Circuits 1 Problems and Solutions: Equivalent Resistance (Part 5)

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  • Опубликовано: 7 ноя 2024

Комментарии • 5

  • @furkanyasinaydogan6069
    @furkanyasinaydogan6069 3 года назад +1

    hi.I am from turkey.I watch your videos.
    it was very useful to me.May ı ask you a question?
    I'm making a circuit in a microcap but no lamp in app.
    So I thought I could put resistor instead of lamp.
    the lamp must be 220 volts and 100 watts.How can I adapt these values ​​to the resistance?
    I would be glad if you answer :)

    • @pauljstar
      @pauljstar  3 года назад +1

      What is the lamp model type? It's helpful to know what kind of load you're using (examples are LED single, LED array, incandescent, halogen, fluorescent). But in general, power is equal to voltage multiplied by current (p = vi) or square voltage divided by resistance (p = v^2 / r)...so square voltage divided by power should yield a resistance you might be interested in (220 v * 220 v / 100 w = 484 ohm at operating point). Note 1: 220 V is a root-mean-square averaging method, so resistance also carries this same average understanding. Note 2: Incandescent bulbs have variable resistance proportional to temperature.

  • @mygreatbigfoot1679
    @mygreatbigfoot1679 3 года назад +1

    I was going to watch but instead of being kind and using type option you selected spider instead.