Difficult Trigonometric Identities with Fractions and Reciprocals MCR3U

[@samuelopoku2906]

I salute you boss 😊😊😊😊 very very fantastic may God continue to give you more knowledge

[@MathematicsTutor]

Thanks. Playlist for you: ruclips.net/video/R-Bb9U6LJmg/видео.html

[@DrRSPMD2010]

Thanks Anil, that’s amazing !!!

[@MalutiChali]

Amazing

[@jasoninirllife]

I have a test on this in two days and it's the only unit I've really struggled with in pre-calc, hopefully your video helps me out.

[@MathematicsTutor]

PLAYLIST for you: ruclips.net/video/X-yT2mCDmdo/видео.html
All the Best!

[@salamiumaru333]

How do you always know tht this is actually the right way to solve this proof sir

[@rajendranr3856]

I too feel,these are random approach and prescripted doing...

[@michaelperez3792]

Yo are the best. Thank you so much!!

[@KundaJohn-z3h]

Thank you for your insane skills of expression

[@MathematicsTutor]

Thanks for appreciation

[@henrybotwe1900]

Thanks

[@EmmaWamimbi-mv3zj]

Thanks but what u say covers the calculation

[@crazyjester993]

4:38 denominator similar method

[@chilandapretty-rd7zg]

WOW

[@theuniversejustbreaks]

Thanks SIr...

[@aminaabdelghani5200]

Thank you

[@bruh-lk8rd]

why at 8:23 cot is sin/cos? isnt it cos/sin?

[@MathematicsTutor]

cot was in the denominator. Hope that helps. Thanks

[@bel_100]

Omg your video has saved me , thank you

[@kevin-gg8ir]

Props to you sir!👏 I tried one of these from the other side and finally got it😁

[@MathematicsTutor]

PLAYlist: ruclips.net/video/_B0xntkx8ms/видео.html
Thanks

[@abderrahimoubihi5424]

Could you please prove this identity
Sin4x+cosx/cos4x+sinx=sec3x+tan3x

[@neoidt]

ım from türkiye. math is dont have language so thank you so much

[@justinchandra352]

Hey, I have a question at 11:47 on the video I did the question a different way but I got the same answer I just wanna know if I made some maths errors or not. so 1-sinx can I substitute cosx? I got this by square rooting the sin^2x +cos^2x=1 and then I rearranged to get cosx=1-sinx. So my question is can I square root the identities or will I break the maths laws thank you.

[@prithvisinghpanwar007]

It's incorrect because root(a²+b²) can not be simplified as a+b
root(a²×b²) can be simplified as ±ab

[@Aliabdi-mk9zx3tl1d]

Wararka ruska intay kudanbeysey.