He's one of the best math teachers I've encountered in my lifetime, and I've been around! He seems willing to work with his students and encourage them to study this fabulous science!
He could be if he shortened the solutions. A 20 min video is not helpful. Every video contains way too much backstory, smiley faces, and sales pitch for the importance of math. It would be much more helpful to have links to previous videos explaining order of operations or methods needed to solve it… instead of a “brief” explanation EACH TIME. I do like the vids, but it’s frustrating to have to keep hitting the fast forward so many times.
Your videos are outstanding they were what made me try out your math program. You are direct and to the point. The enthusiasm and positivity you bring is priceless.
You can solve using logarithms. But by the process of elimination is faster. 3² = 9 3³ = 27 Therefore 2 < x ÷ 2 < 3 If x = 8 yields 4 too big Same with 24 If x = 2.26 yields 1.13 too small So answer is d) 4.52
Seems easier to start by raising both sides by the power of 2. Then by the power rules, you have 3^x=144. That is how I started the problem. Then do your log functions.
Dear John, Here is how I finally solved this my way, after some help from you on logs. First, I squared both sides. Why? Because squaring the side with the exponent is done by adding the exponent x/2 to itself, and adding half of any value to half equals that value (n/2 + n/2 = n). Result is a simplified exponent: 3^(x/2) × 3^(x/2) = 3^x and 12 × 12 = 144 So, 3^x =144 then xlog3 = log144 as you taught me. Finally, divide both sides by log3: x = log144 / log3 = 4.52 approximately. What do you think of this?
I did not need a calculater or a log table: So here's my logic of getting my choice of d: 3^2 = 9, so for 3^y = 12, y would be slightly larger than 2. And x/2 woulc be slighlt larger than 2. So the multiple choice answer is d.
This is an excellent example of how relying on PEMDAS just adds confusion. Use parentheses, or recast the problem as two pieces. y=x/2; 3^y = 12. Solve for y, then solve for x.
how about squaring both sides 3^(x/2)^2 = 12^2 3^x = 144 x log 3 = log 144 x = (log3+log3+log4+log4)/log3 x= (2+2log4)/log3 => 2(1+log4)/log3 where log4/log3 is log4 base3
Look, without even writing anything down it's easy to see that this is log(144)/log(3) (actually the log can be in any base). In base 10 we know that log(144) is going to be "a bit over 2" (just the log(100) part), and most of us just know that log(3) is a tad under 0.5. So we know log(144)/log(3) is going to be something somewhat over 4. That's enough to zero us in on answer (d). See, you don't have to solve these things exactly - if you just cultivate the right sort of number sense you can usually figure them out in seconds in this sort of "multiple choice" environment. Especially when the offered options are as spread out as these are - (d) is the only one that's even in the ballpark.
I started by observing 3 power 2 is 9. 12/9 is 4/3. Square root 3 is about 1.7, 4th root about 1.3. So 3 power x/2 =12 gives x/2 approximately 2.25. X is double, approximately 4.5. Viewing the options, (d). Giving this a multiple choice, and has to be solved in 10 seconds, no one will have time for anymore calculation.
If you use deductive reasoning, you can get rid of 2 of the 4 solutions, as they don't make sense (for example 3 to the 4th power is 81, and so x cannot be 8 -- must be less than 8, so that also rules out 24). However we do know that 3 to the 2nd power is 9 and that 3 to the third power is 27 so it's somewhere in between. Actually you don't really need to do much math except figure out what 3 to the 2nd power and the 3rd power is to narrow down the answer. But technically you can do this in your head too (not even need logs; of course using logs is the mathematically correct way to solve this, but if you didn't know, you could use trial-and-error here too with some reasoning). (Actually you can eliminate answer C pretty quickly too if you figure that 2.26 / 2 is 1.13, which is less than 2 and we know that 3 squared is 9, which is still too low, but 4.52 / 2 = 2.26, and that might work because it's more than 2, but less than 3.
To solve without a calculator (or even without writing it down on paper) 9 < 12 < 27 3^2 < 3^(x/2) < 3^3 2 < x/2 < 3 4 < x < 6 The only solution that fits this inequality is D) 4.52
I should be able to solve it easily! Come on, if I could do that would I be watching at all? John, you are great at math for sure , that's why I watch! But I don't need comments that try and make me feel dumb for not thinking something's easy! Thanks John!
Some times. 10:07 you don’t have to actually do the Algebra In particular this problem Will know the answer is in front of us Choice a And b see way off so you are left with c and d with out doing a lot of math in my head I came up with D I had a teacher who gave up a multiple choice test He told us there were a lot of problems He said you definitely won’t finish any many of your are going to not do well and many will fail Your goal is to get as many right He said you are going to come up with different strategies to pass this test We were just given the test with out any notice or preparation The one hint or help he gave us The correct answer in is in front of you use that A lot of the problems you solve in you head pretty quickly Pretty much you had to eliminate the wrong answers I did well on it Some of the problems were extremely difficult I didn’t attempt to do them I went to the next problem This basic strategy was do what you know and if there is time go back In some problems later in the test you were given the correct answer It was a very valuable lesson to learn He gave a similar test a few days later most did well on it lesson learned
Greetings. The answer is d, 4.52. The expression 3^X/2=12 boils down to 3^X=12^2. That is X log3=log 144, and X =log 144/log 3=2.158362492÷ .477121254= 4.523719014= 4.52 approximately. Lovely. 3^X/2=12 can be written as 3^(X/2×2/X)= 12^2/X to get rid of the exponent X/2. Now we have 3=12^2/X. Moving forward we want to get rid of the root X. We will accomplish this by raising all the terms of the expression by X to get 3^X=12^(2/X ×X/1). That is 3^X=12^2. From here you will employ logarithmic functions. Try it and see.
I see that if 3 to the x power is equal to 2 times 12, therefore 24, then x has to be 8. (3, 8 times makes 24, then divide that by 2)). What do you think?? Makes sense to me. I choose a) 8.
I think I got it wrong because I misunderstood how to work out te exponent 'x'. It isn't 3 times 8. It is 3times 3, then that answer, 9, times 3, and so on 8 times. @@StephenRayWesley
You don't need to check c with a calculator. 2.26 divided by 2 is 1 point something, clearly not enough to make 12. Or, x/2 has to be more than 2, because 3^2=9, which is less than 12. So x has to be more than 4.
Trickier than it looks ... First: The exponent is, both, confusing and distracting. * Given: In terms of MDAS Ops, The "x÷2" is ALL depicted as *superscipt but, for the sake of clarity, I would recommend enclosure, within parenthesis (however redundant). ... ** Let us disregard the "factored form", of the exponent "(x÷2)" and substitute with "(?)". ENGLISH: How many times to multiply 3, by itself, to attain 12 ? .. ** Intuitively, 3*3=9 and 3*3*3=27 and 12 is much closer to 3 squared so, looking at the given answers, we know that we are looking for an answer that is twice "(?)" or (BETWEEN 4 and 5) TOOK ME LONGER THAN I HAD HOPED
Nice, that you are so appassionate about math and guessing games 😅 I have one for you: imagine, there was a big flaw in the assumption, that the public exponent of a secure RSA signature, was given by a large number, which was extremely difficult to solve by brute force. If however you would not use the formula E = pq Where p and q are large prime numbers and E the product, how would you attempt to get one of the factors without testing each possible combination? On a 32 bit Intel processor, it is solvable in seconds for a 8192 bit long number with integer multiplication, if you throw over board the obvious and tackle the problem from an innocent point of view. You can make it, if you forget for a moment the dimensions and all what you know, except simple multiplication and division. If you solve it, keep the result for you. It is a fascinating thought process, which however would activate worldly powers, should the solution become public.
The way I solved it realizing the first two are wrong and gave me 2 real choices left and knowing I am dividing x by 2 the quociant will be between 2 and 3 eliminates c leaving d as the correct answer
Mr RUclips Math Man. If I chose to use your bacon and eggs concept/theory would I get the answer? So if I say log base 3 to the power of 12 = x/2, would that work?
What is 1 + 1? (Hint - It's 2). He could make a 20 video explaining this and have the student so confused that the student drops the math class and switches to Art 101 or phys ed.
None of the answers is correct. Answer d) is the closest (it comes to 11.97) but with that it is just as incorrect as the others. But if that isca close enough outcome, it is easily solved: 3^2=9, which is too small, 3^3=27 which is to big, so x+2 is in between 2 and 3, so x is in between 4 and 5. Only reply possible then is d. It is not rocketscience
D is not incorrect. If x = 4.52 then 3^(x/2) = 3^2.26 ≈ 11.97 which is accurate to 3 significant digits, which is exactly what we'd expect when x is also accurate to 3 significant digits. If we use a more accurate result, say x = 4.523719014285829748398, then plugging back in we get 3^(x/2) = 3^2.261859507142914874199 ≈ 11.999999999999999999999285. Still not quite 12. The only exact solution is x = 2 log₃(12)
@@MarieAnne. 11.97 is not 12. Ergo, not correct. When answering multiple choice one would 'expect' the outcome to be correct, unless the question states 'which one comes closest'
U did not simplify saying log 12 divided by log 3 will give 2.26 and then multiply 2.26 by 2 will give rounded up 4.52. This is click bate, but should not be in standard form of test, take too long, unfair did not say use log, cz take too long that time is too tight in standard test why question like this should not be in standard test, but good to get (click bate!), math teacher or not, everybody need something using U tube to get some recognition n few cents or more. All these steps would have been simpler if question stated use log! All these has zero connection in reality for vast plus people other than those forced to learn to go to college even then only top 5-ercent graduates, best of best, ever get their field gets job, why trade school is booming n I know even ex-electrical, mechanical engineering major ended up going to trade school to obtain automotive certifications to be auto technician how highly computerized and must have at least fair understanding of electrical knowledge... This math is totally useless is my closing fact-based point indeed and case closed!
You are really falling down on this one, dont' want to use a calculator, defeats the whole purpose., You are just wasting time. just stick to the present problem
I get impatient with this teacher. Its a log problem so just get to it! I get it, you are trying to confuse new students with too many ideas and scribbles.
Utter ridiculous to take 20 mins for what took me literally 3 seconds to do it twice. I had to make sure as it was so easy. This guy is laughable. He would have flunked 11+ for not answering in the time allotted. So bloody remedial it’s beyond a joke if people can’t do this - it’s simple multiplication. Oh wait, I know someone who can’t do this his initials are DT.
This is why math is so fucked up. There could be 2 more different ways to solve this. Plug that number that number back into the equation. Then tell me what you come up with.
He's one of the best math teachers I've encountered in my lifetime, and I've been around! He seems willing to work with his students and encourage them to study this fabulous science!
He could be if he shortened the solutions. A 20 min video is not helpful. Every video contains way too much backstory, smiley faces, and sales pitch for the importance of math. It would be much more helpful to have links to previous videos explaining order of operations or methods needed to solve it… instead of a “brief” explanation EACH TIME.
I do like the vids, but it’s frustrating to have to keep hitting the fast forward so many times.
Your videos are outstanding they were what made me try out your math program. You are direct and to the point. The enthusiasm and positivity you bring is priceless.
You can solve using logarithms.
But by the process of elimination is faster.
3² = 9
3³ = 27
Therefore 2 < x ÷ 2 < 3
If x = 8 yields 4 too big
Same with 24
If x = 2.26 yields 1.13 too small
So answer is d) 4.52
Once you get to
2 < x ÷ 2 < 3
you can just multiply through by 2 to get
4 < x < 6
and then just find the one number in this interval
Seems easier to start by raising both sides by the power of 2. Then by the power rules, you have 3^x=144. That is how I started the problem. Then do your log functions.
That's what I did, as detailed in my earlier post. It is almost the simplest way, and has a simpler exponent of just x.
Dear John, Here is how I finally solved this my way, after some help from you on logs.
First, I squared both sides. Why? Because squaring the side with the exponent is done by adding the exponent x/2 to itself, and adding half of any value to half equals that value (n/2 + n/2 = n). Result is a simplified exponent:
3^(x/2) × 3^(x/2) = 3^x and 12 × 12 = 144
So, 3^x =144
then xlog3 = log144 as you taught me. Finally, divide both sides by log3:
x = log144 / log3 = 4.52 approximately.
What do you think of this?
x/2 x log 3 = log 12
x/2 = log 12/ log 3
x = 2 x log 12/ log 3
x = 4,52
That’s what I did. Obvious
got it. logic dictates the exponent has to be a little more than 2 as 3 sqrd = 9 & 3 cubed = 27)
4.52 - 2 = 2.52 as the exponent. thanks for the fun.
It's x÷2 not x-2
thanks for the catch@@the318pop
I did not need a calculater or a log table: So here's my logic of getting my choice of d: 3^2 = 9, so for 3^y = 12, y would be slightly larger than 2. And x/2 woulc be slighlt larger than 2. So the multiple choice answer is d.
This is an excellent example of how relying on PEMDAS just adds confusion. Use parentheses, or recast the problem as two pieces. y=x/2; 3^y = 12. Solve for y, then solve for x.
how about squaring both sides 3^(x/2)^2 = 12^2
3^x = 144
x log 3 = log 144
x = (log3+log3+log4+log4)/log3
x= (2+2log4)/log3 => 2(1+log4)/log3 where log4/log3 is log4 base3
Look, without even writing anything down it's easy to see that this is log(144)/log(3) (actually the log can be in any base). In base 10 we know that log(144) is going to be "a bit over 2" (just the log(100) part), and most of us just know that log(3) is a tad under 0.5. So we know log(144)/log(3) is going to be something somewhat over 4. That's enough to zero us in on answer (d).
See, you don't have to solve these things exactly - if you just cultivate the right sort of number sense you can usually figure them out in seconds in this sort of "multiple choice" environment. Especially when the offered options are as spread out as these are - (d) is the only one that's even in the ballpark.
I started by observing 3 power 2 is 9. 12/9 is 4/3. Square root 3 is about 1.7, 4th root about 1.3. So 3 power x/2 =12 gives x/2 approximately 2.25. X is double, approximately 4.5. Viewing the options, (d).
Giving this a multiple choice, and has to be solved in 10 seconds, no one will have time for anymore calculation.
If you use deductive reasoning, you can get rid of 2 of the 4 solutions, as they don't make sense (for example 3 to the 4th power is 81, and so x cannot be 8 -- must be less than 8, so that also rules out 24). However we do know that 3 to the 2nd power is 9 and that 3 to the third power is 27 so it's somewhere in between. Actually you don't really need to do much math except figure out what 3 to the 2nd power and the 3rd power is to narrow down the answer. But technically you can do this in your head too (not even need logs; of course using logs is the mathematically correct way to solve this, but if you didn't know, you could use trial-and-error here too with some reasoning). (Actually you can eliminate answer C pretty quickly too if you figure that 2.26 / 2 is 1.13, which is less than 2 and we know that 3 squared is 9, which is still too low, but 4.52 / 2 = 2.26, and that might work because it's more than 2, but less than 3.
To solve without a calculator (or even without writing it down on paper)
9 < 12 < 27
3^2 < 3^(x/2) < 3^3
2 < x/2 < 3
4 < x < 6
The only solution that fits this inequality is D) 4.52
Clearly explained . Thanks
I should be able to solve it easily! Come on, if I could do that would I be watching at all? John, you are great at math for sure , that's why I watch! But I don't need comments that try and make me feel dumb for not thinking something's easy! Thanks John!
3^2 is 9
3^2 and a bit is 12
Y = 2 and a bit
3^y= 12
3^x/2 = 12
Y = x/2
2 and a bit = x/2
4 and a bit = x
I agree too ... he's a very great teacher and professor...😊😊😊 How great he is😮😮😮😮
just by guessing 3^2=9, and 3^3=27, then3^x is between those two choices , so x/2 must be between 2 and 3 - the multiple choice of between >4 but
3^2 = 9. 3^3=27. So x/2 must be between 2 and 3. X must be between 4 and 6. Only one answer fits, pick that one. 4 seconds, on to the next question.
Got d) by guesswork but appreciated the math lesson afterwards! Not all equations are so simple to guess! 😊
Some times. 10:07 you don’t have to actually do the Algebra In particular this problem Will know the answer is in front of us Choice a
And b see way off so you are left with c and d with out doing a lot of math in my head I came up with D I had a teacher who gave up a multiple choice test He told us there were a lot of problems He said you definitely won’t finish any many of your are going to not do well and many will fail Your goal is to get as many right He said you are going to come up with different strategies to pass this test We were just given the test with out any notice or preparation The one hint or help he gave us The correct answer in is in front of you use that A lot of the problems you solve in you head pretty quickly Pretty much you had to eliminate the wrong answers I did well on it Some of the problems were extremely difficult I didn’t attempt to do them I went to the next problem This basic strategy was do what you know and if there is time go back In some problems later in the test you were given the correct answer It was a very valuable lesson to learn He gave a similar test a few days later most did well on it lesson learned
₃ˣ÷² ₌ ₁₂ Squaring both sides; (aᵇ)ᶜ= aᵇᶜ hence ₃(x ÷ 2)² =₃(x/2) *2
₃ˣ ₌ ₁₂²
xlog₃ 3= log₃ 144
x= log₃144
x=4.52
It has to b D because if you subsitute A B or C for x they are either tt large or too small
Greetings. The answer is d, 4.52. The expression 3^X/2=12 boils down to
3^X=12^2. That is X log3=log 144,
and X =log 144/log 3=2.158362492÷ .477121254=
4.523719014= 4.52 approximately. Lovely.
3^X/2=12 can be written as
3^(X/2×2/X)= 12^2/X to get rid of the exponent X/2. Now we have
3=12^2/X. Moving forward we want to get rid of the root X. We will accomplish this by raising all the terms of the expression by X to get
3^X=12^(2/X ×X/1). That is 3^X=12^2. From here you will employ logarithmic functions. Try it and see.
I use this method it much easier
I see that if 3 to the x power is equal to 2 times 12, therefore 24, then x has to be 8. (3, 8 times makes 24, then divide that by 2)). What do you think?? Makes sense to me. I choose a) 8.
So do I
I think I got it wrong because I misunderstood how to work out te exponent 'x'. It isn't 3 times 8. It is 3times 3, then that answer, 9, times 3, and so on 8 times. @@StephenRayWesley
Wouldn't it be easier to just do:
x/2 (log3) = log12
x/2 = log12/log3
x/2 = 2.26
x = 2.26 times 2 = 4.52
?
You don't need to check c with a calculator. 2.26 divided by 2 is 1 point something, clearly not enough to make 12.
Or, x/2 has to be more than 2, because 3^2=9, which is less than 12. So x has to be more than 4.
Trickier than it looks ... First: The exponent is, both, confusing and distracting.
* Given: In terms of MDAS Ops, The "x÷2" is ALL depicted as *superscipt but, for the sake of clarity, I would recommend enclosure, within parenthesis (however redundant). ...
** Let us disregard the "factored form", of the exponent "(x÷2)" and substitute with "(?)".
ENGLISH: How many times to multiply 3, by itself, to attain 12 ? ..
** Intuitively, 3*3=9 and 3*3*3=27 and 12 is much closer to 3 squared so, looking at the given answers, we know that we are looking for an answer that is twice "(?)" or (BETWEEN 4 and 5)
TOOK ME LONGER THAN I HAD HOPED
Nice, that you are so appassionate about math and guessing games 😅
I have one for you: imagine, there was a big flaw in the assumption, that the public exponent of a secure RSA signature, was given by a large number, which was extremely difficult to solve by brute force.
If however you would not use the formula
E = pq
Where p and q are large prime numbers and E the product, how would you attempt to get one of the factors without testing each possible combination?
On a 32 bit Intel processor, it is solvable in seconds for a 8192 bit long number with integer multiplication, if you throw over board the obvious and tackle the problem from an innocent point of view.
You can make it, if you forget for a moment the dimensions and all what you know, except simple multiplication and division.
If you solve it, keep the result for you. It is a fascinating thought process, which however would activate worldly powers, should the solution become public.
PS: hints available 😊
D.4.52
It's Also Guess
3^2 = 9
3^3 =27
So
3^2.26 = 12
2.26 × 2 = 4.52
X/2 = Log12 / Log3 => X = 2(Log12/Log3) => X = 2 x 2.26 = 4.52
3^x =144.
144>3^4 but less than 3^5
Ans is between 4 and 5
4 .52
Well 3^2 is 9 and 3^3 is 27 so x/2 has to be a smidge over 2 meaning x must be a bigger idhe over 4, so D.
Now, to work it out properly.
Where is the subscribe button?
4.52
What is the question? If we are finding x, then answer is D . No real calculation needed as x/2 must be between 2 and 3
D. 4.52
3 ^2 = 9, 3^3 = 27
Therefore X/2 has to be larger than 2, but less than 3.
4.52 is the only logical answer.
Are logs really old? They were first publicized in 1614 by John Napier. A logarithm is the inverse function of exponentiation.
Yes, I have a long in my backyard that is hundreds of years old.
One of the oldest logs is Homer's Odyssey. Sumerians made accounting log tables, I think. 😅
D) 4.42
3exp2= 9, 3exp3= 27. Therefore x/2 must be between 2 and 3 or x must be between 4 and 6. Only answer d satisfied, x≈ 4.52.
In short simply we can say 3^x/2 = 12, squaring both side. 3^x =144, greater than 3^4 & less than 3^5 So x is greater than 4 & less than 5. ANS....d
D dividing it by 2 gives c
How do you solve this without a calculator?
Dude, I am confused more from this rhan before. Please redo this teaching how to do this WITHOUT a calculator and the "log" talk.
The way I solved it realizing the first two are wrong and gave me 2 real choices left and knowing I am dividing x by 2 the quociant will be between 2 and 3 eliminates c leaving d as the correct answer
Mr RUclips Math Man. If I chose to use your bacon and eggs concept/theory would I get the answer? So if I say log base 3 to the power of 12 = x/2, would that work?
D by inspection
What is 1 + 1? (Hint - It's 2). He could make a 20 video explaining this and have the student so confused that the student drops the math class and switches to Art 101 or phys ed.
where did your confusion begin?
nothing wrong with Art 101 or with phys ed...
So which are you; Russell or Whitehead?
I agree, helluva lot of waffle.
@@rjones6219 what waffle??
3² = 9.
3³ = 27.
So x:2 = 2, something.
So x = 4, something.
D.
I love him. I just think he puts too much unnecessary language in the video, then needed. We just want him to get to the point!
d
C) 2.26, opps read the equation wrong. X/2 not 3x/2. So D) 4.52
This question is pretty easy. 8 is much bigger.24 is even bigger. 2.26 is too small. Then the answer is d
Guesstamated. So 3 squared is 9 and 3 cubed is 27 so closest answer to 12 must be over the square and a lot less than the cube and that is 4.52.
Too much time wasted in solving problem.
In my days we didn't have calculators, logs were recorded in a booklet 😂
8?
8
x/2 must be bigger than 2 and less than 3 thus it must be 4.52/2.
Just looking at it, I'd eliminate a and b, and pick d...
None of the answers is correct. Answer d) is the closest (it comes to 11.97) but with that it is just as incorrect as the others.
But if that isca close enough outcome, it is easily solved: 3^2=9, which is too small, 3^3=27 which is to big, so x+2 is in between 2 and 3, so x is in between 4 and 5. Only reply possible then is d. It is not rocketscience
D is not incorrect. If x = 4.52 then 3^(x/2) = 3^2.26 ≈ 11.97 which is accurate to 3 significant digits, which is exactly what we'd expect when x is also accurate to 3 significant digits.
If we use a more accurate result, say x = 4.523719014285829748398, then plugging back in we get
3^(x/2) = 3^2.261859507142914874199 ≈ 11.999999999999999999999285. Still not quite 12.
The only exact solution is x = 2 log₃(12)
@@MarieAnne. 11.97 is not 12. Ergo, not correct. When answering multiple choice one would 'expect' the outcome to be correct, unless the question states 'which one comes closest'
a(8
D. X =4,52
Common sense, logic and a calculator. You can't miss.
Now let's see the proper method. I don't want to lose my newly found algebra "skills". ;)
d..
D
11.975? I love your videos, but that is not 12 in my world. Rounding up? So, pick the best answer? lol
24
My answer is A. 8
x = 50.3017
Was hoping to learn without the use of calculator 🤦🏻♀️
Got a happy face but had almost zero confidence. Algo boost!
something divided by 2 is 12. so that would be 24? my guess is d!
10 seconds later, I understood that 4
1+1= 11
U did not simplify saying log 12 divided by log 3 will give 2.26 and then multiply 2.26 by 2 will give rounded up 4.52. This is click bate, but should not be in standard form of test, take too long, unfair did not say use log, cz take too long that time is too tight in standard test why question like this should not be in standard test, but good to get (click bate!), math teacher or not, everybody need something using U tube to get some recognition n few cents or more. All these steps would have been simpler if question stated use log! All these has zero connection in reality for vast plus people other than those forced to learn to go to college even then only top 5-ercent graduates, best of best, ever get their field gets job, why trade school is booming n I know even ex-electrical, mechanical engineering major ended up going to trade school to obtain automotive certifications to be auto technician how highly computerized and must have at least fair understanding of electrical knowledge... This math is totally useless is my closing fact-based point indeed and case closed!
d) possibly?✓✓✓
Smh. Very annoying
Get to it and stop stretching out the video for earning. The video actually gave me anxiety!!!!!!
You are really falling down on this one, dont' want to use a calculator, defeats the whole purpose., You are just wasting time. just stick to the present problem
He talks and talks and talks........
I lost interest!!!
I get impatient with this teacher. Its a log problem so just get to it! I get it, you are trying to confuse new students with too many ideas and scribbles.
Utter ridiculous to take 20 mins for what took me literally 3 seconds to do it twice. I had to make sure as it was so easy. This guy is laughable. He would have flunked 11+ for not answering in the time allotted. So bloody remedial it’s beyond a joke if people can’t do this - it’s simple multiplication. Oh wait, I know someone who can’t do this his initials are DT.
And yet there are students that graduated High School that can't make change, when the Cash Register is broken.
I really wish you would just show how to solve the problem and not talk so much!
I wouldn't last 45 mins in his maths class, so boring!
This is why math is so fucked up. There could be 2 more different ways to solve this. Plug that number that number back into the equation. Then tell me what you come up with.
4.52
d
8
D
24
4.52
8
D
D