Really helpful video. With Parsecs that have a value between 1 and 10, or have a series of numbers (eg 1.2345), you'd still multiply by the log function to get the value needed to multiply by 5? I haven't used equations of a broader sense for quite a while but am aware of the conceptual value they bring once understood. Thanks again J
Thank you very much I am studying GCSE astronomy and I found it very helpful.
Really helpful video. With Parsecs that have a value between 1 and 10, or have a series of numbers (eg 1.2345), you'd still multiply by the log function to get the value needed to multiply by 5? I haven't used equations of a broader sense for quite a while but am aware of the conceptual value they bring once understood. Thanks again J
hi Justin
you would need to use the log button on your calculator
thank you! good and simple explanation.
explained this whole concept very clearly thanks!
VERY thorough; thank you so much!
This was helpful, but what if the distance of a star is 20,000 parsecs from us, or 573,786 parsecs?
you have a log10 button on your calculator
If there is any confusion- yes the absolute magnitude is -15.5!!!
there was a minus sign on the video ...
the absolute value of -15.5?
15.5 or negative 15.5?
negative 15.5
I'm 13 yrs old and I'm studing astronomy thanks to explain me very clearly.