Vectors: Horizontal and Vertical Components
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- Опубликовано: 28 авг 2024
- This MATHguide video will demonstrate how to break down a vector into horizontal and vertical components. Find the text lesson related to this video at www.mathguide.c....
See our...
lessons on vectors: www.mathguide.com/lessons2/Vectors.html
quiz on vector components: www.mathguide.com/cgi-bin/quizmasters2/VC.cgi
quiz on vector addition: www.mathguide.com/cgi-bin/quizmasters2/VA.cgi
quiz on vector subtraction: www.mathguide.com/cgi-bin/quizmasters2/VS.cgi
quiz on vector magnitude: www.mathguide.com/cgi-bin/quizmasters2/VM.cgi
quiz on vector direction: www.mathguide.com/cgi-bin/quizmasters2/VD.cgi
Is it possible to check if my answer is correct by using the a squared plus b squared equals c squared rule? Thanks so much for your help by the way. You're literally changing lives with your good work.
You have been the first to help me actually figure out my simple mistake my breaking this down into digestible bites. I am eternally greatful, thank you.
Good video if you already know the basics of vectors and are just trying to learn about horizontal and vertical components. Thank you.
I literally learned more on this than my physics teacher. Thank you so much!!
Glad it helped.
Amazing help for anyone starting a level physics or engineering in the UK. Thanks !!
Straight forward, Like it is supposed to be. Thank you, man.
Excellent!
Thank you so much, this helped me on my physics quiz
I have a test tomorrow and this was very helpful. Thank you!
May you do exceptionally well on your test! Good luck.
@@MATHguide What are the units of the answers?
@@ericschneps302 These problems were in Newtons.
Lots of love from India ❤️
Nice explanation
Thank you!
0:21 Don't yawn. It's contagious. lol
Thank you so much I immediately subscribed after I finished the video God Bless 🙏🏾❤️
Excellent! You will not be disappointed.
Thank you so much. You really helped with my understanding
Thank you so much for this.
Thank u, thank you, thank you, thank you so much.....u really made it very easy ......at last I found answer to my one of the biggest doubt❤️❤️❤️❤️❤️
GOD BLESS YOU! thank u so much
You are very welcome!
Thanks a lot it looked difficult in class
Ayozie Michael Glad it helped!
Thanks, its alot easier once visualised!
im so glad i found this
We have nearly 300 instructional videos. Enjoy them all.
This was very helpful
Thank you very much!!
You're welcome.
at 6:52 you say that "its a whole other video" referring to when we add vectors with the horizontal and vertical components. Whats that video called?
Thank your for simplyfying this.
thanks you
"Hey I was on the highway doing 60MPH"
Cool story bro
Awesome video😍
thank you very much
cleared my big doubt thanks
GOD BLESS YOU. YOU ARE THE BESTTTTT THANKSSSSS SOO MUCHHHH
What if the question gives you polar coordinates to solve from?
Vectors are a form of polar coordinates in a sense because a vector has length and a certain angle.
Thank you
Work done = horizontal + vertical component
What does that mean ?
Work is equal to distance times the force in the same direction as the distance.
why do we take components of velocity in projectile motion?
The vertical component is affected by gravity but the horizontal component is not affected by gravity.
Thank u so much
sir can't we just directly multiply that 120 to the cos and sin by taking the 120 on left hand side instead of taking new two 120 on each side?
This video shows all of the algebra that is involved with the process. If you are proficient with algebra and need not show all the steps, you can do that so long as your instructor is okay with it.
I have a question, if we want to resolve a horizontal vector to its hypotenuse component, shouldn't we multiply to horizontal vector times sec theta to get the answer ? All the books and my friends are multiplying it with cos theta. When I tell them the hypotenuse = adjacent side X sec theta logic, they say "You are right but we are also right" What the heck ?
Okay, now I understand their logic which they wouldn't explain to me, their answer comes up from dot product which is perfectly reasonable. Now I want to find why I am wrong.
If you start with a horizontal vector, say , then its magnitude is 3. Why are you doing trigonometry?
I can't get the same answers.. what should I do?
Watch the video again.
Thank you :)) A big help :)
Donnabelle Marin Glad it helped!
what are their directions ?
The direction of the vector was given. It was 35 degrees measured counter-clockwise from the positive x-axis.
Ok wait im confused 120× 35 is not 98.30?? what am I missing?
You need to multiply 120 times the cosine of 35 degrees. Don't leave out the trigonometric function.
thanks mate
Thank youuuu
thx alot man
You are welcome. Please like the video and subscribe to the channel.
MATHguide will do :)
Where did you get the 120?
Given
Cant thank u enough!
Glad it helped!
Came in clutch
Someone please help me understand what does this prove? I know the calculations and the soh cah toa rule, I know how to calculate them and find the answer. But I don't really understand why are we doing this? What are we actually trying to find? What actually is happening here? Please someone tell me!
Given the direction and speed of a river, we may only be interested in say the vertical component of the river.
Physics test tomorrow:(
Sunday?
@@MATHguide oh, right, it was still Saturday… I’m sorry, I get confused at times…
Anyways… thanks for the video! Definitely did help :)
@@martin6742 alright. 👍
im so confused
Cguro nagiging TANGA na ako sa science🤣dko gets🤣
Walang silbi pa ka top achievers ko Kung dko gets🤣
دحجي عربي يمعود شدتمصرن
You will need to improve your confidence but you have got great potential keep it up and thanks for the lesson.
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