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Very good. Thanks 🙏🙏🙏🙏🙏
Hello Sir, please consider a 3 phase fault problem with fault impedance too. That will also help many students.
Sir, in your previous problem, 10% =.1pu only . But hear 10%=.1j pu .. Why here 'j' comes??
When ever you write reactance, mark it like j0.1 puBecause inductive reactance is jXLEven in the previous problem, you can use j0.1pu
Sir IL also per unitil akkande
20MVA=20000KVA right
correct
If"=2.802+5.408 = 8.21 than varuthu but nenga 8.081 nu write panringa antha angle ah add panna -90 varaathu sir please replay me
Sir, Eg" value calculation wrong aha varuthu so calculation num sollikodunga
Very good. Thanks 🙏🙏🙏🙏🙏
Hello Sir, please consider a 3 phase fault problem with fault impedance too. That will also help many students.
Sir, in your previous problem, 10% =.1pu only . But hear 10%=.1j pu .. Why here 'j' comes??
When ever you write reactance, mark it like j0.1 pu
Because inductive reactance is jXL
Even in the previous problem, you can use j0.1pu
Sir IL also per unitil akkande
20MVA=20000KVA right
correct
If"=2.802+5.408 = 8.21 than varuthu but nenga 8.081 nu write panringa antha angle ah add panna -90 varaathu sir please replay me
Sir, Eg" value calculation wrong aha varuthu so calculation num sollikodunga