30.2 Cross Product
HTML-код
- Опубликовано: 1 июн 2017
- MIT 8.01 Classical Mechanics, Fall 2016
View the complete course: ocw.mit.edu/8-01F16
Instructor: Dr. Peter Dourmashkin
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
More courses at ocw.mit.edu
Crisp, precise and crystal clear explanation. Great animation! Thank you!
Great video. Helpful definition of CP.
PS. We have finally moved away from the blackboard! Well done ;-)
Thnanks a a lot, Pr
Great. Asinteta&bsinteta
perfect
Can someone please explain how can the length of a vector (cross product) which is a “1D line” be equal to the area which is 2D this is somehow confusing to me?
wow, he had to show right hand with left hand because video is flipped
quite tricky maneuver when explaining right hand rule :)
I don't get it. Is this intended for high school or college?
I mean there's no intuitional and logical basis to the concept. Also, if it's a college course, what's the need when you have uploaded Walter Levin's lectures?
Sir,why we use sin theta in vector product
to get the perpendicular height. area of //gm is twice the area of the triangle
@@aditya_saha thankyou bro
Can u tell me why cross product is the area of the parallelogram? What does the area signify?
Hi sir. I just want to ask a question. Why is the height equals to b×sin(angle) not b×a. In another way why is the area of parallelogram doesn't equal to a×b
it came back to how we calculate the area of a parallelogram. The area is the horizontal component of it times the vertical component. B is the horizontal component, but A is not the vertical component. To find the vertical component, we use trigonometry thus sin came to existence.
You taught WRONG! Their is no such thing as the left hand rule. If you do a cross b the orthogonal vector is always pointing up.