The stability of equilibria of a differential equation, analytic approach

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  • Опубликовано: 28 янв 2025

Комментарии •

  • @lokidragion4859
    @lokidragion4859 4 года назад

    Thank you, this is such a great video, you actually explain it way better than my teacher

  • @Taddius4zindagi
    @Taddius4zindagi 11 лет назад +1

    Super thanks! People who selflessly spare time and effort to help sc****d students like us restore faith in humanity... God bless you...

  • @viji001
    @viji001 11 лет назад +3

    thanks , it was great. I choose dynamical system for degree, coz of u

  • @Mr1Lemos
    @Mr1Lemos 8 лет назад

    Thanks for your video! Very clear and easy to understand :)

  • @shadenaguirre6317
    @shadenaguirre6317 7 лет назад +1

    what makes the differential equation semi-stable?

  • @danieltian5088
    @danieltian5088 6 лет назад

    Awesome video. Thank you

  • @ankit45822
    @ankit45822 7 лет назад

    I can not understand that how the arrow moves away or toward from origin. In which function do you ask ?

  • @robert6816
    @robert6816 8 лет назад

    Thank you...concise and clear

  • @uditsaxena3844
    @uditsaxena3844 4 года назад

    thanks i understood it all

  • @tomenart
    @tomenart 8 лет назад

    great video man

  • @Fabian_AD
    @Fabian_AD 8 лет назад

    What if it's not an autonomous differential equation?

    • @duanenykamp5700
      @duanenykamp5700  8 лет назад

      If the differential equation isn't autonomous, then it presumably doesn't have any equilibria, as the rates of change would be explicitly changing with time. None of this analysis would apply.

    • @Fabian_AD
      @Fabian_AD 8 лет назад

      What about an equation like:
      y' = (y-1)/(t^2)
      Would it be ok to just set y' = 0 and get rid of the t^2?

    • @duanenykamp5700
      @duanenykamp5700  8 лет назад +1

      In this case, you can directly calculate that y(t)=1 is a solution to the differential equation, at least if you start with a positive t. For y larger than 1, y' is clearly positive. For y smaller than 1, y' is clearly negative. Hence, nearby solutions are moving away from the solution y(t)=1.