Shear and Moment Diagrams with Uniform Distributed Load

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  • Опубликовано: 15 сен 2024
  • In this example, we calculate the shear and moment diagram for a beam under a uniform distributed load (F=-1.5 N/m). We can see that the shear diagram is the integral of the uniform distributed load (V=-1.5x+6 N), and the moment diagram is the integral of the shear diagram (M=-1.5 x^2/2+6x N*m).
    For more complicated loadings, see this follow up video: • Shear and Moment Diagr...

Комментарии • 15

  • @ashishtiwari1912
    @ashishtiwari1912 7 лет назад

    Great video....the explanation was better than most videos that I went through..

  • @Schlog1
    @Schlog1 5 лет назад +3

    Great video, but there's a small error.
    At 5:10 when you rewrite an equation to isolate M at cut C, you fail to change the sign of the term -6x when you move it to the RHS of the equation.
    You correct it later when you define the M at a cut C as the integral of V, but the error is still there at 6:31 when you write the correct version.
    They're both on screen at the same time. It's cute, but it's wrong.

  • @slatoraplin4694
    @slatoraplin4694 9 лет назад +1

    I really like the depth of the analysis in the screencast, but can you go over more complex examples?

    • @mrsoltys
      @mrsoltys 9 лет назад

      Sure. Do you have anything in mind?

  • @asimmessi876
    @asimmessi876 4 года назад

    Your perfect! Thank you soo much .

  • @Frank_The_Tank22
    @Frank_The_Tank22 7 лет назад +1

    Excellent video, thanks for your time. Can you do one with a load that isn't uniform?

    • @DrSoltysScreencasts
      @DrSoltysScreencasts  7 лет назад +1

      Sure, What kind of loading do you have in Mind?

    • @Frank_The_Tank22
      @Frank_The_Tank22 7 лет назад

      Dr Soltys Screencasts maybe with a couple of different forces at different points, as well as a distributed load with a positive slope w(x)? (I mean looks like a triangle load)

    • @DrSoltysScreencasts
      @DrSoltysScreencasts  7 лет назад +1

      Here's a video with combined loading
      ruclips.net/video/5oFqaRhFr1s/видео.html

  • @FaReS4201
    @FaReS4201 8 лет назад

    Thank you so much :)

  • @cpinchin
    @cpinchin 7 лет назад

    thanks

  • @yl3485
    @yl3485 7 лет назад

    Sorry, may I ask some questions? In 5:21, should it be Mc= -(1.5x^2)/2+6x?
    Also, i want to ask that why we don't calculate the moment by using shear force?
    I think shear force=resultant force(6-1.5x) and we can use it to calculate same answer
    If we use shear force to calculate the bending moment, the (Mc) should be equal to 6x-1.5x^2
    I know Mc= -(1.5x^2)/2+6x is correct answer, but why these two answer is not equal?

    • @yl3485
      @yl3485 7 лет назад

      I just study this subject so i am confusing to above questions.

    • @yl3485
      @yl3485 7 лет назад

      Oh, i got it. If we use shear force to calculate bending moment, it should be (6-1.5x)x+1.5x^2/2=6x-(1.5x^2/2), right?

  • @conorbulloch8432
    @conorbulloch8432 3 года назад

    Makes no sense. Thanks