Free GRE Prep Hour: Mixing Inequalities, Absolute Values, and Quantitative Comparisons

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  • Опубликовано: 12 дек 2024

Комментарии • 15

  • @asifzohaib9753
    @asifzohaib9753 3 года назад +1

    YOUR PLAYLIST IS ENOUGH FOR PREP
    ARATION

  • @mahmoodghorbanmoghaddam5641
    @mahmoodghorbanmoghaddam5641 2 года назад

    Thanks for your great lessons.
    I think the answer of Q4 (38:50) is D, because x can be either less than -3/5 or more than -3 (not less than -3/5 and more than -3). then for example +10 is an acceptable answer for x (as we can try in the equation). and also -4 can be an answer for x.
    therefore |x| can be 4 (for x = -4) and also can be 10 (for x = +10), so answer D seems to be the right one.

    • @manhattanprepgre7390
      @manhattanprepgre7390  2 года назад

      So glad you enjoy them! Be careful when you're on the negative side of the number line. The expression works out to a value that is greater than -3 (so to the right of the number line) AND less than -3/5 (to the left of the number line) - so graphed, it must be between those numbers (since -3 is LESS than -3/5). Check out the value you chose x = 10. If you plug that in for the original inequality, |3 + 30| < -2(10), or |33| < -20...but an absolute value can NEVER be less than a negative because it's always positive! It's also not true that -4 will work, test the original inequality again. |3 - 12| < -2(-4), or |-9| < 8 --> 9 < 8 (which it isn't). I think for me, it can be really easy to mix up the negative side of the number line unless I draw it out. So I would create a line that has so that you can more easily see that the greater than -3 and less than -3/5 puts the numbers in between those two (not on the outsides of them). Hope this helps!

  • @pranavpatil9494
    @pranavpatil9494 3 года назад

    Thank you whitney for this video♥️
    Just love your concept regarding Inequalities

  • @sarahhesham6309
    @sarahhesham6309 3 года назад +2

    Amazing, thanks.

  • @zeeldesai4175
    @zeeldesai4175 Год назад

    What is the final answer of question at (23.27) is it D?

  • @vedantbhenia9085
    @vedantbhenia9085 3 года назад +1

    Hey Vit, does the playlist you made for GRE preparation includes everything?

    • @manhattanprepgre7390
      @manhattanprepgre7390  3 года назад +2

      Hi! Our Free Prep Hour playlist includes a ton of content and strategy review! That said, we believe that solid preparation for the GRE would also include things such as practice exams, the Official Guide, and a more formal organization of the content and topics covered (such as a Strategy Guide for quant and/or verbal).

  • @JF-rg1vt
    @JF-rg1vt Год назад

    Hi. Question 2: I don't understand if the answer is C ord D. Because yes one option is 28/3 but the other is not so the answer should be D. Please explain me.

    • @AhmedMohamed-nz3zx
      @AhmedMohamed-nz3zx 7 месяцев назад

      same I dont know the answer for qustion 2, did u figure it out?

  • @AhmedMohamed-nz3zx
    @AhmedMohamed-nz3zx 7 месяцев назад

    I am confused on the answer for question 2. What is the answer can someone please explain

  • @SHUBHAMSINGH-gh6ln
    @SHUBHAMSINGH-gh6ln 3 года назад

    What is the answer of last question - is it D

    • @manhattanprepgre7390
      @manhattanprepgre7390  3 года назад +4

      Hi Subham! The answer to the last question is actually B. In order for the absolute value of x to be greater than the absolute value of y, x must be further from 0 than y is (regardless of positive or negative). That is illustrated by the numberline on the top left (with x set further from 0 than y in both the positive or the negative). Next, however, you're told that the sum of x and y must be positive. In order for that to be true, at least 1 (if not both) must be positive. So if both are positive, x is greater than y (B). Or if x is positive and y is negative, then again, x is greater than y (B). But since it is QC, you want to try to "prove D." In other words, could you have a situation where x and y are equal, or where y is greater than x? Based on the number line, they cannot be equal (or |x| won't be greater than |y|). So can y be greater? That would mean that y had to be positive and x had to be negative. However, if y is positive but x is negative, x is going to be MORE negative than y is positive, meaning that their sum would be negative. That would violate x+y>0. So the only relationships have x > y. Hope this helps!

    • @SHUBHAMSINGH-gh6ln
      @SHUBHAMSINGH-gh6ln 3 года назад

      @@manhattanprepgre7390 Thanks for your time and response. It cleared my doubts.