuuuuuuu ❤ thanks
My GPA thanks you
Thank you 😌
Hi there, How do we find the utility function of society when it comes to prepare some compensation policy due to price increase of an administered price?
in equivalent variation why is the budget after price change also being taken as 10?
graphical representation would have been helpful
What if demand for X depends on Y? You have used a poor example to help many problems as your MUy differentiates to 1
true
Sir how to find EV and CV when price decreased?
In the CS equation how the square upon Px is gone?
The integral of 1/Px^2 = -1/Px. Notice if you take the derivative of -1/Px you get 1/Px^2.
Do you do online tutoring?
Sorry, I don't do that.