Thank you so much for illuminating how to do combined rate problems! I found these so confusing, but now I think I have a solid understanding and systematic approach. Thank you.
Hi Jeff, How would I use the formula you've mentioned with this problem? Working together, 7 identical pumps can empty a pool in 6 hours. How many hours will it take 4 pumps to empty the same pool?
Hello Jeff, How can we apply the same above formula for the 700 + problem below, Lindsay can paint 1/x of a certain room in 20 minutes.what fraction of the same room can Joseph paint in 20 mins. if the two of them can paint the room in an hour, working together at their respective rates?
lindsays rate=1/x by 1/3=3/x.rate of joseph can be calculated with the above formula to be 3/(3-x).now since we are asked for 20 min it would be 1/3-x. plz let me know if its right or wrong
Let assume x any value say 6 G paints 1/6 of room =20min G paints 1 room =120min G+J=60 min(last line) Taking LCM of both We get efficiency of B=1 To get fraction of room painted by J;take ratio.i.e.20/120=1/6.. Use options and use x as 6. If any option equals 1/6 that will be the answer.. Hope it will help you.
Let 1/x be the fraction of the room that Lindsay can paint in 20 minutes. Let 1/y be the fraction of the room that Joseph can paint in 20 minutes. Lindsay's Rate= 1/(20x) rooms per minute Joseph's Rate= 1/(20y) rooms per minute Then from the Generic Equation we can write: 60/(20x) + 60/(20y) = 1 3/x + 3/y = 1 solving for 1/y we get 1/y= 1/3 - 1/x=(x-3)/(3x)
Thank you so much for illuminating how to do combined rate problems! I found these so confusing, but now I think I have a solid understanding and systematic approach. Thank you.
I find using the combined work formula: T = A.B / A+B is easier.
Imagine using a second account to reply to your first comment
Yep, that's what I do.
hey great job jefff
You have been doing great
Job
Please further upload other concepts videos
Just did a video on this myself, on my Quant playlist.
Thanks for sharing this Jeff.... It has cleared all of my doubts.
Hey, very clear examples! Please do more vids!!! :)
I love wrokig with charts. They just make sense to me
great work jeff ! your work is seriously underrated
Thank you so much Jeff 🙏🏽
i wish you posted more often
wow, thanks for the explanation! your method is much faster :)
excellent explanation. Thank you!
Sir..plz give more tough questions ..Thanks for this video..
Thanks !
Thanks ..It help me a lot.
Very nice videos well done.. do u provide online classes?
Thanks alot jeff :)
Hi Jeff,
How would I use the formula you've mentioned with this problem?
Working together, 7 identical pumps can empty a pool in 6 hours. How many hours will it take 4 pumps to empty the same pool?
Each pump's rate = 1/42. 4 pumps will take 42/4 or 10.5 hours
many thanks
Thank you
Thanks alot :)
Hello Jeff,
How can we apply the same above formula for the 700 + problem below, Lindsay can paint 1/x of a certain room in 20 minutes.what fraction of the same room can Joseph paint in 20 mins. if the two of them can paint the room in an hour, working together at their respective rates?
lindsays rate=1/x by 1/3=3/x.rate of joseph can be calculated with the above formula to be 3/(3-x).now since we are asked for 20 min it would be 1/3-x. plz let me know if its right or wrong
Let assume x any value say 6
G paints 1/6 of room =20min
G paints 1 room =120min
G+J=60 min(last line)
Taking LCM of both
We get efficiency of B=1
To get fraction of room painted by J;take ratio.i.e.20/120=1/6..
Use options and use x as 6.
If any option equals 1/6 that will be the answer..
Hope it will help you.
Let 1/x be the fraction of the room that Lindsay can paint in 20 minutes.
Let 1/y be the fraction of the room that Joseph can paint in 20 minutes.
Lindsay's Rate= 1/(20x) rooms per minute
Joseph's Rate= 1/(20y) rooms per minute
Then from the Generic Equation we can write:
60/(20x) + 60/(20y) = 1
3/x + 3/y = 1
solving for 1/y we get 1/y= 1/3 - 1/x=(x-3)/(3x)
HARD