Good video I only have a question if someone could answer me I would appreciate it, Why in the first round the dn bit did not turn on and cut the count until the toggle was turned off?
The XIO Timer.DN is essentially what resets the timer. Without that bit, the timer would never reset back to zero if the person did not let go of the push button
Hello Klette, I'm wondering why use the .en and .dn latching circuit with the .tt instead of just taking the .en directly to the output rung, is this possibly only momentary? Or why not use a tof.dn directly to the output?
Great question. The toggle bit is representing a momentary pushbutton. The .DN needs to be normally closed so the memory will drop out and the timer can be started again. The .DN bit changes so fast we cannot normally see it on the screen. does this answer your question?
@@KletteTech At exactly 3:51 is it possible for the DN bit to energize while the Toggle_11 is closed? I'm asking because I want to start AND stop the TON with a single bit.
Perhaps you can help me predict the following rung (from left to right): ---] [--------------------TON--------------] [-------------------( )--- input timer time.DN output I inherited a program which has several rungs like this, but I'm not sure of the behavior. Am I correct that this will act as a time delay for the output? And the timer will only reset when the input opens?
It will delay the output turning on. It will reset when the input goes false. I have never seen it programmed like that. But it should work as you stated.
You're a very good teacher. Thanks for the videos, I appreciate them.
Glad you like them!
Love your 5000 series! I've watched them all! Hope you put up more!
Thanks. Hopefully I will be putting more PLC videos up soon.
Wow this explanation is so clear! Thank you dude!
Glad it helped!
Far better information than that other guy who babbles endlessly with his skull fracture
Yea you’re the goat
You are the BEST 🎉
thanks
Helpful video, thanks. Small error at 1:15 -- multiplier is 0.001.
Good video I only have a question if someone could answer me I would appreciate it, Why in the first round the dn bit did not turn on and cut the count until the toggle was turned off?
The XIO Timer.DN is essentially what resets the timer. Without that bit, the timer would never reset back to zero if the person did not let go of the push button
Hello Klette, I'm wondering why use the .en and .dn latching circuit with the .tt instead of just taking the .en directly to the output rung, is this possibly only momentary? Or why not use a tof.dn directly to the output?
Yes. The tt would only work if the TON is enabled. It is a small difference but a big one.
Dear Sir, How to program Ramp up and ramp down in PLC in order to run drive from setting in m/m. ? (Ramp function gen)
Thats a drive parameter. No need to add it to PLC
why the timer1.DN is closed with a toggled bit = opened? I haven't seen the state change? why not choose an open contact to close during count?
Great question. The toggle bit is representing a momentary pushbutton. The .DN needs to be normally closed so the memory will drop out and the timer can be started again. The .DN bit changes so fast we cannot normally see it on the screen. does this answer your question?
@@KletteTech At exactly 3:51 is it possible for the DN bit to energize while the Toggle_11 is closed? I'm asking because I want to start AND stop the TON with a single bit.
Perhaps you can help me predict the following rung (from left to right):
---] [--------------------TON--------------] [-------------------( )---
input timer time.DN output
I inherited a program which has several rungs like this, but I'm not sure of the behavior.
Am I correct that this will act as a time delay for the output? And the timer will only reset when the input opens?
It will delay the output turning on. It will reset when the input goes false. I have never seen it programmed like that. But it should work as you stated.
Me salvou.
De nada