But 2^16 = 65,536, Why do we say the maximum addressable addresses are 64,000? I assumed if we had a word, which contains 4bytes. If i divide 64,000 by 32 bits, somewhere i start getting decimal values. I would assume i get whole number all the way through
Harry Porter and the Fully Associative Cache
Bravissimo. L'unico video su RUclips che ha spiegato in maniera DECENTE questa cosa.
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you're a legend...thanks lot
good videos!
Thank you, sir.
But 2^16 = 65,536, Why do we say the maximum addressable addresses are 64,000? I assumed if we had a word, which contains 4bytes. If i divide 64,000 by 32 bits, somewhere i start getting decimal values. I would assume i get whole number all the way through
because 65,536 *is* the max.
You are correct, 6400 is based on an approximation that 2^10 = 1024 which is pretty close to 1000
Just to be clear there are 26 bits in the tag meaning 2^26 combinations of keys correct?
Yes, for every position you will have either 0 or 1. Hence, 2*2*2... = 2^26.
Thanks a lot !