Problem Solved: Chemical Pounds Per Day Formula - Distribution System Math
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- Опубликовано: 1 авг 2024
- American Water College Presents - Problem Solved!
This is the solution to a typical "pounds per day" problem, found on state certification exams. It is also an important calculation for distribution system operators.
americanwatercollege.org
225 gpm × 1440 min/day =324,000 ÷ 1,000,000= 0.324 MGD
I think this video would be much improved if you took the time to explain where the formula comes from. Gallons per minute can be converted to gallon per day by multiply by the number of minutes in a day, 1440. If a student understands that, this becomes much clearer. Otherwise it's just "memorize a formula" and a bunch of random seemingly disconnected numbers.
thank you
You are so right. Other students are confuse when their instructors rants without explaining sources of their formula, conversions. Ultimately those students loses interest in the subject matter.
It's all about unit conversion. 225* 1440= 324000 gpd
2mg/L = (2÷1000)g/L = (2÷1000)/(1000) g/g.
Since 1 liter= 1000 grams.
Then
From a gallon of water to pounds of water, multiply by 8,34.
Now 324000 *( 2 ÷1000000)* 8,34= 5,4 lb/d
How did you get the 694.4 gpm? That's where I'm lost and confused at.
Love the videos ....Question,why not use the Davidson pie chart for this problem
?
Thanks Mr
This problem is for a well. Wells usually do not run for 24 hours every day, which this problem implies (that is where the 694.4 number comes in). They should add another video to show you how many lbs per day with a 5, 8, 12 hour well runtime (whatever is more realistic for a water system well)
Thank you for your video
If I have reuse wastewater transmission via pipe line distance 400 km
How much chlorine should be dosing per day?
The daily water transport 115,000 m3/day
How do the units cross out so that lbs/day is equal to the multiplication of MGD, mg/L, and lbs/gal?? I don't understand how the formula works
Can you do more problems based on a d-1 water distribution test? Thanks I enjoy your videos very well organized an Ramsay to understand
LOL that slide through! lmao!!!!
I’m wondering why the mg/l isn’t converted to gallons when doing the problem? I thought all units had to be the same type when doing these problems
This also only applies if you're working with Gas Chlorine, which is 100% pure.
If you were working with solid chlorine, it'll be 65% pure
If you were working with liquid chlorine, it'll be 12.5% pure
Look, I'm a steam plant engineering guy looking at a wastewater job. We don't think in MGD, but ... when in Rome. My concern is that he never gets rid of the "mg/L." Here's what I did ...
225 gal/min * 1440 min/day * 2 mg/L * 3.789 L/gal * 1 Kg/1000000 gm * 2.2 lb/gal
Where's the "PFM" in his unit conversions?
Mike Goodman
M (of Million gallons per day) cancelled out mg/l.
Millions cancels out milligrams per liter(mg/l)
Hi, Why we are multiplying by 8.34?
8.34 is the weight in pounds of 1 gallon of water
@@SerenityRick he should have stated that too.
How did he get 694.4 GPM?
same as the million gallons per day do the math and divide by how mins in a day
GPM X 1440 = MGD
+tafarrier Wouldn't that equal GPD instead of Millions of GPD?
yes it's GPD.
when you do dosage problems your looking for MGD.
100,000 GPD = .1 MGD
I understand it better by multiplying it by 1440. However, if one doesn’t desire to work with big numbers the video is a great example. 👍
I totally lost you when the 225 gpm converts to 694.? ? ? ? ?
What is 8,34?
The weight of one gallon of water in lbs. I noticed he didn't state that bit of info during the lesson.
the weight of water per gallon
If you're in WASTEWATER...you should know where that formula comes from