Python Programming Practice: LeetCode #6 -- ZigZag Conversion

[@johnbanyan11]

man.. ur making sense even to me ...i'm the guy who started coding from last two months...thanks for the content

[@neotank874]

You are an undiscovered treasure of youtube.

[@DataDaft]

Thanks. =)

[@karamanabdullah]

I know your views are very low but you are very precious for data science.

[@fnfal113]

Thanks man, your initial assesment made me create a solution before watching the real code in your video.

[@sady02_]

Man I thought it is 1B but it was 18 views
Wish you the best

[@devashreesharma3865]

I loved how you explained it so easily. Thank you so much :)

[@manh9105]

finally understood this zigzag problem's solution

[@tubex1300]

i loved the way you approach to the problems solving in recursion - can you make a videos that will explain deeply in recursion pls

[@mryup6100]

What an elegant solution!

[@thonmaker7880]

Solid video

[@abaundwal]

Very nice explanation

[@yashm05]

Best Technique !!! thanks for the video :)

[@vishalsinghsengar7951]

The content is awesome and deserving of more love

[@sidehat1655]

I wouldn't have bothered with the intermediate form. Easier just to change one string into the other. Less lines of code.
'''
def zigzag(in_s, row_count, col_count):
in_s_len, out_s, i = len(in_s), "", 0
for col in range(col_count):
for row in range(row_coun)t:
if col % 2 or not row % 2:
out_s += in_s[i]
i += 1
return out_s
'''
God coding on your phone is painful... Zero chance there isn't a bug there but hopefully you get the idea.
I just loop the rows and treat the even and odd ones differently.

[@MJ-qr5xw]

Was stuck at this problem for 3 hrs , now i feel foolish😅. Thanks for such a good explination

[@wildworldexplorerstv]

You're a legend!

[@snehanath277]

Thank you very much.

[@Lumary]

brilliant solution, thanks for sharing! :)