Laplace domain - tutorial 5: Inverse Laplace transform

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  • Опубликовано: 7 ноя 2024

Комментарии • 19

  • @ozzyfromspace
    @ozzyfromspace 4 года назад +4

    I love how you broke the rational expressions into simple partial fractions. Definitely a computational highlight. And it’s not a trick! It makes perfect sense 😊😊🙌🏽🎊

    • @Kuchdelan
      @Kuchdelan  4 года назад

      Glad it was helpful!

  • @JustMe-lg4hq
    @JustMe-lg4hq 4 года назад

    the best as always

  • @TheSabri306
    @TheSabri306 5 лет назад +1

    Superb Sir..!!

  • @Lestibournes
    @Lestibournes 5 лет назад

    Example 8 (at 21:36) really tricked me. I was so used to breaking down and simplifying the fraction that I tried to do it again. It's really clever to put that example there to remind us to check the tables first before deciding what to do.

  • @mortezakhoshbin
    @mortezakhoshbin 5 лет назад +1

    thank u iman i am learning fr om you new things😍😍😍

    • @Kuchdelan
      @Kuchdelan  5 лет назад

      Thank you very much, Morteza!

  • @shohrekariminejhad3813
    @shohrekariminejhad3813 5 лет назад +1

    Thank you so much Iman! Your videos really help to gain a deep understanding of signal analysis. I wish you could also make few videos on Z-transformation.

    • @Kuchdelan
      @Kuchdelan  5 лет назад +2

      Thank you very much Shohre. I am very happy to hear my videos were useful for you. My next course is most likely DSP and I will cover all different transformations (including Z transformation). Cheers!

  • @surendra_c
    @surendra_c 5 лет назад +1

    thank you very very much for creating this channel to teach signal processing,YOU ARE AMAZING.....😍😍
    please dont forget to like my comment....and see you sir ....in the next video..... 🎵🎼🎶🎸

    • @Kuchdelan
      @Kuchdelan  5 лет назад +1

      Lol, your comment gave me a good laugh and made my day ;) Thank you!

  • @Lestibournes
    @Lestibournes 5 лет назад +1

    In the third example, why not separate the fraction into 2 fractions based on multiplication? the result would be convolution instead of subtraction.

    • @Kuchdelan
      @Kuchdelan  5 лет назад +1

      Yes, that also works but keep in mind that finding convolution in the time domain is really time consuming.

  • @Lestibournes
    @Lestibournes 5 лет назад

    Example 8 (at 21:36) really tricked me. I was so used to breaking down and simplifying the fraction that I tried to do it again. It's really clever to put that example there to remind us to check the tables first before deciding what to do.

  • @Lestibournes
    @Lestibournes 5 лет назад +1

    Example 8 (at 21:36) really tricked me. I was so used to breaking down and simplifying the fraction that I tried to do it again. It's really clever to put that example there to remind us to check the tables first before deciding what to do.

    • @Kuchdelan
      @Kuchdelan  5 лет назад +1

      I really like the fact that you tried hard before using the table! This is the key to learning. Best!

    • @Lestibournes
      @Lestibournes 5 лет назад

      @@Kuchdelan I've been doing it myself in Frequency Domain 7, Laplace Domain 4, and Laplace Domain 5. It's the only way to survive so many examples without having my brain melt, plus it's good to practice. Cheers!