Courses on Khan Academy are always 100% free. Start practicing-and saving your progress-now: www.khanacademy.org/science/p... Introduction to what a reference frame is.
What does position mean? In physics, we love to precisely describe the motion of an object. Seriously, the first few chapters of basically every physics textbook are devoted to teaching people how to precisely describe motion since it is so important to everything else we do in physics. But to describe an object's motion, we have to first be able to describe its position-where it is at any particular time. More precisely, we need to specify its position relative to a convenient reference frame. Earth is often used as a reference frame, and we often describe the position of an object as it relates to stationary objects in that reference frame. For example, a professor’s position could be described in terms of where she is in relation to the nearby white board (Figure 1). In other cases, we use reference frames that are not stationary but rather are in motion relative to Earth. To describe the position of a person in an airplane, for example, we use the airplane, not Earth, as the reference frame (Figure 2). The variable xxx is often used to represent the horizontal position. The variable yyy is often used to represent the vertical position. [What about z?] zzzz xxyyzzzz What does displacement mean? If an object moves relative to a reference frame-for example, if a professor moves to the right relative to a whiteboard, or a passenger moves toward the rear of an airplane-then the object’s position changes. This change in position is known as displacement. The word displacement implies that an object has moved, or has been displaced. Displacement is defined to be the change in position of an object. It can be defined mathematically with the following equation: \text{Displacement}=\Delta x=x_f-x_0Displacement=Δx=x f −x 0 D, i, s, p, l, a, c, e, m, e, n, t, equals, delta, x, equals, x, start subscript, f, end subscript, minus, x, start subscript, 0, end subscript x_fx f x, start subscript, f, end subscript refers to the value of the final position. x_0x 0 x, start subscript, 0, end subscript refers to the value of the initial position. \Delta xΔxdelta, x is the symbol used to represent displacement. [What does the triangle symbol mean?] \Deltadeltayyy_f y, start subscript, f, end subscripty_0 y, start subscript, 0, end subscript \Delta y=y_f-y_0 delta, y, equals, y, start subscript, f, end subscript, minus, y, start subscript, 0, end subscript y_0-y_f y, start subscript, 0, end subscript, minus, y, start subscript, f, end subscript-\Delta yminus, delta, y x_0 x, start subscript, 0, end subscriptx_i x, start subscript, i, end subscriptx_1 x, start subscript, 1, end subscript Displacement is a vector. This means it has a direction as well as a magnitude and is represented visually as an arrow that points from the initial position to the final position. For example, consider the professor that walks relative to the whiteboard in Figure 1. Figure 1: A professor paces left and right while lecturing. The +2.0\text{ m}+2.0 mplus, 2, point, 0, space, m displacement of the professor relative to Earth is represented by an arrow pointing to the right. (Image credit: Openstax College Physics) The professor’s initial position is x_0=1.5\text{ m}x 0 =1.5 mx, start subscript, 0, end subscript, equals, 1, point, 5, space, m and her final position is x_f=3.5\text{ m}x f =3.5 mx, start subscript, f, end subscript, equals, 3, point, 5, space, m. Thus, her displacement can be found as follows, Δx=xf−x0=3.5 m−1.5 m=+2.0 m. In this coordinate system, motion to the right is positive, whereas motion to the left is negative. Now consider the passenger that walks relative to the plane in Figure 2. Figure 2: A passenger moves from his seat to the back of the plane. The −4.0 m displacement of the passenger relative to the plane is represented by an arrow toward the rear of the plane. (Image credit: Openstax College Physics) The airplane passenger’s initial position is x_0=6.0\text{ m}x 0 =6.0 mx, start subscript, 0, end subscript, equals, 6, point, 0, space, m and his final position is x_f=2.0\text{ m}x f =2.0 mx, start subscript, f, end subscript, equals, 2, point, 0, space, m, so his displacement can be found as follows, Δx=xf−x0=2.0 m−6.0 m=−4.0 m. His displacement is negative because his motion is toward the rear of the plane, or in the negative x direction in our coordinate system. In one-dimensional motion, direction can be specified with a plus or minus sign. When you begin a problem, you should select which direction is positive-usually that will be to the right or up, but you are free to select positive as being any direction. What do distance and distance traveled mean? We must be careful when using the word distance since there are two ways in which the term distance is used in physics. We can talk about the distance between two points, or we can talk about the distance traveled by an object. Distance is defined to be the magnitude or size of displacement between two positions. Note that the distance between two positions is not the same as the distance traveled between them. Distance traveled is the total length of the path traveled between two positions. Distance traveled is not a vector. It has no direction and, thus, no negative sign. For example, the distance the professor walks is 2.0 \text{ m}2.0 m2, point, 0, space, m. The distance the airplane passenger walks is 4.0 \text{ m}4.0 m4, point, 0, space, m. It is important to note that the distance traveled does not have to equal the magnitude of the displacement (i.e., distance between the two points). Specifically, if an object changes direction in its journey, the total distance traveled will be greater than the magnitude of the displacement between those two points. See the solved examples below. What's confusing about displacement? People often forget that the distance traveled can be greater than the magnitude of the displacement. By magnitude, we mean the size of the displacement without regard to its direction (i.e., just a number with a unit). For example, the professor could pace back and forth many times, perhaps walking a distance of 150 meters during a lecture, yet still end up only two meters to the right of her starting point. In this case her displacement would be +2 \text{ m}+2 mplus, 2, space, m, the magnitude of her displacement would be 2 \text{ m}2 m2, space, m, but the distance she traveled would be 150 \text{ m}150 m150, space, m. In kinematics we nearly always deal with displacement and magnitude of displacement and almost never with distance traveled. One way to think about this is to assume you marked the start of the motion and the end of the motion. The displacement is simply the difference in the position of the two marks and is independent of the path taken when traveling between the two marks. The distance traveled, however, is the total length of the path taken between the two marks. People often forget to include a negative sign, if needed, in their answer for displacement. This sometimes occurs if they accidentally subtract the final position from the initial position rather than subtracting the initial position from the final position. What do solved examples involving displacement look like? Example 1: Displacement of four moving objects Four objects move according to the paths shown in the diagram below. Assume the units of the horizontal scale are given in meters. (Image credit: altered from Openstax College Physics) What was the displacement of each object? Object A had an initial position of 0\text{ m}0 m0, space, m and a final position of 7\text{ m}7 m7, space, m. The displacement of object A can be shown with this equation: \Delta x_A= 7\text{ m}-0\text{ m}=+7\text{ m}Δx A =7 m−0 m=+7 mdelta, x, start subscript, A, end subscript, equals, 7, space, m, minus, 0, space, m, equals, plus, 7, space, m Object B had an initial position of 12\text{ m}12 m12, space, m and a final position of 7\text{ m}7 m7, space, m. The displacement of object B can be shown with this equation: \Delta x_B= 7\text{ m}-12\text{ m}=-5\text{ m}Δx B =7 m−12 m=−5 mdelta, x, start subscript, B, end subscript, equals, 7, space, m, minus, 12, space, m, equals, minus, 5, space, m Object C had an initial position of 2\text{ m}2 m2, space, m and a final position of 10\text{ m}10 m10, space, m. The displacement of object C can be shown with this equation: \Delta x_C= 10\text{ m}-2\text{ m}=+8\text{ m}Δx C =10 m−2 m=+8 mdelta, x, start subscript, C, end subscript, equals, 10, space, m, minus, 2, space, m, equals, plus, 8, space, m Object D had an initial position of 9\text{ m}9 m9, space, m and a final position of 5\text{ m}5 m5, space, m. The displacement of object D can be shown with this equation: \Delta x_D= 5\text{ m}-9\text{ m}=-4\text{ m}Δx D =5 m−9 m=−4 mdelta, x, start subscript, D, end subscript, equals, 5, space, m, minus, 9, space, m, equals, minus, 4, space, m Example 2: Distance traveled of four moving objects Four objects move according to the paths shown in the diagram below. Assume the units of the horizontal scale are given in meters. (Image credit: altered from Openstax College Physics) What was the total distance traveled by each object? Object A travels a total distance of 7\text{ m}7 m7, space, m. Object B travels a total distance of 5\text{ m}5 m5, space, m. Object C travels a total distance of 8\text{ m}+2\text{ m}+2\text{ m}=12\text{ m}8 m+2 m+2 m=12 m8, space, m, plus, 2, space, m, plus, 2, space, m, equals, 12, space, m. Object D travels a total distance of 6\text{ m}+2\text{ m}=8\text{ m}6 m+2 m=8 m6, space, m, plus, 2, space, m, equals, 8, space, m. [Attributions and References]
I'm in primary and I remember very well when I was little I used to think about this stuff I never knew the names but now you've helped me understand how to explain this to my friends with the proper names. Thank you soo much!😁😁😁
Same things apply to mind. Analyzing an event, you can choose the reference of the cause that you want to start on. If you trow a rock, what’s the cause? Your hand? Your thoughts? Your neurons ? Your will of trying to discover what happens if you trow a rock? The add on television that induced you the feeling of trying to trow a rock? Or the electricity in the television? Or the clouds that allowed clear television signal ? Or your parents that bought the television? See? There are infinite causes and correlations, and if you want to go to the source you will end up answering always with “because the Big Bang” that would not be useful (and who knows if the Big Bang was the real start of all anyway lol) , that’s why we choose reference. That’s why free will is real, because it’s simply a point of reference we choose to allow us to make calculations in our reasonable frame and make decisions. You cannot do that if you take the Big Bang as a point of reference, same, you cannot calculate the car speed if you take your galaxy as reference ;) (well technically you can, but you will need physical laws that are incomplete and doesn’t fit together and doesn’t exist yet (relativity and quantum m.) that’s why relativity is true only if you have a specific point of reference, that cannot be used in quantum mechanics, that has its specific set of rules and assumptions, basically its point of reference) All reality is described assuming something else and the unfolding consequences, are inherently bound to frame of reference
It seems that there is missing one litlle but important fact. Frames of reference = 1) Coordinate system (Cartesian, Polar, Cylindrical, spherical and so on...) + 2) The set of physical reference points (=ground, car and plane [in this video]) that uniquely fix (locate and orient) the coordinate system and standardize measurements. Coordinate systems arn't mentioned. Implicitly/tacitly there is Cartesian coordinate system with only x-axe in the video. Otherwise great video! I always visualize like two or more Coordinate systems move relative to each other. That is how it's in my textbook from physics.
This video was nothing but the explanation of relative velocity in my view... only at the part, they talk about reference frames & that too not much satisfactory. But nevertheless, a good video, liked it!!
What if both the car and plane are moving the same direction. Would the velocity of the plane from the perspective of the car be the same or slightly lower like 200m/s?
5 лет назад
You're right, it would be slightly lower at 200 m/s since the car is moving in the same direction at 50 m/s.
An elevator is moving upward at a speed of 3 meters per second. A passenger in the elevator drops a watch. Find the velocity and acceleration of the watch in a frame of reference attached to (a) the elevator (b) the building
rusty ryan Suppose you are traveling 50 m/s to the right and the plane is traveling 250 m/s, also to the right. Then it appears to you that the plane is traveling away from you at "only" 200 m/s.
All reference frames are valid. But are observations made by an Observer in a moving reference frame also valid when the Observer does not know he is in a moving reference frame. Please explain why we need relative motion rather than motion. Observer in plane would measure car speed at 300 m/s but car is moving at 50m/s. There is an apparent conflict. Observer in plane cannot resolve the conflict since he does not know he is moving and observing relative motion of the car.
To make the dough for the pie crust, mix 2 1/2 cups all-purpose flour and 1 teaspoon each salt and sugar in a medium-size bowl. Cut 2 sticks chilled unsalted butter into pieces. With a pastry blender, cut in butter, working until mixture resembles coarse meal.
05:58 = 3 different ways to calculate a problem and all 3 ways give the same answer, KINDA even though the answers might seem slightly different, they actually aren't, some things you just have to understand them with out an explanation, if you can do that you a Genius . Yes
It's actually a point or in other words a criteria that u use to measure or compare something......for example when u calculate percentage u use 100%as a standard in such case 100 would be the standard similarly when u use reference (inertial) u would consider a point where all inertial laws would hold good....it would remain in it's inertial frame unless it's diatribes/accelerated....hope u got it what I actually wanna say💫🙃
I have a Question.....The space shuttle is flying at 17,500mph and the Earth spinning at 1000mph....What would be the correct frame of reference.............. How can the space shuttle fly faster than Earths rotation?and can anything possibly fly that fast without breaking up,after all its held together with rivets and bolts and probably space tape .......
The satellite is in space, and in space, there is no air, so the plane does not encounter any air or atmospheric resistance,thats why it doesnt break up.
The correct frame of reference for when the rotation of the Earth cannot be neglected is an Earth centered inertial reference frame, which has a fixed orientation (such as the J2000 reference frame) en.wikipedia.org/wiki/Earth-centered_inertial
I am confused and no one will help me. (1) I am told there is only ONE type of inertial frame of reference. (2) meaning if i do a physics experiment in ANY inertial frame i will get the SAME RESULTS no matter what inertial frame i am in (3) I am told earth is an inertial frame. (4) I am told being in outer space at a constant velocity is an inertial frame. OK THESE STATEMENTS CONTRADICT ONE ANOTHER !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Because if that were ALL true then that would mean that i could do physics experiments in outer space (at a constant velocity) and then do the SAME PHYSICS EXPERIMENT on earth and get the SAME RESULTS. But that IS NOT TRUE. THAT IS A LIE. If i am in outer space(at constant velocity) and i hold a ball out and let go of the ball with out throwing it or pushing it in any direction the ball will just float there. But on earth if i do the SAME experiment the ball will fall to the ground. So there are (1) more than one TYPE of inertial frames of reference OR (2) earth is NOT an inertial frame of reference. SO WHICH IS IT !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Why wont any one answer me???????
Well, the one in the middle is wrong. The plane relative to the car moving in the opposite direction should be a subtraction. For example, you are in your car on the highway. Your car is going 50 miles per hour. Another car is passing you going 60 mph. The 60 mph car is going 10 mph relative the 50 mile . You should point the car in the right direction because you have the care pointed in the opposite direction of the air plane, but you draw an arrow in the same direction of airplane.
Car velocity= -50m/s^2 Plane velocity= 250 m/s^2 Relative to the person in car, plane velocity: 250-(-50)=300 meters per second squared Edit: I think it's right...
To make the dough for the pie crust, mix 2 1/2 cups all-purpose flour and 1 teaspoon each salt and sugar in a medium-size bowl. Cut 2 sticks chilled unsalted butter into pieces. With a pastry blender, cut in butter, working until mixture resembles coarse meal.
To make the dough for the pie crust, mix 2 1/2 cups all-purpose flour and 1 teaspoon each salt and sugar in a medium-size bowl. Cut 2 sticks chilled unsalted butter into pieces. With a pastry blender, cut in butter, working until mixture resembles coarse meal.
This video explains when Max Planck said "When you change the way you look at things, the things you look at change"
What does position mean?
In physics, we love to precisely describe the motion of an object. Seriously, the first few chapters of basically every physics textbook are devoted to teaching people how to precisely describe motion since it is so important to everything else we do in physics.
But to describe an object's motion, we have to first be able to describe its position-where it is at any particular time. More precisely, we need to specify its position relative to a convenient reference frame. Earth is often used as a reference frame, and we often describe the position of an object as it relates to stationary objects in that reference frame. For example, a professor’s position could be described in terms of where she is in relation to the nearby white board (Figure 1). In other cases, we use reference frames that are not stationary but rather are in motion relative to Earth. To describe the position of a person in an airplane, for example, we use the airplane, not Earth, as the reference frame (Figure 2).
The variable xxx is often used to represent the horizontal position. The variable yyy is often used to represent the vertical position. [What about z?]
zzzz
xxyyzzzz
What does displacement mean?
If an object moves relative to a reference frame-for example, if a professor moves to the right relative to a whiteboard, or a passenger moves toward the rear of an airplane-then the object’s position changes. This change in position is known as displacement. The word displacement implies that an object has moved, or has been displaced.
Displacement is defined to be the change in position of an object. It can be defined mathematically with the following equation:
\text{Displacement}=\Delta x=x_f-x_0Displacement=Δx=x
f
−x
0
D, i, s, p, l, a, c, e, m, e, n, t, equals, delta, x, equals, x, start subscript, f, end subscript, minus, x, start subscript, 0, end subscript
x_fx
f
x, start subscript, f, end subscript refers to the value of the final position.
x_0x
0
x, start subscript, 0, end subscript refers to the value of the initial position.
\Delta xΔxdelta, x is the symbol used to represent displacement.
[What does the triangle symbol mean?]
\Deltadeltayyy_f
y, start subscript, f, end subscripty_0
y, start subscript, 0, end subscript
\Delta y=y_f-y_0
delta, y, equals, y, start subscript, f, end subscript, minus, y, start subscript, 0, end subscript
y_0-y_f
y, start subscript, 0, end subscript, minus, y, start subscript, f, end subscript-\Delta yminus, delta, y
x_0
x, start subscript, 0, end subscriptx_i
x, start subscript, i, end subscriptx_1
x, start subscript, 1, end subscript
Displacement is a vector. This means it has a direction as well as a magnitude and is represented visually as an arrow that points from the initial position to the final position. For example, consider the professor that walks relative to the whiteboard in Figure 1.
Figure 1: A professor paces left and right while lecturing. The +2.0\text{ m}+2.0 mplus, 2, point, 0, space, m displacement of the professor relative to Earth is represented by an arrow pointing to the right. (Image credit: Openstax College Physics)
The professor’s initial position is x_0=1.5\text{ m}x
0
=1.5 mx, start subscript, 0, end subscript, equals, 1, point, 5, space, m and her final position is x_f=3.5\text{ m}x
f
=3.5 mx, start subscript, f, end subscript, equals, 3, point, 5, space, m. Thus, her displacement can be found as follows, Δx=xf−x0=3.5 m−1.5 m=+2.0 m. In this coordinate system, motion to the right is positive, whereas motion to the left is negative.
Now consider the passenger that walks relative to the plane in Figure 2.
Figure 2: A passenger moves from his seat to the back of the plane. The −4.0 m displacement of the passenger relative to the plane is represented by an arrow toward the rear of the plane. (Image credit: Openstax College Physics)
The airplane passenger’s initial position is x_0=6.0\text{ m}x
0
=6.0 mx, start subscript, 0, end subscript, equals, 6, point, 0, space, m and his final position is x_f=2.0\text{ m}x
f
=2.0 mx, start subscript, f, end subscript, equals, 2, point, 0, space, m, so his displacement can be found as follows, Δx=xf−x0=2.0 m−6.0 m=−4.0 m. His displacement is negative because his motion is toward the rear of the plane, or in the negative x direction in our coordinate system.
In one-dimensional motion, direction can be specified with a plus or minus sign. When you begin a problem, you should select which direction is positive-usually that will be to the right or up, but you are free to select positive as being any direction.
What do distance and distance traveled mean?
We must be careful when using the word distance since there are two ways in which the term distance is used in physics. We can talk about the distance between two points, or we can talk about the distance traveled by an object.
Distance is defined to be the magnitude or size of displacement between two positions. Note that the distance between two positions is not the same as the distance traveled between them.
Distance traveled is the total length of the path traveled between two positions. Distance traveled is not a vector. It has no direction and, thus, no negative sign. For example, the distance the professor walks is 2.0 \text{ m}2.0 m2, point, 0, space, m. The distance the airplane passenger walks is 4.0 \text{ m}4.0 m4, point, 0, space, m.
It is important to note that the distance traveled does not have to equal the magnitude of the displacement (i.e., distance between the two points). Specifically, if an object changes direction in its journey, the total distance traveled will be greater than the magnitude of the displacement between those two points. See the solved examples below.
What's confusing about displacement?
People often forget that the distance traveled can be greater than the magnitude of the displacement. By magnitude, we mean the size of the displacement without regard to its direction (i.e., just a number with a unit). For example, the professor could pace back and forth many times, perhaps walking a distance of 150 meters during a lecture, yet still end up only two meters to the right of her starting point. In this case her displacement would be +2 \text{ m}+2 mplus, 2, space, m, the magnitude of her displacement would be 2 \text{ m}2 m2, space, m, but the distance she traveled would be 150 \text{ m}150 m150, space, m. In kinematics we nearly always deal with displacement and magnitude of displacement and almost never with distance traveled. One way to think about this is to assume you marked the start of the motion and the end of the motion. The displacement is simply the difference in the position of the two marks and is independent of the path taken when traveling between the two marks. The distance traveled, however, is the total length of the path taken between the two marks.
People often forget to include a negative sign, if needed, in their answer for displacement. This sometimes occurs if they accidentally subtract the final position from the initial position rather than subtracting the initial position from the final position.
What do solved examples involving displacement look like?
Example 1: Displacement of four moving objects
Four objects move according to the paths shown in the diagram below. Assume the units of the horizontal scale are given in meters. (Image credit: altered from Openstax College Physics)
What was the displacement of each object?
Object A had an initial position of 0\text{ m}0 m0, space, m and a final position of 7\text{ m}7 m7, space, m. The displacement of object A can be shown with this equation:
\Delta x_A= 7\text{ m}-0\text{ m}=+7\text{ m}Δx
A
=7 m−0 m=+7 mdelta, x, start subscript, A, end subscript, equals, 7, space, m, minus, 0, space, m, equals, plus, 7, space, m
Object B had an initial position of 12\text{ m}12 m12, space, m and a final position of 7\text{ m}7 m7, space, m. The displacement of object B can be shown with this equation:
\Delta x_B= 7\text{ m}-12\text{ m}=-5\text{ m}Δx
B
=7 m−12 m=−5 mdelta, x, start subscript, B, end subscript, equals, 7, space, m, minus, 12, space, m, equals, minus, 5, space, m
Object C had an initial position of 2\text{ m}2 m2, space, m and a final position of 10\text{ m}10 m10, space, m. The displacement of object C can be shown with this equation:
\Delta x_C= 10\text{ m}-2\text{ m}=+8\text{ m}Δx
C
=10 m−2 m=+8 mdelta, x, start subscript, C, end subscript, equals, 10, space, m, minus, 2, space, m, equals, plus, 8, space, m
Object D had an initial position of 9\text{ m}9 m9, space, m and a final position of 5\text{ m}5 m5, space, m. The displacement of object D can be shown with this equation:
\Delta x_D= 5\text{ m}-9\text{ m}=-4\text{ m}Δx
D
=5 m−9 m=−4 mdelta, x, start subscript, D, end subscript, equals, 5, space, m, minus, 9, space, m, equals, minus, 4, space, m
Example 2: Distance traveled of four moving objects
Four objects move according to the paths shown in the diagram below. Assume the units of the horizontal scale are given in meters. (Image credit: altered from Openstax College Physics)
What was the total distance traveled by each object?
Object A travels a total distance of 7\text{ m}7 m7, space, m.
Object B travels a total distance of 5\text{ m}5 m5, space, m.
Object C travels a total distance of 8\text{ m}+2\text{ m}+2\text{ m}=12\text{ m}8 m+2 m+2 m=12 m8, space, m, plus, 2, space, m, plus, 2, space, m, equals, 12, space, m.
Object D travels a total distance of 6\text{ m}+2\text{ m}=8\text{ m}6 m+2 m=8 m6, space, m, plus, 2, space, m, equals, 8, space, m.
[Attributions and References]
Like repentance from an Ancient Greek word (μετάνοια) meaning "changing one's mind".
True in life !!!
Long story, you'd probably get 100%in an English test.
Por favor lo puede explicar en español
I'm in primary and I remember very well when I was little I used to think about this stuff I never knew the names but now you've helped me understand how to explain this to my friends with the proper names. Thank you soo much!😁😁😁
khan's voice makes me smile and feel safe and happy inside! had to get it out sry :-)
Best way to explain Frames of Reference👏
i always take out my physics instruments when i'm driving
me too
Very interesting
Same things apply to mind. Analyzing an event, you can choose the reference of the cause that you want to start on. If you trow a rock, what’s the cause? Your hand? Your thoughts? Your neurons ? Your will of trying to discover what happens if you trow a rock? The add on television that induced you the feeling of trying to trow a rock? Or the electricity in the television? Or the clouds that allowed clear television signal ? Or your parents that bought the television? See? There are infinite causes and correlations, and if you want to go to the source you will end up answering always with “because the Big Bang” that would not be useful (and who knows if the Big Bang was the real start of all anyway lol) , that’s why we choose reference. That’s why free will is real, because it’s simply a point of reference we choose to allow us to make calculations in our reasonable frame and make decisions. You cannot do that if you take the Big Bang as a point of reference, same, you cannot calculate the car speed if you take your galaxy as reference ;) (well technically you can, but you will need physical laws that are incomplete and doesn’t fit together and doesn’t exist yet (relativity and quantum m.) that’s why relativity is true only if you have a specific point of reference, that cannot be used in quantum mechanics, that has its specific set of rules and assumptions, basically its point of reference)
All reality is described assuming something else and the unfolding consequences, are inherently bound to frame of reference
"I don't recommend you doing this while driving, let's say someone else is driving" Safety first
Yeh coz first you need to stay alive inorder to calculate someone's velocity w.r.t your frame of reference XD
I'm learning something that I found out as a kid who always traveled through bus. Didn't thought it was this important. Thank you sal. ❤️
An awesome easy way to explain complex idea like this
Fantastic video. My mind is blown.
This video was amazing.
this helped me alot :) ty.......
How to write on a mouse pointer like this?
He is using a wacom
Sir,your explanation is excellent.Sir, please explain with reference to earth.
OMG thank you so much I didn't get this nut now i do
Can time be taken as frame of reference to describe motion
Yes thank u soooo much, my physics teacher just made such simple thing sound sooo hard, but ur explanation was perfect!!!
I’m Italian and I understood everything even without subtitles
🤌
It is so fun to see how much he cares for human rights by not letting us drive the car or plane lol
He sounds like ranboo
In which playlist is this??
Best frame of reference video luv your work
NICE DRAWING AND EXPLANATION ..................
Sirr..... Non inertial frame pathi sollunga..... Plzzz
I am in class 8 but intreseted to see this and learn this so that I could be like 10% of Einstein😆
Im in 11 and i wish i didn’t have to watch this
@@themanedoe4282 🤣🤣🤣
I'm in my first year in college and I feel the same
I am in 9th I don't know why I am watching this
im in 7th and this is so pointless why do i need to know this... teach me how to pay my bills please
It is very easy to understand
It seems that there is missing one litlle but important fact.
Frames of reference =
1) Coordinate system (Cartesian, Polar, Cylindrical, spherical and so on...)
+
2) The set of physical reference points (=ground, car and plane [in this video]) that uniquely fix (locate and orient) the coordinate system and standardize measurements.
Coordinate systems arn't mentioned. Implicitly/tacitly there is Cartesian coordinate system with only x-axe in the video.
Otherwise great video!
I always visualize like two or more Coordinate systems move relative to each other. That is how it's in my textbook from physics.
This is just an introduction man. We will get into the depth in the successive videos.
Dodo
I enjoy this video.
What about with the same directions?
Im in uni and have had a brainfart moment, this really helped me get back on track!
@@snoochen Go on? By the way, I didn't fail :)
This video was nothing but the explanation of relative velocity in my view... only at the part, they talk about reference frames & that too not much satisfactory. But nevertheless, a good video, liked it!!
Does direction not play an important part in this like you only depicted this using one direction what if the direction is REVERSED?
He specifically only used the left and right example as that's the simplest example.
Thanks I can study this for my CFA tomorrow for 7th grade, thanks again
What is CFA
@@psshamsabadfirst9785 central frequencies apple
@@zombiebrainlover6269 what is this can you explain
well that car have fragmented that stick man with the velocity 50m/s
The Geostationary Satellites, are they in Inertial frame of reference with respect to Earth.
What if both the car and plane are moving the same direction. Would the velocity of the plane from the perspective of the car be the same or slightly lower like 200m/s?
You're right, it would be slightly lower at 200 m/s since the car is moving in the same direction at 50 m/s.
@ OK, thank you so much.👍
I always keep my physics instruments with me
Awesome
Thank you
An elevator is moving upward at a speed of 3 meters per second. A passenger in the elevator drops a watch. Find the velocity and acceleration of the watch in a frame of reference attached to (a) the elevator (b) the building
What's the relative velocity of plane and car if they travel in the same direction.?
rusty ryan Suppose you are traveling 50 m/s to the right and the plane is traveling 250 m/s, also to the right.
Then it appears to you that the plane is traveling away from you at "only" 200 m/s.
What if you are the one on the plane? What would it be to you?
@@GloriaMPerez-cx4ndspeed of car relative to plane is -200 m/s 🤔 if I am right
All reference frames are valid. But are observations made by an Observer in a moving reference frame also valid when the Observer does not know he is in a moving reference frame. Please explain why we need relative motion rather than motion. Observer in plane would measure car speed at 300 m/s but car is moving at 50m/s. There is an apparent conflict. Observer in plane cannot resolve the conflict since he does not know he is moving and observing relative motion of the car.
Thanks
Ayy getting into some awesome stuff now :D
To make the dough for the pie crust, mix 2 1/2 cups all-purpose flour and 1 teaspoon each salt and sugar in a medium-size bowl. Cut 2 sticks chilled unsalted butter into pieces. With a pastry blender, cut in butter, working until mixture resembles coarse meal.
What does all this stuff got to do with the video?
@@iamdwez2031 thank you for this recipe. I skipped my physics test and made this instead.
Time well spent!
thanks
And then you measure the speed of light and find that it's the same in all three frames of reference. That one's a real mind-bender.
lol ifkr
Go in a rocket
And you will get difference
I am being held against my will to watch this, help.
Update: I have been released about 30 l8r.
05:58 = 3 different ways to calculate a problem and all 3 ways give the same answer, KINDA even though the answers might seem slightly different, they actually aren't, some things you just have to understand them with out an explanation, if you can do that you a Genius . Yes
Why must calculate like that?
That's a lot of speed
😍❤
Can someone explain what relative means
it means the value of something depends on the way you observe or the type of the environment of the observer.
(hope this make sense)
good Indian map color
That’s just a coincidence. What’s racist in it?
@@is3nsor 😂😂where are you from
Who is running this platform
I am Learning
True life
👍👍
What is a reference ?
It's actually a point or in other words a criteria that u use to measure or compare something......for example when u calculate percentage u use 100%as a standard in such case 100 would be the standard similarly when u use reference (inertial) u would consider a point where all inertial laws would hold good....it would remain in it's inertial frame unless it's diatribes/accelerated....hope u got it what I actually wanna say💫🙃
@@asharibimran4708 dont know Abt this ,but I got it , seriously I want this ans and finally u solve my problem, thanks a lot
❤🎉😊
I wanted to see the music vid😭
I have a Question.....The space shuttle is flying at 17,500mph and the Earth spinning at 1000mph....What would be the correct frame of reference..............
How can the space shuttle fly faster than Earths rotation?and can anything possibly fly that fast without breaking up,after all its held together with rivets and bolts and probably space tape .......
The satellite is in space, and in space, there is no air, so the plane does not encounter any air or atmospheric resistance,thats why it doesnt break up.
The correct frame of reference for when the rotation of the Earth cannot be neglected is an Earth centered inertial reference frame, which has a fixed orientation (such as the J2000 reference frame) en.wikipedia.org/wiki/Earth-centered_inertial
I am confused and no one will help me. (1) I am told there is only ONE type of inertial frame of reference. (2) meaning if i do a physics experiment in ANY inertial frame i will get the SAME RESULTS no matter what inertial frame i am in (3) I am told earth is an inertial frame. (4) I am told being in outer space at a constant velocity is an inertial frame. OK THESE STATEMENTS CONTRADICT ONE ANOTHER !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Because if that were ALL true then that would mean that i could do physics experiments in outer space (at a constant velocity) and then do the SAME PHYSICS EXPERIMENT on earth and get the SAME RESULTS. But that IS NOT TRUE. THAT IS A LIE. If i am in outer space(at constant velocity) and i hold a ball out and let go of the ball with out throwing it or pushing it in any direction the ball will just float there. But on earth if i do the SAME experiment the ball will fall to the ground. So there are (1) more than one TYPE of inertial frames of reference OR (2) earth is NOT an inertial frame of reference. SO WHICH IS IT !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Why wont any one answer me???????
Earth is not exactly inertial frame of reference but it can be approximated to one
In case no one knew, the car was going at a speed of 180 kmph (Around 112 mph). That's hella fast for roads...
That's why B is correct
two cars driving 70KM/h crash head-on at 140KM/h
Well, the one in the middle is wrong. The plane relative to the car moving in the opposite direction should be a subtraction. For example, you are in your car on the highway. Your car is going 50 miles per hour. Another car is passing you going 60 mph. The 60 mph car is going 10 mph relative the 50 mile . You should point the car in the right direction because you have the care pointed in the opposite direction of the air plane, but you draw an arrow in the same direction of airplane.
Car velocity= -50m/s^2
Plane velocity= 250 m/s^2
Relative to the person in car, plane velocity:
250-(-50)=300 meters per second squared
Edit: I think it's right...
at least he can spell car right
@@glennakidd4382 *At
I don't see anything from the plane except for the clouds.
Frs more like fps
unable to understand ...explain in pbi or hindi
Learn English, this isn't that hard.
@@abandoned7501 why??
ik
To make the dough for the pie crust, mix 2 1/2 cups all-purpose flour and 1 teaspoon each salt and sugar in a medium-size bowl. Cut 2 sticks chilled unsalted butter into pieces. With a pastry blender, cut in butter, working until mixture resembles coarse meal.
To make the dough for the pie crust, mix 2 1/2 cups all-purpose flour and 1 teaspoon each salt and sugar in a medium-size bowl. Cut 2 sticks chilled unsalted butter into pieces. With a pastry blender, cut in butter, working until mixture resembles coarse meal.
Y is everyone giving procedures in cooking?
Urdu/Hindi channel here....
watermelon
lol
could not think of a better comment xD
Why don't you just say: reference frame means point of view?
@Kevin C Well, to me, I start imagining wooden picture frames.
You sound like ranboo
Unclear