Hi Mrs. Havrot! Amazing videos as usual. I was curious, is there a reason you never did 8.6? My teacher never covered it in class either so I was curious if there is a reason teachers skip it.
Hi, I have a question. How would you find the cartesian equation of a plane containing the y-axis and the point (4,2,1). The answer is x-4z=0 but I'm not sure how to get that.
As with any other Cartesian equation you need to find the normal first. So you need to pick some point on the y axis (I chose (0,1,0) ). When you do the cross product with the point (4,2,1) you should get (-1,0,4). Now if you plug this A= -1, B= 0 and C =4 amd solve for D you will get D= 0. So that gives you -x +0y +4z = 0. Of course you could then simply multiply by -1 to get your answer. Got it? 😊
@@mshavrotscanadianuniversit6234 Thank you for the detailed response! I'm confused because to get the normal vector you need to do the cross product of the two direction vectors. Here you're given 2 points so you could only find one direction vector, so I'm wondering why you did the cross product of the two points to get the normal vector.
You aren’t given two points here. You are given the y axis (and any point on the yaxis will be a direction vector for the y axis) and you are given some point whose coordinates provide a second direction vector from (0,0,0)
Hi Ms Harvot :) I have a homework question that gives you the cartesian equation of a plane and they want you to get two other points on that plane. I'm not sure how to do this
Sorry for the delayed response. I believe I covered most of this lesson in a previous lesson. Also, sketching planes is not a curriculum requirement (although that doesn’t mean that your teacher can’t ask you about it) See this document www.edu.gov.on.ca/eng/curriculum/secondary/math1112currb.pdf
4 years later and styll replying to comments. Ur the best! 😊
Thank you. I take replying seriously 😊
Amazing and life saving videos, as always. Miss you absolutely saved me in grade 11 and 12!
That's wonderful to hear! I'm so happy to be here for you and to help you achieve your educational dreams and goals. xox
真的太棒了 很完美的课程 感谢您❤❤❤
感谢您的观看 : )
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Excellent online class, the best video on youtube target on what I currently learn and help me catch up during the suspension at home😂
Whoops! A grad prank gone bad?
@@mshavrotscanadianuniversit6234 depends on if I can use the time wisely before the final exam🤣
Well … get to work you slacker 😂
We people watching you online are also your students! Won't let you down
I love all my online students. They are always so respectful and complimentary❤️
Thank you madam.clear and precise explanation
Thank you for watching, commenting and subscribing. 😊
not in medical school yet. but, I too, attribute any math success to your videos.
Go all the way Javeria! I'd be so proud of you.😊
thank you mrs...you helped me alot in my maths for engineering
Good luck with your studies! Glad that I was able to help you along the way. 😊
Hi Mrs. Havrot! Amazing videos as usual. I was curious, is there a reason you never did 8.6? My teacher never covered it in class either so I was curious if there is a reason teachers skip it.
I guess sketching planes isn’t a requirement for the curriculum? Good to read it anyway!
Hi, I have a question. How would you find the cartesian equation of a plane containing the y-axis and the point (4,2,1). The answer is x-4z=0 but I'm not sure how to get that.
As with any other Cartesian equation you need to find the normal first. So you need to pick some point on the y axis (I chose (0,1,0) ). When you do the cross product with the point (4,2,1) you should get (-1,0,4). Now if you plug this A= -1, B= 0 and C =4 amd solve for D you will get D= 0. So that gives you -x +0y +4z = 0. Of course you could then simply multiply by -1 to get your answer. Got it? 😊
Remember as well that if you were asked for a point and the z axis you could use (0, 0, 1)
@@mshavrotscanadianuniversit6234 Thank you for the detailed response! I'm confused because to get the normal vector you need to do the cross product of the two direction vectors. Here you're given 2 points so you could only find one direction vector, so I'm wondering why you did the cross product of the two points to get the normal vector.
You aren’t given two points here. You are given the y axis (and any point on the yaxis will be a direction vector for the y axis) and you are given some point whose coordinates provide a second direction vector from (0,0,0)
Hi Ms Harvot :) I have a homework question that gives you the cartesian equation of a plane and they want you to get two other points on that plane. I'm not sure how to do this
Substituting the coordinates in the plane equation you should get zero if the point lies within the plane.
For instance you can set x and y = 0 and then just find a value for z that makes it zero, or set y and z = 0 ... many possibilities.
@@mshavrotscanadianuniversit6234 I will try this :) Thanks!!
Are you doing 8.6?
Sorry for the delayed response.
I believe I covered most of this lesson in a previous lesson. Also, sketching planes is not a curriculum requirement (although that doesn’t mean that your teacher can’t ask you about it)
See this document
www.edu.gov.on.ca/eng/curriculum/secondary/math1112currb.pdf
@@mshavrotscanadianuniversit6234 aww :( i find it hard to make those planes i really would've loved if u had done it