Reverse Strings in JAVA | (simple & easy)

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  • Опубликовано: 11 сен 2024
  • Reverse Strings in JAVA | (simple & easy)
    In today's video, I will be showing you how to reverse a string in Java!
    ► Software Used:
    ● IntelliJ IDEA: www.jetbrains....
    ► Helpful Learning Sites:
    ● Codecademy: www.codecademy...
    ● freeCodeCamp: www.freecodeca...
    ► Song Used:
    ● One More Time: • [FREE] Lofi Type Beat ...
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    ● GitHub: github.com/Min...

Комментарии • 68

  • @Spider-Man_67
    @Spider-Man_67 Год назад +9

    Very simple & sweet code, thank man!

  • @ajeetkumarsingh1302
    @ajeetkumarsingh1302 5 месяцев назад +3

    great video man probably shortest programming video i have watched on youtube. i am new to coding how do i excel in this

    • @mintype
      @mintype  Месяц назад

      just keep coding :) if u dont know what to code go learn something new and maybe some cool ideas will pop into ur head!

  • @armenia18yt3
    @armenia18yt3 2 месяца назад +1

    short and simple, thank you

    • @mintype
      @mintype  2 месяца назад

      You're welcome!

  • @mintype
    @mintype  Год назад +3

    If anyone has any other things related to CS or JAVA they want a video on, just reply here!
    Join the discord! -> discord.gg/hhGu6mV5wm

  • @bankarsandipk
    @bankarsandipk Год назад +3

    Nice short explanation 😊

    • @mintype
      @mintype  Год назад

      Glad it was helpful!

  • @ShathyMasud
    @ShathyMasud 5 дней назад

    Nice work ❤

  • @kevswags
    @kevswags 11 месяцев назад +3

    I think i found an easier way:
    String s = "123456789";
    StringBuilder x = new StringBuilder(s);
    x.reverse();
    String output = x.toString();
    System.out.println(output);

    • @mintype
      @mintype  11 месяцев назад +5

      Your way works and is more simple than my way, however this video is supposed to teach those who don’t know how to reverse a sting WITHOUT StringBuilder. (For example in a AP CSA class they would ask you to do this without StringBuilder)

    • @DecartesGreatStar
      @DecartesGreatStar 5 месяцев назад

      interviews tend to not allow things like StringBuilder, while yes it is more efficient, they want to see if you know the fundamental logic

  • @raykhonayorieva7156
    @raykhonayorieva7156 Год назад +1

    great very simple and very understandable thank you thank you

    • @mintype
      @mintype  Год назад

      Glad it was helpful!

  • @Idealbruda
    @Idealbruda 16 дней назад +1

    Dude can u explain why decremented the str.length by 1

    • @mintype
      @mintype  16 дней назад +1

      Using str.length gives you the length of a string but since getting a char from a string starts at 0 not 1, we need to go back one to get the last letter. For example if we had the string “Hello”, and we got the length it would be 5 but if we got the 5th letter AND start counting from 0 not 1 then we we would have an issue because we would go 0, 1, 2, 3, 4, 5 and if you look closely I just listed 6 numbers. So really using the length you are getting the 6th letter here of a 5 letter word. That’s why we subtract one.

    • @Idealbruda
      @Idealbruda 14 дней назад

      @@mintype thx understood

  • @renukasp3510
    @renukasp3510 Год назад +1

    Simple and easy 👏

    • @mintype
      @mintype  Год назад

      Thanks a lot 😊

  • @User-1234-r1z
    @User-1234-r1z Месяц назад +1

    0:24 greater than or equal to

    • @mintype
      @mintype  Месяц назад

      oh yea thanks

  • @xebex5451
    @xebex5451 6 месяцев назад

    thanks man!!

  • @urboigot45iron4
    @urboigot45iron4 Год назад +2

    nice

  • @code-Known
    @code-Known 3 месяца назад +1

    type mismatch bro

  • @baseplate_462
    @baseplate_462 7 месяцев назад

    im not exactly sure i understand why we do .length - 1; what is the -1 for?

    • @almira4008
      @almira4008 6 месяцев назад

      -1 means the index of last character, because index starts from zero, so when you want to get last characters' index you should add this -1

    • @DecartesGreatStar
      @DecartesGreatStar 5 месяцев назад +1

      array {1, 2, 3, 4, 5}
      There's 5 elements inside, it has a length of 5.
      However, if we want to know the index of each element inside the array the value '1' is at position '0' which means element '5' is at position '4', so to get the value '5' we need to write array[4]. given N is the length of the array, n-1 determins the position of those elements.
      If simple wrote i = str.length; you would get an out of bounds exception element because the element '5' is at position '4', not position '5'. Following the formular n-1, we say str.-length-1 to ensure we always end up at the last element contained within the array.

    • @ravalimanchala8170
      @ravalimanchala8170 4 месяца назад

      Thank you for your valuable information

    • @frailedtea
      @frailedtea 3 месяца назад

      @@DecartesGreatStar You're amazing!

  • @chrism2828
    @chrism2828 11 месяцев назад +1

    I keep getting an exception out of bounds error and I’m not sure why.

    • @mintype
      @mintype  11 месяцев назад

      send ur code here

  • @JSR2428
    @JSR2428 4 месяца назад

    Why you use that + sign with result?

    • @mintype
      @mintype  Месяц назад

      the plus makes it so the thing after gets ADDED to the string. so the string starts off with nothing in it and each time it goes through the for loop, one letter from the str string is added to result. (it goes backwards so its reversed.)

  • @pradipacharya3168
    @pradipacharya3168 Год назад +3

    how do u reverse the string itself

    • @mintype
      @mintype  Год назад +2

      you can set the original string variable's value to the result string variable's value like so:
      str = result;

    • @pradipacharya3168
      @pradipacharya3168 Год назад

      @@mintype what if you wanted to change the string itself inside the loop rather than creating a empty string to store the reversed version on. (thxs for the reply btw, i'm new so that helped)

    • @mintype
      @mintype  Год назад +2

      @@pradipacharya3168 I've done some research and if you wanted to change the string itself inside the loop rather than create an empty string to store the reversed version to, that wouldn't really work. However, this video is to show people how to reverse strings using a for loop, like how they may expect a student to in a computer science class. If you really wanted to reverse a string in less lines of code etc., you could do the following:
      String originalString = "Hello, world!";
      StringBuilder reversedString = new StringBuilder(originalString).reverse();
      System.out.println(reversedString); // prints "!dlrow ,olleH"

    • @pradipacharya3168
      @pradipacharya3168 Год назад

      @@mintype thank you man, that helped a lot!

    • @mintype
      @mintype  Год назад

      glad it helped!

  • @oshadhaedirisinghe1455
    @oshadhaedirisinghe1455 6 месяцев назад

    Thank you

  • @47lokeshkumar74
    @47lokeshkumar74 Год назад +1

    Nice

  • @alejandroquinonescaicedo8
    @alejandroquinonescaicedo8 Год назад +1

    StringBuilder

    • @mintype
      @mintype  Год назад

      StringBuilder is another way you could do this. However, I am teaching how to do this manually, because in schools, teachers don't want you to take shortcuts.

  • @irisrin
    @irisrin 11 месяцев назад

    my results came out diffrent

    • @mintype
      @mintype  11 месяцев назад

      Can you provide some info? Like give me your code so I can see whats wrong. Also maybe tell me your version of Java? New Java versions come out all the time and can break old code.
      discord help server: discord.gg/hhGu6mV5wm

  • @Idealbruda
    @Idealbruda 16 дней назад

    WRONG CODE

    • @mintype
      @mintype  16 дней назад

      ??? What went wrong?

    • @Idealbruda
      @Idealbruda 14 дней назад

      @@mintype o
      ol
      oll
      olle
      olleh
      this is the actual output what i got

    • @mintype
      @mintype  9 дней назад

      Isn’t that hello backwards though? “olleh”

  • @nahidasultana6842
    @nahidasultana6842 Год назад

    Hi, I am having an error. what mistake i have made?
    package Practice;
    public class HelloReverse {
    public static void main(String[] args) {

    String input ="Hello world!";
    String output=" ";
    for(int i=input.length()-1;i>=0;i--);
    output+=input.charAt(i);
    System.out.println(output);

    • @mintype
      @mintype  11 месяцев назад

      You have a ; (semicolon) at the end of your for loop!!!!
      updated code:
      String input ="Hello world!";
      String output=" ";
      for(int i=input.length()-1;i>=0;i--) output+=input.charAt(i);
      System.out.println(output);

    • @nahidasultana6842
      @nahidasultana6842 11 месяцев назад

      @@mintype Thank you so much!

    • @ravalimanchala8170
      @ravalimanchala8170 3 месяца назад

      Thank you

    • @ravalimanchala8170
      @ravalimanchala8170 3 месяца назад

      Thank you

    • @ravalimanchala8170
      @ravalimanchala8170 3 месяца назад

      Thank you

  • @bhaveerathod2373
    @bhaveerathod2373 Год назад +1

    nice