I've seen this formula in secondary school when we studied logarithms but I never knew that it will be there in physics' second year somewhere with the vibrant strings... Thank you so much for the service, sir.
Nice trick to think of the distance between units on a log scale. The geometric mean idea just comes from taking the halfway point between log values like this: log(x) = [log(2) +log(3)]/2. Doing the math, you get x = sqrt(2*3), as used in this video. You can get any value along a log scale by doing regular linear interpolation, while logging any value that should show up on that scale. A more general formula might be x*=x1(x2/x1)^n, where x* is the actual value at a fraction of n between x1 and x2 (n is the fraction you visually see on the log scale, so like 0.5 in this video).
Thank you so much for providing a calculation that is actually universally useful, instead of trick that only works sometimes. Your comment is far more valuable than the posted video.
@@nicolejacobs2052 Thank you! I'm glad this comment was useful. I think the video is beneficial for those who want just a quick rule of thumb when looking at log plots, but it leaves out the math details behind why it works and how to interpret other increments.
Thanks... It was very helpful. Before watching this, i also used to thought that the middle of two tickmark is the middle value of them... Now i can find out correctly
So i'm 3 minutes into this video and then i thought.... Jean-Claude Van Damme is teaching me about log scales... i can't get the image out of my head now!
Quick note, those are not equalities, they are approximations, at the last step when you provide the value of the square root in decimals. Very useful video overall, many thanks.
A derivation would come from just logging the values used to linearly interpolate along the scale. So log(x) = [log(2) +log(3)]/2. Doing the math, you get x = sqrt(2*3).
@@patbassal That's true, but I found that a couple more steps makes it more intuitive. The distance from 1 to 2 is log(2), and from 1 to 3 is log(3). The distance to the halfway point in between those two is then [log(3) - log(2)]/2 + log(2) (The first term being the distance from 2 to the halfway point, and the second term being the distance from 1 to 2. Adding those two, you get the full distance to the halfway point.) This simplifies to [log(2) +log(3)]/2. Then you just take 10 to this number, and you get: sqrt(3*2) = sqrt(6). This can be generalized to any two numbers m & n (where n
@@1900maniac Yes, great explanation. I skipped explaining that step, but I completely agree with the adding of log(n), which is necessary for proper interpolation. I am curious about your thoughts of another comment I posted 4 months ago. I posted an equation that could be generally used for any distance (not just halfway) between m and n.
What this video showed for in 2 minutes made me understood what I couldn't in a lecture for 2 hours...
Exactly 🤷🏻♀️🤦🏻♀️
Thanks man, never learned this when we had logs. Now at university I needed to read a logscale and I just couldn't get my head around it. Thanks!
By 1:30 I already learned more than 4 articles and 2 vídeos i watched before. So simple. Thank you!
Great! Thanks for the comment!
Thanks a million! This video has made everything so clear to me!
I've seen this formula in secondary school when we studied logarithms but I never knew that it will be there in physics' second year somewhere with the vibrant strings... Thank you so much for the service, sir.
Very nice explanation and so nice to hear etcetera pronounced correctly!
THANK YOU FOR HELPING ME WITH MY PHYSICS PAPER I LOVE YOU
Great lecture..... Love from 🇮🇳..... U just solved my problem
Kakali Roy Thank you! Please share!
3.16 is should be at the middle because u said we cant look this graph linearly
Right! - midway between 1 and 10
Thanks so much for posting! Clear, concise, very helpful. Much appreciated!
Mid point between 2 tick marks x & y on logarithmic scale is called "geometric mean" and to calculate it you take square root of (x × y)
I really enjoyed this video. Reminded me of past days.
This video is great! But how do I plot a point if I know the value? If I want to find where 13 is on the graph how do I find it?
Nice trick to think of the distance between units on a log scale. The geometric mean idea just comes from taking the halfway point between log values like this: log(x) = [log(2) +log(3)]/2. Doing the math, you get x = sqrt(2*3), as used in this video. You can get any value along a log scale by doing regular linear interpolation, while logging any value that should show up on that scale. A more general formula might be x*=x1(x2/x1)^n, where x* is the actual value at a fraction of n between x1 and x2 (n is the fraction you visually see on the log scale, so like 0.5 in this video).
Thank you so much for providing a calculation that is actually universally useful, instead of trick that only works sometimes. Your comment is far more valuable than the posted video.
@@nicolejacobs2052 Thank you! I'm glad this comment was useful. I think the video is beneficial for those who want just a quick rule of thumb when looking at log plots, but it leaves out the math details behind why it works and how to interpret other increments.
am i a genius or what? figured that on my own. delving into narcissism, forgive me fellow students xD
You are my today hero! Thank you much. So simple and understandable compare yo others video in RUclips :)
Thank you so much! This was very helpful.
Simple and easy.. Love it!
Very informative. thank you
Thanks... It was very helpful. Before watching this, i also used to thought that the middle of two tickmark is the middle value of them... Now i can find out correctly
how to find a random point on logarithmic x axis? we have used midpoint technique but what we gonna do now?
So i'm 3 minutes into this video and then i thought.... Jean-Claude Van Damme is teaching me about log scales... i can't get the image out of my head now!
So useful and easy to remember! Thank you so much!
Thank you very much Sir...It really helped a lot 👍👍👍
Straight to the point.
As a Grade 5/Year 6 maths teacher, who is interested in the use of log scales in financial analysis, I thought this was an excellent explanation.
John Roycroft thank you!
Quick note, those are not equalities, they are approximations, at the last step when you provide the value of the square root in decimals. Very useful video overall, many thanks.
Very nice clear explanation that is easy to understand
Brilliant explanation! Thank you!
Very Helpful! Thank You!
right to the point. Thank you.
Great video! Thanks! This Geometric Mean Equation. How is it derived? What does the geometric mean have to do with log?
A derivation would come from just logging the values used to linearly interpolate along the scale. So log(x) = [log(2) +log(3)]/2. Doing the math, you get x = sqrt(2*3).
@@patbassal That's true, but I found that a couple more steps makes it more intuitive.
The distance from 1 to 2 is log(2), and from 1 to 3 is log(3).
The distance to the halfway point in between those two is then [log(3) - log(2)]/2 + log(2)
(The first term being the distance from 2 to the halfway point, and the second term being the distance from 1 to 2. Adding those two, you get the full distance to the halfway point.)
This simplifies to [log(2) +log(3)]/2. Then you just take 10 to this number, and you get: sqrt(3*2) = sqrt(6).
This can be generalized to any two numbers m & n (where n
@@1900maniac Yes, great explanation. I skipped explaining that step, but I completely agree with the adding of log(n), which is necessary for proper interpolation. I am curious about your thoughts of another comment I posted 4 months ago. I posted an equation that could be generally used for any distance (not just halfway) between m and n.
I can finally say I love log scale. I didn't understand it for many years.
Very helpful! Thank you!
Thank you so much sir 🥰🥰
Great video, I understand it perfectly now!
Thank you! from Korea
Wow at age 60 learning the most clear explanation ever !
Wowwwwwww, that is superb....
Perfect! Thank you.
Your a life saver
Being frustrated at around 11:30 PM, but so happy this video FINALLY explained this to me! Thanks!
Thanks million times i could read before but had some confusion, and you cleared that confusion now
Thanks Professor ❤
Greaat video
Great explaining
Thank you so much..
thank you so much
nice explaning thankyou
This was so easy to understand, thank you for simplifying it so well.
Great job - thx for sharing.
Thank you sir
This was an outstanding video demonstration. Thank you professor.
was really helpful..Thank you so much
Thank you thank you
Thanks a lot! It becomes more clear difference between linear scale and normal scale;
good shit bro,, thanks
Nooo! He is my Professor at SDSU.
@@kishorekumarshivaram4971 oh cool, what are you studying?
Nice explanation. thanks for the video.
🎉
A great job friend!! Helped me a lot to read stats! Ty!
Thank you so much.You gave me homework to send.
etsetera
That music in the end gives me playboi carti vibes (thanks for the vid tho!)
💖💖💖💖💖
Very nice! Thank you very much. This is missing part from mine and the mathematics books.
Thanks
How can I pick a point for the exact value that I want? like 1.5
thank you sooooooo much !!!!!
good video, explanation very good.
Very good video
refresher dayumm
middle point between 1 and 10 should be 5 -_- . arrrr
Wow, easy when you know. Thanks so much!
Hi~~ i’m korean. Your vedio helped me a lot !!
Where lies the zero value and the negative values in the log scale?
Thanku Sir
nice sir
Thank you!
Thank you!
I think it's wrong 😢😢
Love from India
Nice and helpful explanation buddy
Thank you! This meant a lot for mw
I love u
grt sir
THANKS INTERESTING AND DESCRIPTIVE
Very nice advaice,thanks
can i share this video to my student
Thank you very much ❤❤❤
directed by david lynch
I just want to say THANK YOU SO MUCH THIS ACTUALLY HELPED.... I have been trying to understand this for wayyyy too long
I still don't get it.
You really have saved me
Thank you so much.
Where are you from?
Thanks man 👍🏿
you are a LEGEND
Thank you sir
Thank you alot
Great video, really helpful and to the point.
Little ignorant things like these, can become so troublesome for lecturers. Thanks for sharing your knowledge.