Lec 7: Variational Calculus, Lagrange's Equations

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  • Опубликовано: 22 дек 2024

Комментарии • 25

  • @feynmath
    @feynmath 3 года назад +2

    The music at the starting of every lecture is so soothing.
    Love it.

  • @rahmatnawisiregar6263
    @rahmatnawisiregar6263 4 года назад +8

    Ahhh... it is absolutely easy to understand.. i love the way you teach, Sir. Slowly and detail..
    I love it...
    Greetings from Indonesia

  • @happyhayot
    @happyhayot 4 года назад +7

    Excellent professor, excellent examples. Thanks.

  • @happyhayot
    @happyhayot 4 года назад +6

    I missed the integration by parts at 29:10, why do we write only the second term?

    • @happyhayot
      @happyhayot 4 года назад +8

      I got it at 1:11:15 , it is because n is equal to zero at the endpoints.

    • @mamathamaddur836
      @mamathamaddur836 3 года назад +2

      @@happyhayot thank you

  • @user-wb4pz8pz7f
    @user-wb4pz8pz7f 5 лет назад +6

    Thank you so much...
    Great lecture...

  • @rahgeer.9893
    @rahgeer.9893 Месяц назад

    27:30 why third term didn't appear??

  • @nitink9879
    @nitink9879 2 года назад +2

    13:27 Could anyone please explain this step? I don't understand what sir is saying.

    • @कुमाऊँनी-ढ7ख
      @कुमाऊँनी-ढ7ख Год назад

      He said from the expansion of e to the power minus t Nx, we will consider only upto the linear term which is 1- tNx

  • @feynmath
    @feynmath 3 года назад +2

    Can anyone help me with the step at 29:13 ?
    Where does the negative sign come from and how can we pull "eta " out?

    • @sheetalmadi336
      @sheetalmadi336 3 года назад +1

      Do integration by parts of the second term of the integrand,then you will get two terms,and after putting the limits the first term vanishes as n(eta) is 0 at the end points.(x1 and x2).

    • @feynmath
      @feynmath 3 года назад +1

      @@sheetalmadi336 Thanks. Figured that out. 🙂

  • @debojyotikoley8067
    @debojyotikoley8067 3 года назад +3

    In Brachistochrone problem according to my calculation y dot=√{1/(c^2*y)-1}. Where is my fault?

    • @chethans5908
      @chethans5908 2 года назад

      actually 1/(c^2) is just another constant, so its just a symbol. To avoid confusion one may write 1/c^2 as d, so the final equation will become Square root of d/y -1

  • @kaustuvregmi1469
    @kaustuvregmi1469 4 года назад +2

    Wow Very beautiful

  • @pastorofmuppets7654
    @pastorofmuppets7654 4 года назад +2

    Where can I find the first video? Thank you in advance.

    • @daily8150
      @daily8150 3 года назад +1

      ruclips.net/p/PLwdnzlV3ogoXUbQmP-T2gPhYXeEcxP6U8

  • @mihirhota8086
    @mihirhota8086 5 лет назад +2

    Very good explanation.

  • @AlexBlade27
    @AlexBlade27 Год назад

    I was wondering, Lagrangian was the one who invented Variational calculus. He was the one who got Lagrange's equation in physics. He arrived at the concept of Functionals. What did Hamilton did then? Because if Lagrange put Functional as L. He would arrive at same conclusion as Hamilton.

  • @AA-cy9ib
    @AA-cy9ib 3 года назад +2

    0:25

  • @dr.b.gnanavel3765
    @dr.b.gnanavel3765 4 года назад +2

    Super sir.

  • @ankitmishra2723
    @ankitmishra2723 5 лет назад +2

    Thanks sir

  • @e4eduspace281
    @e4eduspace281 3 года назад +2

    Thanks sir