The Real TORIC TRANSPOSITION tutorial

[@DrPrateekJain_eye]

Thanks ma'am .
Answer for last toric transposition
+10DS / -6DCyl@90° / -8DCyl@180°

[@InsightOphthalmology]

That's absolutely correct !

[@salmalahari8195]

Hello madam, please can you kindly do an optics series especially an introductory course. I am really struggling with it. I always find your videos very enlightening. Thank you very much. God bless you

[@TheSingingSingh874]

Thanks

[@pratibharathore3364]

Maam How to find base curve value in day-to-day cases?
Any formula for that?

[@drkanikagupta1193]

Sphere 10, bc-6 at 90, cc-8at 180

[@fgzy123]

Thanks for the video. Why would you say the 180 degree axis is vertical. Isn't it horizontal?

[@zulnaem]

Tq so much dr amreet

[@batanaistanleynyatsanza5703]

Excellent explanation I'm a happy student

[@InsightOphthalmology]

Glad to hear that

[@matteocapobianco5168]

I've a question, How to find base curve value? Great video!

[@InsightOphthalmology]

Good question!
It's determined through trial lenses that come in different base curves.
If not it can also be determined using the keratometry readings

[@BuddingOphthalmologist]

Mam will you do video on binocular balancing

[@TheSingingSingh874]

Thanks Dr👍

[@ophthojooeileyecirclehisha4917]

thank you so much

[@IbnuIshmael]

What if the question was +4DS/-2DC x180 (BC=-6D)
I mean the @ change with ‘x’

[@drkanikagupta1193]

I am not sure of a question but it mentioned that the lens is not stable and falls off so how shall we modify the prescription. Could you explain the concept?

[@atyutep4850]

How to represent it in the optical cross

[@praisypraisycmc2082]

+10.00DS/-6.00DC@90/-8.00DC@180

[@Scotch230393]

towards the end, the second example, the base curve at its axis should be (-6DC@180) not (-6DC@90). otherwise great video! and thank you

[@nithyasr3740]

I got 90 as axis. Could please explain how do you feel it is 180. Thanks.

[@Scotch230393]

Actually you're right, I followed the formula before simple transposition

[@ShayanKhan-do4fx]

👍❤

[@franklinchowdhury4156]

Thank you very much

[@atyutep4850]

How to represent it in the optical cross