Thanks for your great lessons. I think the answer of Q4 (38:50) is D, because x can be either less than -3/5 or more than -3 (not less than -3/5 and more than -3). then for example +10 is an acceptable answer for x (as we can try in the equation). and also -4 can be an answer for x. therefore |x| can be 4 (for x = -4) and also can be 10 (for x = +10), so answer D seems to be the right one.
So glad you enjoy them! Be careful when you're on the negative side of the number line. The expression works out to a value that is greater than -3 (so to the right of the number line) AND less than -3/5 (to the left of the number line) - so graphed, it must be between those numbers (since -3 is LESS than -3/5). Check out the value you chose x = 10. If you plug that in for the original inequality, |3 + 30| < -2(10), or |33| < -20...but an absolute value can NEVER be less than a negative because it's always positive! It's also not true that -4 will work, test the original inequality again. |3 - 12| < -2(-4), or |-9| < 8 --> 9 < 8 (which it isn't). I think for me, it can be really easy to mix up the negative side of the number line unless I draw it out. So I would create a line that has so that you can more easily see that the greater than -3 and less than -3/5 puts the numbers in between those two (not on the outsides of them). Hope this helps!
Hi! Our Free Prep Hour playlist includes a ton of content and strategy review! That said, we believe that solid preparation for the GRE would also include things such as practice exams, the Official Guide, and a more formal organization of the content and topics covered (such as a Strategy Guide for quant and/or verbal).
Hi. Question 2: I don't understand if the answer is C ord D. Because yes one option is 28/3 but the other is not so the answer should be D. Please explain me.
Hi Subham! The answer to the last question is actually B. In order for the absolute value of x to be greater than the absolute value of y, x must be further from 0 than y is (regardless of positive or negative). That is illustrated by the numberline on the top left (with x set further from 0 than y in both the positive or the negative). Next, however, you're told that the sum of x and y must be positive. In order for that to be true, at least 1 (if not both) must be positive. So if both are positive, x is greater than y (B). Or if x is positive and y is negative, then again, x is greater than y (B). But since it is QC, you want to try to "prove D." In other words, could you have a situation where x and y are equal, or where y is greater than x? Based on the number line, they cannot be equal (or |x| won't be greater than |y|). So can y be greater? That would mean that y had to be positive and x had to be negative. However, if y is positive but x is negative, x is going to be MORE negative than y is positive, meaning that their sum would be negative. That would violate x+y>0. So the only relationships have x > y. Hope this helps!
YOUR PLAYLIST IS ENOUGH FOR PREP
ARATION
Thanks for your great lessons.
I think the answer of Q4 (38:50) is D, because x can be either less than -3/5 or more than -3 (not less than -3/5 and more than -3). then for example +10 is an acceptable answer for x (as we can try in the equation). and also -4 can be an answer for x.
therefore |x| can be 4 (for x = -4) and also can be 10 (for x = +10), so answer D seems to be the right one.
So glad you enjoy them! Be careful when you're on the negative side of the number line. The expression works out to a value that is greater than -3 (so to the right of the number line) AND less than -3/5 (to the left of the number line) - so graphed, it must be between those numbers (since -3 is LESS than -3/5). Check out the value you chose x = 10. If you plug that in for the original inequality, |3 + 30| < -2(10), or |33| < -20...but an absolute value can NEVER be less than a negative because it's always positive! It's also not true that -4 will work, test the original inequality again. |3 - 12| < -2(-4), or |-9| < 8 --> 9 < 8 (which it isn't). I think for me, it can be really easy to mix up the negative side of the number line unless I draw it out. So I would create a line that has so that you can more easily see that the greater than -3 and less than -3/5 puts the numbers in between those two (not on the outsides of them). Hope this helps!
Thank you whitney for this video♥️
Just love your concept regarding Inequalities
Amazing, thanks.
What is the final answer of question at (23.27) is it D?
Hey Vit, does the playlist you made for GRE preparation includes everything?
Hi! Our Free Prep Hour playlist includes a ton of content and strategy review! That said, we believe that solid preparation for the GRE would also include things such as practice exams, the Official Guide, and a more formal organization of the content and topics covered (such as a Strategy Guide for quant and/or verbal).
Hi. Question 2: I don't understand if the answer is C ord D. Because yes one option is 28/3 but the other is not so the answer should be D. Please explain me.
same I dont know the answer for qustion 2, did u figure it out?
I am confused on the answer for question 2. What is the answer can someone please explain
is question 2 D?
What is the answer of last question - is it D
Hi Subham! The answer to the last question is actually B. In order for the absolute value of x to be greater than the absolute value of y, x must be further from 0 than y is (regardless of positive or negative). That is illustrated by the numberline on the top left (with x set further from 0 than y in both the positive or the negative). Next, however, you're told that the sum of x and y must be positive. In order for that to be true, at least 1 (if not both) must be positive. So if both are positive, x is greater than y (B). Or if x is positive and y is negative, then again, x is greater than y (B). But since it is QC, you want to try to "prove D." In other words, could you have a situation where x and y are equal, or where y is greater than x? Based on the number line, they cannot be equal (or |x| won't be greater than |y|). So can y be greater? That would mean that y had to be positive and x had to be negative. However, if y is positive but x is negative, x is going to be MORE negative than y is positive, meaning that their sum would be negative. That would violate x+y>0. So the only relationships have x > y. Hope this helps!
@@manhattanprepgre7390 Thanks for your time and response. It cleared my doubts.